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An elevator is moving upward at a constant speed of 2.50 \(\mathrm{m} / \mathrm{s}\) . A bolt in the elevator ceiling 3.00 \(\mathrm{m}\) above the elevator floor works loose and falls. (a) How long does it take for the bolt to fall to the elevator floor? What is the speed of the bolt just as it hits the elevator floor (b) according to an observer in the elevator? (c) According to an observer standing on one of the floor landings ofm the building? (d) According to the observer in part(c), what distance

Short Answer

Expert verified
(a) 0.78 s; (b) 7.65 m/s; (c) 7.49 m/s; (d) 2.57 m.

Step by step solution

01

Define the Problem

We need to determine how long it takes for the bolt to fall and its speed when it hits the floor, as observed by different perspectives (inside the elevator and from the building). The elevator is moving upward at 2.50 m/s, and the distance from the ceiling to the floor is 3.00 m.
02

Consider Observer in Elevator (a)

From the observer inside the elevator, the initial velocity (\( v_0 \)) of the bolt is 0 m/s relative to the elevator because both start together. Use the equation of motion: \( s = v_0t + \frac{1}{2} a t^2 \).Here, \( s = 3.00 \, \mathrm{m}\), \( v_0 = 0 \, \mathrm{m/s}\), and \( a = 9.81 \, \mathrm{m/s^2} \).Solving for \( t \):\[ 3.00 = \frac{1}{2} \times 9.81 \times t^2 \]\[ t^2 = \frac{3.00 \times 2}{9.81} \]\[ t = \sqrt{\frac{6.00}{9.81}} \]\[ t \approx 0.78 \text{ seconds}\]
03

Find Bolt Speed as it Hits Floor (b) Observer in Elevator

Use the kinematic equation for final velocity: \( v_f = v_0 + at \).Substitute \( v_0 = 0 \), \( a = 9.81 \, \mathrm{m/s^2} \), and \( t = 0.78 \, \mathrm{s} \):\[ v_f = 0 + 9.81 \times 0.78 \]\[ v_f \approx 7.65 \, \mathrm{m/s} \]Thus, to the observer in the elevator, the speed is approximately 7.65 m/s just before impact.
04

Consider Observer in Building for (c)

Here, the observer on the floor sees the initial velocity of the bolt as the upward speed of the elevator, 2.50 m/s upward. The motion equation for the bolt is relative to the building:Start with \( v_i = -2.50 \, \mathrm{m/s} \) (downward for the bolt), \( a = 9.81 \, \mathrm{m/s^2} \):Use equation: \( s = v_i t + \frac{1}{2} a t^2 \).Since the motion goes beyond 3.00 m if considered from the building, recalibrate with:\[ 3.00 = -2.50t + \frac{1}{2} \times 9.81t^2 \]Solve for \( t \) to determine time till it hits floor under these conditions.
05

Calculate Time for Observer in Building

This requires solving the quadratic equation:\( 0 = 4.905t^2 - 2.50t - 3.00 \).Using the quadratic formula \( t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \):\( a = 4.905, b = -2.50, c = -3.00 \).\[ t = \frac{-(-2.50) \pm \sqrt{(-2.50)^2 - 4 \times 4.905 \times (-3.00)}}{2 \times 4.905} \]\[ t \approx 1.02 \text{ seconds} \]
06

Calculate Final Speed for Observer in Building (c)

Use equation \( v_f = v_i + a t \), where \( v_i = -2.50 \, \mathrm{m/s} \) and \( t = 1.02 \, \mathrm{s} \).\[ v_f = -2.50 + 9.81 \times 1.02 \]\[ v_f \approx 7.49 \, \mathrm{m/s} \]This is the speed observed by someone standing in the building.
07

Determine Distance Traveled (d) Observer in Building

For the observer in the building, calculate the distance the bolt travels:Use equation: \( s = v_i t + \frac{1}{2} at^2 \).\( v_i = -2.50 \, \mathrm{m/s} \), \( a = 9.81 \, \mathrm{m/s^2} \), \( t = 1.02 \, \mathrm{s} \):\[ s = -2.50 \times 1.02 + \frac{1}{2} \times 9.81 \times (1.02)^2 \]\[ s \approx 2.57 \text{ meters} \]
08

Assemble Final Answer

(a) Time to fall: 0.78 seconds. (b) Speed in elevator: 7.65 m/s. (c) Speed to building observer: 7.49 m/s. (d) Distance to building observer: 2.57 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is a branch of physics that describes the motion of objects without considering the forces that cause the motion. In this problem, we focused on how a bolt falls from the ceiling of an elevator moving upwards. One key aspect is understanding the equations of motion, which help us determine various parameters like time, velocity, and displacement. These equations form the backbone of analyzing motion in one dimension.

When tackling kinematics problems, the following equations are essential:
  • Displacement (s): \( s = v_0t + \frac{1}{2} a t^2 \)
  • Final velocity (v_f): \( v_f = v_0 + at \)
Where:
  • \( v_0 \) is the initial velocity,
  • \( a \) is the acceleration (usually gravity for free-falling objects, where \( a = 9.81 \, \mathrm{m/s^2} \)),
  • \( t \) is the time,
  • \( s \) is the displacement or distance.

Understanding each of these elements in context helps solve kinematic problems effectively, as seen when calculating the time and final speed of the falling bolt.
Relative Motion
Relative motion is crucial when analyzing how different observers perceive motion. In this scenario, the bolt's motion appears differently to someone in the elevator compared to an observer standing stationary on a floor landing.

For the observer inside the elevator, the bolt's motion is straightforward. Since both started moving simultaneously, the bolt's initial velocity is \( 0 \, \mathrm{m/s} \) relative to the elevator. Hence, applying the kinematic equations becomes simple. For an outside observer, however, the initial velocity includes the elevator's upward speed of \( 2.50 \, \mathrm{m/s} \).

When studying relative motion:
  • Identify the observers and note if they move with constant velocity.
  • Determine the initial velocities from each observer's viewpoint.
  • Apply equations accordingly to obtain time, speed, and distances specific to each observer's perspective.

This concept highlights that motion is just as much about perspective as it is about physical movement. Always take into account these differences to accurately describe motion as seen by different observers.
Free Fall
Free fall describes the motion of objects moving under the influence of gravity alone. In this problem, the bolt experiences free fall after breaking loose from the elevator ceiling. While gravity is the only force acting on the bolt, its initial conditions, like the elevator's movement, affect how different observers see this motion.

Key characteristics of free fall include:
  • An acceleration of about \( 9.81 \, \mathrm{m/s^2} \) in a downward direction on Earth.
  • Absence of air resistance when considering ideal conditions.
  • The initial vertical velocity set by the context, such as the velocity of the moving elevator viewed by an outside observer.

By applying the principles of free fall, we can determine how long it takes the bolt to reach the elevator floor and its speed upon impact. It shows that regardless of horizontal motion or initial upward speed, gravity uniformly accelerates all objects downward at the same rate. Thus, mastering these nuances of free fall helps in analyzing and solving many problems involving motion due to gravity.

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