/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 (a) Calculate the specific heat ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol. (b) The actual specific heat of water vapor at low pressures is about 2000 J/kg \(\cdot\) K. Compare this with your calculation and comment on the actual role of vibrational motion.

Short Answer

Expert verified
Calculated specific heat: 1385.67 J/kg K; actual: 2000 J/kg K. Vibrational motion contributes to the actual specific heat.

Step by step solution

01

Determine Degrees of Freedom

For a nonlinear triatomic molecule, the number of degrees of freedom is 3 translational and 3 rotational, giving a total of 6 degrees of freedom.
02

Apply Equipartition Theorem

According to the equipartition theorem, each degree of freedom contributes \( \frac{1}{2} R \) (with \( R = 8.314 \) J/mol K, the universal gas constant) to the energy per mole. So for 6 degrees of freedom, the total molar energy is \( 6 \times \frac{1}{2} R = 3R \).
03

Calculate Molar Specific Heat at Constant Volume

The molar specific heat at constant volume \( C_v \) is equal to the total energy per mole divided by temperature, so:\[C_{v, \, \text{molar}} = 3R = 3 \times 8.314 = 24.942 \, \text{J/mol K}\]
04

Convert to Specific Heat for Water Vapor

Convert molar specific heat to specific heat per kilogram by dividing by the molar mass of water (18.0 g/mol = 0.018 kg/mol):\[c_{v, \, \text{specific}} = \frac{24.942}{0.018} = 1385.67 \, \text{J/kg K}\]
05

Compare with Actual Specific Heat Value

The calculated specific heat \( 1385.67 \) J/kg K is significantly less than the actual value of 2000 J/kg K for water vapor. This difference suggests that vibrational motion, which we did not consider in our assumption, does contribute to the specific heat significantly.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
The term "degrees of freedom" refers to the number of independent ways in which a molecule can store energy. For molecules in the gas phase, degrees of freedom encompass translational, rotational, and vibrational motions. In our problem of nonlinear triatomic molecules like water vapor, the focus is on translational and rotational motions. - Translational motions allow molecules to move freely in three-dimensional space: up-down, left-right, and forward-backward. - Nonlinear molecules also have three rotational degrees of freedom, allowing spinning around each of the three principal axes. Thus, for water vapor as a nonlinear triatomic molecule, the total degrees of freedom traditionally considered is six, which includes three translational and three rotational degrees of freedom. This provides a simplified snapshot of how energy is partitioned within the molecule under these basic motions.
Equipartition Theorem
The equipartition theorem is a fundamental principle in classical physics. It states that each degree of freedom in a system contributes equally to the system's energy. For each degree of freedom, it contributes \( \frac{1}{2} \) times the universal gas constant \( R \) per mole to the energy of a molecule. In the case of our nonlinear triatomic water vapor molecule:- We calculated six degrees of freedom, leading to a total energy contribution of \( 6 \times \frac{1}{2} R = 3R \).- The universal gas constant \( R \) is 8.314 J/mol K. Therefore, the total molar energy for the water molecules under these assumptions is \( 3R \), or about 24.942 J/mol K. This principle helps us determine how molecules store and spread their energy.
Molar Specific Heat
Molar specific heat is an important concept when calculating how substances absorb heat. Specifically, it tells us how much energy one mole of a substance needs to increase its temperature by one Kelvin. Using the equipartition theorem, we determined that the molar specific heat at constant volume \( C_{v, \, \text{molar}} \) for water vapor is \( 3R = 24.942 \, \text{J/mol K} \).To convert this to specific heat per mass, relevant for practical applications, we divide by the molar mass of the substance. In this case, the molar mass of water is 18.0 g/mol or 0.018 kg/mol. Hence, the conversion equation is:\[c_{v, \, \text{specific}} = \frac{24.942}{0.018} = 1385.67 \, \text{J/kg K}\]This calculation provides a theoretical basis for understanding the heat capacity of water vapor without considering vibrational contributions.
Vibrational Motion
Vibrational motion, although not initially considered in many basic calculations, plays a crucial role in the energy dynamics of molecules. Unlike translational and rotational motions, vibrational motion involves the periodic movement of atoms within a molecule around a point of equilibrium. For water vapor:
  • Vibrational motion can significantly contribute additional degrees of freedom, raising the energy storage capacity of the molecule.
  • Only at higher temperatures do these vibrational modes often become "active," as molecules require more energy to excite these movements.
In practice, the actual specific heat of water vapor is around 2000 J/kg K, markedly higher than the theoretical 1385.67 J/kg K calculation. This discrepancy indicates that vibrational motion does in fact contribute significantly to the heat capacity. Thus, acknowledging vibrational modes is essential for precise thermal analysis, especially at higher temperatures.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A large tank of water has a hose connected to it (Fig. P18.59). The tank is sealed at the top and has compressed air between the water surface and the top. When the water height \(h\) has the value 3.50 m, the absolute pressure \(p\) of the compressed air is 4.20 \(\times\) 10\(^5\) Pa. Assume that the air above the water expands at constant temperature, and take the atmospheric pressure to be 1.00 \(\times\) 10\(^5\) Pa. (a) What is the speed with which water flows out of the hose when \(h\) = 3.50 m? (b) As water flows out of the tank, \(h\) decreases. Calculate the speed of flow for \(h\) = 3.00 m and for \(h\) = 2.00 m. (c) At what value of h does the flow stop?

A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.110 m\(^3\) of air at a pressure of 0.355 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.390 m\(^3\). If the temperature remains constant, what is the final value of the pressure?

You have two identical containers, one containing gas \(A\) and the other gas \(B\). The masses of these molecules are \(m$$_A\) = 3.34 \(\times\) 10\({^-}{^2}{^7}\) kg and \(m$$_B\) = 5.34 \(\times\) 10\({^-}{^2}{^6}\) kg. Both gases are under the same pressure and are at 10.0\(^\circ\)C. (a) Which molecules (\(A\) or \(B\)) have greater translational kinetic energy per molecule and rms speeds? (b) Now you want to raise the temperature of only one of these containers so that both gases will have the same rms speed. For which gas should you raise the temperature? (c) At what temperature will you accomplish your goal? (d) Once you have accomplished your goal, which molecules (\(A\) or \(B\)) now have greater average translational kinetic energy per molecule?

A sealed box contains a monatomic ideal gas. The number of gas atoms per unit volume is 5.00 \(\times\) 10\({^2}{^0}\) atoms/cm\(^3\), and the average translational kinetic energy of each atom is 1.80 \(\times\) 10\({^-}{^2}{^3}\) \(J\). (a) What is the gas pressure? (b) If the gas is neon (molar mass 20.18 g/mol), what is \(\upsilon {_r}{_m}{_s}\) for the gas atoms?

Perfectly rigid containers each hold \(n\) moles of ideal gas, one being hydrogen (H\(_2\)) and the other being neon (Ne). If it takes 300 J of heat to increase the temperature of the hydrogen by 2.50\(^\circ\)C, by how many degrees will the same amount of heat raise the temperature of the neon?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.