/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Perfectly rigid containers each ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Perfectly rigid containers each hold \(n\) moles of ideal gas, one being hydrogen (H\(_2\)) and the other being neon (Ne). If it takes 300 J of heat to increase the temperature of the hydrogen by 2.50\(^\circ\)C, by how many degrees will the same amount of heat raise the temperature of the neon?

Short Answer

Expert verified
The temperature of neon will increase by 4.17°C.

Step by step solution

01

Understand the Problem

We have two containers with equal amounts of different ideal gases: hydrogen (H\(_2\)) and neon (Ne). When 300 J of heat increases the temperature of the hydrogen by 2.50°C, we need to determine how many degrees the same amount of heat will raise the temperature of neon.
02

Recall the Heat Capacity Formula for Ideal Gases

The amount of heat \( Q \) required to change the temperature \( \Delta T \) of a gas is given by the formula \( Q = nC_v\Delta T \), where \( n \) is the number of moles, \( C_v \) is the molar heat capacity at constant volume, and \( \Delta T \) is the change in temperature.
03

Determine the Molar Heat Capacities

For a diatomic gas, like hydrogen (H\(_2\)), the molar heat capacity at constant volume \( C_{v,H_2} \) is approximately \( \frac{5}{2}R \), where \( R \) is the ideal gas constant (8.314 J/mol·K). For a monatomic gas like neon (Ne), the molar heat capacity \( C_{v,Ne} \) is approximately \( \frac{3}{2}R \).
04

Calculate the Heat Capacity for Hydrogen

Using the formula \( Q = nC_v\Delta T \), for hydrogen we have: \[ 300 = n \times \frac{5}{2}R \times 2.50. \]Solve for \( n \frac{5}{2}R \).
05

Solve for \( n \frac{5}{2}R \)

From the equation: \[ 300 = n \times \frac{5}{2}R \times 2.50, \]we get:\[ n \frac{5}{2}R = \frac{300}{2.50} = 120, \]which means per degree change, \( n \frac{5}{2}R \) is 120 J/°C.
06

Rearrange for Neon's Temperature Change

Using the same heat amount for neon, \( Q = n \frac{3}{2}R \times \Delta T \), set \( Q = 300 \) and solve for \( \Delta T \):\[ 300 = n \frac{3}{2}R \times \Delta T. \]
07

