/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 A sealed box contains a monatomi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A sealed box contains a monatomic ideal gas. The number of gas atoms per unit volume is 5.00 \(\times\) 10\({^2}{^0}\) atoms/cm\(^3\), and the average translational kinetic energy of each atom is 1.80 \(\times\) 10\({^-}{^2}{^3}\) \(J\). (a) What is the gas pressure? (b) If the gas is neon (molar mass 20.18 g/mol), what is \(\upsilon {_r}{_m}{_s}\) for the gas atoms?

Short Answer

Expert verified
(a) Pressure is \(1.6 \times 10^4\) Pa. (b) \(\upsilon_{rms} = 308\) m/s for neon atoms.

Step by step solution

01

- Understand the Exercise Setup

We need to determine two key parameters: (a) the gas pressure in the box using the given atomic properties and (b) the root mean square speed (\( \upsilon_{rms} \)) of the gas atoms. We are given the number of atoms per unit volume and the average translational kinetic energy for the atoms.
02

- Calculate Gas Pressure

For a monatomic ideal gas, the average translational kinetic energy is given by \( \frac{3}{2} kT \), where \( k \) is the Boltzmann constant \( \approx 1.38 \times 10^{-23} \text{ J/K} \). The pressure \( P \) can be found using the equation \( P = n k T \), where \( n \) is the number of atoms per unit volume. Rearrange the equation for \( T \) from kinetic energy, and plug into \( P = n k T \):\[ T = \frac{2 \times 1.8 \times 10^{-23} }{3 \times 1.38 \times 10^{-23} } \approx 2.32 \text{ K} \]\[ P = (5.00 \times 10^{20}) \times (1.38 \times 10^{-23}) \times 2.32 \approx 1.6 \times 10^4 \text{ Pa} \]
03

- Calculate Root Mean Square Speed \( \upsilon_{rms} \)

The root mean square speed \( \upsilon_{rms} \) can be calculated using:\[ \upsilon_{rms} = \sqrt{\dfrac{3kT}{m}} \]where \( m \) is the mass of one atom. First, convert the molar mass of neon from grams per mole to kilograms. Since the number of atoms in a mole is Avogadro's number \( N_A \approx 6.022 \times 10^{23} \), we find the mass of one atom:\[ m = \frac{20.18}{6.022 \times 10^{23}} \times 10^{-3} \approx 3.35 \times 10^{-26} \text{ kg}\]Substitute into the \( \upsilon_{rms} \) formula:\[ \upsilon_{rms} = \sqrt{\dfrac{3 \times 1.38 \times 10^{-23} \times 2.32}{3.35 \times 10^{-26}}} \approx 308 \text{ m/s} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental principle in chemistry and physics used to describe the behavior of gases. It is expressed by the equation \( PV = nRT \), where:
  • \( P \) represents the pressure of the gas.
  • \( V \) is the volume occupied by the gas.
  • \( n \) is the number of moles of gas.
  • \( R \) is the universal gas constant \( (8.314 \text{ J/mol.K}) \).
  • \( T \) is the temperature in Kelvin.
This law helps us relate the pressure, volume, and temperature of an ideal gas. An ideal gas is a theoretical gas that perfectly follows these conditions without interactions between particles.

In the context of our exercise, we are tasked with finding the gas pressure in a sealed box. The problem provides information about the average kinetic energy of the gas, from which we calculate the temperature. Using the equation \( P = n k T \), where \( n \) is the number of atoms per unit volume and \( k \) is the Boltzmann constant, allows us to estimate the pressure efficiently without directly using the total volume.
Root Mean Square Speed
The root mean square speed \( \upsilon_{rms} \) is a measure of the average speed of particles in a gas. Mathematically, it is expressed as:
  • \( \upsilon_{rms} = \sqrt{\dfrac{3kT}{m}} \)
Here, \( k \) is the Boltzmann constant, \( T \) is the temperature of the gas in Kelvin, and \( m \) is the mass of a single gas atom.

Finding \( \upsilon_{rms} \) involves converting the molar mass of neon to an individual atom's mass. This is done by dividing the molar mass by Avogadro's number, giving us a per-atom mass in kilograms.

