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Spiraling Up. It is common to see birds of prey rising upward on thermals. The paths they take may be spiral-like. You can model the spiral motion as uniform circular motion combined with a constant upward velocity. Assume a bird completes a circle of radius 8.00 \(\mathrm{m}\) every 5.00 \(\mathrm{s}\) and rises vertically at a rate of 3.00 \(\mathrm{m} / \mathrm{s}\) . Determine: (a) the speed of the bird relative to the ground; \((b)\) the bird's acceleration (magnitude and direction); and (c) the angle between the bird's velocity vector and the horizontal.

Short Answer

Expert verified
The bird's speed is approximately 10.49 m/s, acceleration is 12.63 m/s², and the velocity vector angle is about 16.7° above horizontal.

Step by step solution

01

Calculate the Horizontal Speed

The bird completes a circle of radius 8 m in 5 seconds. The circumference of the circle is given by \( C = 2\pi r \) where \( r = 8 \mathrm{m} \). Thus, \( C = 16\pi \mathrm{m} \). The horizontal speed \( v_h \) is thendetermined by \( v_h = \frac{C}{T} \), where \( T = 5 \mathrm{s} \). Therefore, \( v_h = \frac{16\pi}{5} \approx 10.05 \mathrm{m/s} \).
02

Calculate the Speed of the Bird Relative to the Ground

The total speed of the bird is a combination of its horizontal and vertical speeds. The vertical speed \( v_v = 3.00 \mathrm{m/s} \). The bird's total speed \( v \) relative to the ground is given by \( v = \sqrt{v_h^2 + v_v^2} \). Therefore, \( v = \sqrt{(10.05)^2 + (3.00)^2} \approx 10.49 \mathrm{m/s} \).
03

Calculate the Bird's Acceleration

The bird's acceleration comprises the centripetal acceleration due to its circular motion. The centripetal acceleration \( a_c \) is given by \( a_c = \frac{v_h^2}{r} \), where \( r = 8 \mathrm{m} \) and \( v_h = 10.05 \mathrm{m/s} \). Thus, \( a_c = \frac{(10.05)^2}{8} \approx 12.63 \mathrm{m/s^2} \), directed towards the center of the circle.
04

Calculate Angle Between Velocity Vector and Horizontal

To find the angle \( \theta \) between the bird's velocity vector and the horizontal, use the relationship \( \tan\theta = \frac{v_v}{v_h} \), where \( v_v = 3.00 \mathrm{m/s} \) and \( v_h = 10.05 \mathrm{m/s} \). Thus, \( \theta = \tan^{-1}\left(\frac{3.00}{10.05}\right) \approx 16.70^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Circular Motion
Uniform circular motion occurs when an object moves in a circle at a constant speed. Despite the constant speed, the direction of the object changes continuously, which means, technically, there is acceleration. For example, a bird flying in a spiral path, such as described above, partakes in uniform circular motion in the horizontal plane. The bird completes a circle of a specific radius in a fixed period of time, maintaining a constant horizontal velocity. This scenario requires calculating the circumference of the circle—using the formula \( C = 2\pi r \)—and then determining the speed using \( v = \frac{C}{T} \), where \( r \) is the radius and \( T \) is the time to complete one loop. This calculated speed represents the uniform velocity around the circle. It's important to see that, although the speed is constant, the velocity vector keeps moving directionally to remain tangent to the circle's path.
Vertical Velocity
The vertical velocity is part of the bird’s overall motion, describing how fast it rises or falls as it moves along the spiral path. In many curvilinear motions, such as when birds ascend thermals, vertical velocity adds another layer of complexity. Here, the bird rises at a constant vertical rate of 3 meters per second, independently from its horizontal circular motion. This constant speed implies that there is no vertical acceleration; the bird simply continues rising at the same rate. By considering both the horizontal and vertical velocities, we understand the bird's overall speed relative to the ground. This is calculated by combining both velocity components using the Pythagorean theorem: \( v = \sqrt{v_h^2 + v_v^2} \). This allows us to view the bird’s total motion, combining ascension with uniform circular movement.
Centripetal Acceleration
Centripetal acceleration is crucial for understanding the physics of circular motion. Whenever an object rotates in a circular path, there is a central force constantly pulling it toward the center of that path. This force is responsible for changing the direction of the velocity as the object spins, despite keeping the speed constant. For the spiral path, the centripetal acceleration \( a_c \) can be calculated using the formula \( a_c = \frac{v_h^2}{r} \) where the horizontal speed \( v_h \) and radius \( r \) are known. This measure provides insight into how tightly the bird is turning while partaking in its upward spiral motion. The level of this acceleration, directed inward towards the center of the circle, affects how sharply the bird maneuvers its flight path without changing its speed.
Velocity Vector Angle
The angle of the velocity vector relative to the horizontal grants insight into the bird's path through the air. It signifies the direction in which the bird is moving with respect to both its horizontal circular motion and upward velocity. Using trigonometric relationships, specifically the tangent function, this angle \( \theta \) can be determined. The formula \( \tan\theta = \frac{v_v}{v_h} \) helps in calculating this angle. Here, \( v_v \) is the vertical velocity and \( v_h \) is the horizontal velocity. This approach provides the bird's path angle above the horizontal plane, painting the full picture of its flight direction. Understanding this angle helps visualize the combined effect of vertical rise and circular motion, allowing for a comprehensive grasp of the bird’s dynamic spiral path.

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