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Chapter 4: Q12DQ (page 1072)

A light source radiates a sinusoidal electromagnetic wave uniformly in all directions. This wave exerts an average pressure p on a perfectly reflecting surface a distance R away from it. What average pressure (in terms of p) would this wave exert on a perfectly absorbing surface that was twice as far from the source?

Short Answer

Expert verified

The average pressure exerted on the surface twice as far from the source of light will be p/4.

Step by step solution

01

Formula of radiation pressure of light

The radiation pressure of light is given by P=I/cwhere I is wave鈥檚 irradiance and c is speed of light.

02

Deriving logical conclusion.

Doubling the distance reduces the intensity by 1/4 factor , therefore the radiation pressure will be

p/4.

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