In our problem, the temperature was determined in a previous step using the average kinetic energy of gas particles. Once you have both the temperature and atomic mass, you can substitute these values into the \( \upsilon_{rms} \) formula to find the average speed of gas atoms. This concept is crucial because it ties together kinetic energy, temperature, and the velocity of particles.
Average Kinetic Energy
The average kinetic energy of gas particles is central to understanding molecular motion in gases. Defined by the formula:
  • \( KE_{avg} = \frac{3}{2} kT \)
This expression shows the direct proportionality between temperature \( T \) and kinetic energy, tied together by the Boltzmann constant \( k \).

The key takeaway is that as the temperature increases, the average kinetic energy of gas molecules also rises. For example, the given kinetic energy in the problem helps us back-calculate the temperature of the gas, which is then used to find both pressure and the root mean square speed.

Understanding this relationship enables predictions about other properties of gases such as their speed and pressure changes concerning temperature fluctuations. When linked with the Ideal Gas Law, it helps in conducting a more detailed analysis of gas behaviors in various conditions.
Boltzmann Constant
The Boltzmann Constant \( k \) acts as a bridge between macroscopic and microscopic physics. Its value, \( 1.38 \times 10^{-23} \text{ J/K} \), precisely relates the average kinetic energy of particles in a gas with the temperature.
  • \( k = \dfrac{R}{N_A} \)
Here, \( R \) is the universal gas constant and \( N_A \) is Avogadro's number. This arises because while \( R \) is used for one mole of gas, \( k \) is applicable on a per-particle basis.

In solving the exercise, the Boltzmann constant played an essential role in both calculating the temperature from kinetic energy and determining the root mean square speed. By quantifying how much energy each degree of freedom contributes, the Boltzmann constant gives profound insights into thermodynamics and statistical mechanics.

This constant is crucial when analyzing the thermodynamic properties of gases, as seen in our problem. It provides the quantitative link needed to navigate between the microscopic world of particle behavior and the macroscopic concepts of temperature and pressure.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A person at rest inhales 0.50 L of air with each breath at a pressure of 1.00 atm and a temperature of 20.0\(^\circ\)C. The inhaled air is 21.0% oxygen. (a) How many oxygen molecules does this person inhale with each breath? (b) Suppose this person is now resting at an elevation of 2000 m but the temperature is still 20.0\(^\circ\)C. Assuming that the oxygen percentage and volume per inhalation are the same as stated above, how many oxygen molecules does this person now inhale with each breath? (c) Given that the body still requires the same number of oxygen molecules per second as at sea level to maintain its functions, explain why some people report 'shortness of breath' at high elevations.

An empty cylindrical canister 1.50 m long and 90.0 cm in diameter is to be filled with pure oxygen at 22.0\(^\circ\)C to store in a space station. To hold as much gas as possible, the absolute pressure of the oxygen will be 21.0 atm. The molar mass of oxygen is 32.0 g/mol. (a) How many moles of oxygen does this canister hold? (b) For someone lifting this canister, by how many kilograms does this gas increase the mass to be lifted?

For diatomic carbon dioxide gas (CO\(_2\), molar mass 44.0 g/mol) at \(T\) = 300 K, calculate (a) the most probable speed \(\upsilon{_m}{_p}\); (b) the average speed \(\upsilon {_a}{_v}\); (c) the root-mean-square speed \(\upsilon {_r}{_m}{_s}\).

(a) A deuteron, 21 \(H\), is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a nuclear fusion reactor must be heated to about 300 million \(K\). What is the rms speed of the deuterons? Is this a significant fraction of the speed of light in vacuum (c = 3.0 \(\times\) 10\(^8\) m/s)? (b) What would the temperature of the plasma be if the deuterons had an rms speed equal to 0.10\(c\)?

If deep-sea divers rise to the surface too quickly, nitrogen bubbles in their blood can expand and prove fatal. This phenomenon is known as the \(bends\). If a scuba diver rises quickly from a depth of 25 m in Lake Michigan (which is fresh water), what will be the volume at the surface of an N\(_2\) bubble that occupied 1.0 mm\(^3\) in his blood at the lower depth? Does it seem that this difference is large enough to be a problem? (Assume that the pressure difference is due to only the changing water pressure, not to any temperature difference. This assumption is reasonable, since we are warm-blooded creatures.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.