Solve for Neon’s Temperature Change

We know from hydrogen's calculation \( n \frac{5}{2}R = 120 \). We can use \( n \frac{3}{2}R \) by setting \( \frac{3}{5} \times 120 = 72 \). Substituting back we get:\[ 300 = 72 \times \Delta T, \]yielding \[ \Delta T = \frac{300}{72} = 4.17 \text{°C}. \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Capacity
Heat capacity is a key concept in understanding how substances change temperature in response to heat applied. It is defined as the amount of heat required to change the temperature of an object or substance by a given amount, usually expressed in units of joules per degree Celsius (J/°C).
For ideal gases, the heat capacity can be considered under constant volume (denoted as \(C_v\)) or constant pressure (denoted as \(C_p\)). Generally, the heat capacity at constant volume is less than that at constant pressure because, at constant volume, no work is done by the gas to expand.
Understanding heat capacity is essential because it allows us to determine how substances react to the heat applied, which is especially useful in thermodynamics and chemical engineering applications. Moreover, it often explains why different materials require different amounts of energy to achieve the same temperature increase.
Molar Heat Capacity
Molar heat capacity specifically refers to the amount of heat needed to raise the temperature of one mole of a substance by one degree Celsius. This measure is particularly useful when dealing with gases or any substance in its molar form.
For ideal gases, the molar heat capacity at constant volume \(C_v\) differs between monatomic and diatomic gases. For example: - **Diatomic Gases**: Like hydrogen \(\text{H}_2\), have a molar heat capacity \(C_v= \frac{5}{2} R\) (where \(R\) is the gas constant, approximately 8.314 J/mol·K). - **Monatomic Gases**: Like neon \(\text{Ne}\), have a molar heat capacity \(C_v= \frac{3}{2} R\).
These differences are due to the degrees of freedom available within the molecules; diatomic gases can store energy in translational and rotational motion, whereas monatomic gases primarily store energy translationally. This concept not only aids in solving problems involving temperature changes in gases but also in understanding energy storage in different molecular structures.
Temperature Change
Temperature change (\(\Delta T\)) occurs when a substance absorbs or emits a certain amount of heat. The amount of temperature change depends on several factors, including the substance's heat capacity and the amount of heat applied.
The formula \(Q = nC_v\Delta T\) acts as the guideline to calculate the change in temperature, where: - \(Q\) is the heat energy added or removed. - \(n\) is the number of moles of the substance. - \(C_v\) is the molar heat capacity under constant volume. - \(\Delta T\) is the temperature change.
In our case with hydrogen and neon, when the same amount of heat is applied, the temperature will change differently due to each gas's molar heat capacity. The key lies in understanding that different substances with various molecular structures will react uniquely to the same energy input, even with identical quantities.
Heat Transfer
Heat transfer is the process of thermal energy moving from one object or substance to another. This can occur through conduction, convection, or radiation, but in the context of ideal gases within containers, it's primarily tackled through conduction.
When understanding how substances like ideal gases respond to heat, it helps to consider how energy is transferred at the molecular level. For example, when 300 J of heat is added to hydrogen gas, molecules gain energy and temperature rises because of this energy intake. The energy supplied does not change between substances, but the resulting temperature changes can differ due to each substance's unique properties.
This concept underscores the importance of knowing the specific heat capacities of substances being observed, as different systems have different efficiencies and thermal responses, crucial for applications across chemistry and physics fields.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A diver observes a bubble of air rising from the bottom of a lake (where the absolute pressure is 3.50 atm) to the surface (where the pressure is 1.00 atm). The temperature at the bottom is 4.0\(^\circ\)C, and the temperature at the surface is 23.0\(^\circ\)C. (a) What is the ratio of the volume of the bubble as it reaches the surface to its volume at the bottom? (b) Would it be safe for the diver to hold his breath while ascending from the bottom of the lake to the surface? Why or why not?

You have several identical balloons. You experimentally determine that a balloon will break if its volume exceeds 0.900 L. The pressure of the gas inside the balloon equals air pressure (1.00 atm). (a) If the air inside the balloon is at a constant 22.0\(^\circ\)C and behaves as an ideal gas, what mass of air can you blow into one of the balloons before it bursts? (b) Repeat part (a) if the gas is helium rather than air.

A large tank of water has a hose connected to it (Fig. P18.59). The tank is sealed at the top and has compressed air between the water surface and the top. When the water height \(h\) has the value 3.50 m, the absolute pressure \(p\) of the compressed air is 4.20 \(\times\) 10\(^5\) Pa. Assume that the air above the water expands at constant temperature, and take the atmospheric pressure to be 1.00 \(\times\) 10\(^5\) Pa. (a) What is the speed with which water flows out of the hose when \(h\) = 3.50 m? (b) As water flows out of the tank, \(h\) decreases. Calculate the speed of flow for \(h\) = 3.00 m and for \(h\) = 2.00 m. (c) At what value of h does the flow stop?

A person at rest inhales 0.50 L of air with each breath at a pressure of 1.00 atm and a temperature of 20.0\(^\circ\)C. The inhaled air is 21.0% oxygen. (a) How many oxygen molecules does this person inhale with each breath? (b) Suppose this person is now resting at an elevation of 2000 m but the temperature is still 20.0\(^\circ\)C. Assuming that the oxygen percentage and volume per inhalation are the same as stated above, how many oxygen molecules does this person now inhale with each breath? (c) Given that the body still requires the same number of oxygen molecules per second as at sea level to maintain its functions, explain why some people report 'shortness of breath' at high elevations.

(a) Calculate the density of the atmosphere at the surface of Mars (where the pressure is 650 Pa and the temperature is typically 253 \(K\), with a \(CO_2\) atmosphere), Venus (with an average temperature of 730 \(K\) and pressure of 92 atm, with a \(CO_2\) atmosphere), and Saturn's moon Titan (where the pressure is 1.5 atm and the temperature is -178\(^\circ\)C, with a \(N_2\) atmosphere). (b) Compare each of these densities with that of the earth's atmosphere, which is 1.20 kg/m\(^3\). Consult Appendix D to determine molar masses.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.