/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 A jungle veterinarian with a blo... [FREE SOLUTION] | 91Ó°ÊÓ

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A jungle veterinarian with a blow-gun loaded with a tranquilizer dart and a sly \(1.5-\mathrm{kg}\) monkey are each 25 \(\mathrm{m}\) above the ground in trees 90 \(\mathrm{m}\) apart. Just as the hunter shoots horizontally at the monkey, the monkey drops from the tree in a vain attempt to escape being hit. What must the minimum muzzle velocity of the dart have been for the hunter to hit the monkey before it reached the ground?

Short Answer

Expert verified
The minimum muzzle velocity must be approximately 39.82 m/s.

Step by step solution

01

Analyze the Problem

We need to determine the muzzle velocity of a tranquilizer dart shooting horizontally so that it hits a falling monkey. The key to solving this problem is realizing that both the dart and the monkey are subject to the same gravitational acceleration, which influences their vertical motion.
02

Write the Equations for Motion

Since the monkey and the dart experience the same gravity, we can analyze their motion separately and focus on the horizontal motion of the dart. The horizontal distance is 90 meters. The monkey begins at the same height as the dart, 25 meters above ground. - Horizontal motion of dart: \[ x = v_0 \cdot t \]where \( x = 90 \) m, \( t \) is the time, and \( v_0 \) is the muzzle velocity.- Vertical motion of the monkey: \[ y = \frac{1}{2} g t^2 = 25 \]where \( g = 9.8 \) m/s² and \( y = 25 \) m.
03

Solve for Time of Fall

We solve the vertical motion equation to find the time it takes for the monkey to hit the ground.\[ 25 = \frac{1}{2} \times 9.8 \times t^2 \]Solving this gives:\[ t^2 = \frac{50}{9.8} \]\[ t = \sqrt{\frac{50}{9.8}} \]
04

Calculate the Muzzle Velocity

Now, use the time from Step 3 to solve the horizontal motion equation for the muzzle velocity \( v_0 \):\[ 90 = v_0 \cdot \sqrt{\frac{50}{9.8}} \]Thus, solving for \( v_0 \):\[ v_0 = \frac{90}{\sqrt{\frac{50}{9.8}}} \]
05

Numerical Calculation

Calculate the numerical value to find the exact muzzle velocity:\[ t = \sqrt{\frac{50}{9.8}} \approx 2.26 \text{ seconds} \]\[ v_0 = \frac{90}{2.26} \approx 39.82 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Motion
In the scenario where a tranquilizer dart is shot towards a monkey, understanding the horizontal motion of the dart is crucial. Horizontal motion refers to the movement along a straight line parallel to the ground. This involves calculating the distance the dart travels over time.

A key formula used is:
  • \( x = v_0 \cdot t \)
Where \( x \) is the horizontal distance (90 m in this problem), \( v_0 \) is the muzzle velocity of the dart, and \( t \) is the time in seconds that the dart is in motion.

Horizontal motion is straightforward because, in the absence of air resistance, it is unaffected by gravity. The dart maintains a constant velocity horizontally. This means that the dart's horizontal speed stays the same until it hits the target or is stopped by another force. Understanding horizontal motion helps us determine how long it takes for the dart to reach the monkey.
Vertical Motion
Vertical motion, on the other hand, is heavily affected by gravitational forces. In our context, both the tranquilizer dart and the monkey have vertical motion to consider. Vertical motion refers to the up-and-down movement of objects under the influence of gravity.

The equation governing vertical motion is:
  • \( y = \frac{1}{2} g t^2 \)
Here, \( y \) is the vertical displacement, \( g \) is the gravitational acceleration (\(9.8\,\text{m/s}^2\)), and \( t \) is the time taken to fall. For the monkey in the problem, this formula helps determine how long it falls before potentially being hit by the dart.

Vertical motion is identical for both the dart and the monkey since both are accelerated by the same gravitational force, despite potentially moving with different speeds horizontally.
Gravitational Acceleration
Gravitational acceleration is a constant that affects all objects in free fall near the Earth's surface. It is denoted by \( g \) and approximated as \( 9.8\,\text{m/s}^2 \). This means any object dropped will accelerate downwards at this rate due to gravity.

The presence of gravitational acceleration means that both the dart and the monkey are falling vertically at the same rate of increase in velocity. This acceleration impacts any calculations involving the time it takes an object to hit the ground when it is dropped from a height.

In our exercise, gravitational acceleration is crucial because it ensures that the dart and monkey coincide vertically, when both are subjected to the same time of fall. Despite their independent horizontal speeds, vertically, they are identical in motion due to gravity's influence.
Tranquilizer Dart
Understanding the role of the tranquilizer dart in projectile motion adds another layer. The dart is shot horizontally at a certain velocity toward the falling monkey. It is important to establish the minimum velocity needed for the dart to traverse the horizontal distance before the monkey hits the ground.

The tranquilizer dart is unique because it is mainly affected by horizontal velocity, while also inevitably affected by vertical gravitational pull. Initially, it does not have vertical motion, but gravity soon influences it downwards. The minimal initial velocity calculated takes into account how quickly it must travel to make contact before the monkey reaches the jungle floor.

This exercise illustrates how the tranquilizer dart's physics plays out in real-life situations, reiterating essential physics concepts like motion in two dimensions and the effects of gravity.

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