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A 150Ω resistor is connected in series with a 0.250H inductor and an ac source. The voltage across the resistor is vR = (3.80 V) cos [(720 rad/s) t]. (a) Derive an expression for the circuit current. (b) Determine the inductive reactance of the inductor. (c) Derive an expression for the voltage vL across the inductor.

Short Answer

Expert verified

a) The expression of circuit current is given byI=(0.025A)cos[(720rad/s)t]

b) The inductive reactance of the inductor is 180 Ω

c) The expression of voltage across inductor isvL=-(4.56V)sin[(720rad/s)t]

Step by step solution

01

Concept

An inductor is a passive two-terminal device that stores energy in a magnetic field when current passes through it. When an inductor is attached to an AC supply, the resistance produced by it is called inductive reactance (XL).

Resistance is measure of opposition to the flow of current in a closed electrical circuit. It is measured in Ohm (Ω).

02

Given values

Series Resistance, R = 150 Ω

The inductance of the coil, L = 0.250 H

03

Expression for circuit current

Equation of voltage across resistor is

vR=(3.80V)cos[(720rad/s)t]

By using ohm’s law

l=vRR=3.80V150Ωcos720rad/st=0.025Acos720rad/st

Therefore, the expression of circuit current is given byI=(0.025A)cos[(720rad/s)t]

04

Determination of Inductive reactance

Inductive reactance is given by,

XL=ӬL=720rad/s0.250H=180Ω

Therefore, the inductive reactance of the inductor is 180 Ω.

05

Expression of voltage across inductor

Voltage across inductor leads the current by a phase different of – 90 degrees, so the expression of voltage can be given as –

vL=vLcosӬt+90°=IXLcosӬt+90°=0.025A180Ωcos720rad/st+90°=-4.56Vsin720rad/st

Therefore, the expression of voltage across inductor isvL=-(4.56V)sin[(720rad/s)t]

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