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Helium gas is in a cylinder that has rigid walls. If the pressure of the gas is 2.00 atm, then the root-mean-square speed of the helium atoms is \(\upsilon {_r}{_m}{_s}\) = 176 m/s. By how much (in atmospheres) must the pressure be increased to increase the \(\upsilon {_r}{_m}{_s}\) of the He atoms by 100 m/s? Ignore any change in the volume of the cylinder.

Short Answer

Expert verified
The pressure must be increased by approximately 2.92 atm.

Step by step solution

01

Identify the given data

We are given the initial pressure of helium gas, \(P_1 = 2.00\) atm, and its initial root-mean-square speed, \(v_{rms1} = 176\) m/s. We need to find the increase in pressure such that \(v_{rms2} = v_{rms1} + 100 = 276\) m/s.
02

Understand the relationship between pressure and RMS speed

The root-mean-square speed \(v_{rms}\) of gas atoms is related to its temperature \(T\) by the equation \(v_{rms} = \sqrt{\frac{3kT}{m}}\), where \(k\) is the Boltzmann constant and \(m\) is the mass of the gas particles. However, considering the ideal gas law \(PV=nRT\), and since the volume \(V\) is constant in this problem, the pressure \(P\) is directly proportional to \(T\). Thus, \(v_{rms} \propto \sqrt{P}\).
03

Apply proportion relation

Using the relation \(v_{rms} \propto \sqrt{P}\), we can write: \(\frac{v_{rms2}}{v_{rms1}} = \sqrt{\frac{P_2}{P_1}}\). Substitute the known values: \(\frac{276}{176} = \sqrt{\frac{P_2}{2}}\).
04

Solve for \(P_2\)

Square both sides to remove the square root:\[\left(\frac{276}{176}\right)^2 = \frac{P_2}{2}\]Calculate \((\frac{276}{176})^2 = 2.46025\), thus:\[P_2 = 2 \times 2.46025 = 4.9205\] atm.
05

Determine the increase in pressure

The increase in pressure is given by \(\Delta P = P_2 - P_1\). Calculate:\[\Delta P = 4.9205 - 2.00 = 2.9205\] atm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental principle used to understand the behavior of gases. It is expressed as \( PV = nRT \), where:
  • \(P\) is the pressure of the gas
  • \(V\) is the volume of the gas
  • \(n\) is the number of moles
  • \(R\) is the ideal gas constant
  • \(T\) is the temperature in Kelvin
When dealing with problems involving gases, this equation helps relate these variables to each other.
In the exercise with helium gas, the volume \(V\) remains constant, simplifying the relationship between pressure and temperature.
This concept tells us that if the number of moles and the volume do not change, any increase in pressure is directly associated with an increase in temperature. This principle helps in calculating how the root-mean-square speed changes with pressure.
Pressure-Temperature Relationship
The connection between pressure and temperature in gases is crucial to understanding gas behavior. According to the ideal gas law, with constant volume and number of moles, the pressure of a gas is directly proportional to its temperature. If we double the temperature, the pressure also doubles, provided mass and volume remain unchanged.
In the context of the problem, increasing the root-mean-square speed of helium molecules requires raising the temperature, which in turn requires increasing the pressure due to their proportional relationship.
This understanding allows us to predict changes in gas behavior and calculate precise requirements, such as how much the pressure needs to be increased for a specific increase in the root-mean-square speed.
Helium Gas Properties
Helium is a noble gas with some unique properties that influence how it behaves as a gas. It is an inert, colorless, and odorless gas that is less dense than the air we breathe.
Here are some important properties of helium gas:
  • Low atomic mass: Helium atoms have lower mass compared to many other gases, allowing them to move more quickly, as seen in their relatively high root-mean-square speeds.
  • Non-reactive: Being a noble gas, helium does not easily form compounds with other elements, making it stable under various conditions.
  • Low density and high internal energy: Its low density contributes to unique behavior in terms of buoyancy and thermal properties.
These attributes are critical when considering helium in applications where pressure, volume, and temperature are important, such as in this problem where the speed of its atoms relate directly to its pressure and temperature due to its distinct physical characteristics.

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Most popular questions from this chapter

Perfectly rigid containers each hold \(n\) moles of ideal gas, one being hydrogen (H\(_2\)) and the other being neon (Ne). If it takes 300 J of heat to increase the temperature of the hydrogen by 2.50\(^\circ\)C, by how many degrees will the same amount of heat raise the temperature of the neon?

You have several identical balloons. You experimentally determine that a balloon will break if its volume exceeds 0.900 L. The pressure of the gas inside the balloon equals air pressure (1.00 atm). (a) If the air inside the balloon is at a constant 22.0\(^\circ\)C and behaves as an ideal gas, what mass of air can you blow into one of the balloons before it bursts? (b) Repeat part (a) if the gas is helium rather than air.

You have two identical containers, one containing gas \(A\) and the other gas \(B\). The masses of these molecules are \(m$$_A\) = 3.34 \(\times\) 10\({^-}{^2}{^7}\) kg and \(m$$_B\) = 5.34 \(\times\) 10\({^-}{^2}{^6}\) kg. Both gases are under the same pressure and are at 10.0\(^\circ\)C. (a) Which molecules (\(A\) or \(B\)) have greater translational kinetic energy per molecule and rms speeds? (b) Now you want to raise the temperature of only one of these containers so that both gases will have the same rms speed. For which gas should you raise the temperature? (c) At what temperature will you accomplish your goal? (d) Once you have accomplished your goal, which molecules (\(A\) or \(B\)) now have greater average translational kinetic energy per molecule?

A welder using a tank of volume 0.0750 m\(^3\) fills it with oxygen (molar mass 32.0 g/mol) at a gauge pressure of 3.00 \(\times\) 10\({^5}\) Pa and temperature of 37.0\(^\circ\)C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 22.0\(^\circ\)C, the gauge pressure of the oxygen in the tank is 1.80 \(\times\) 10\({^5}\) Pa. Find (a) the initial mass of oxygen and (b) the mass of oxygen that has leaked out.

A 20.0-L tank contains \(4.86 \times 10{^-}{^4}\) kg of helium at 18.0\(^\circ\)C. The molar mass of helium is 4.00 g/mol. (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?

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