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An empty cylindrical canister 1.50 \(\mathrm{m}\) long and 90.0 \(\mathrm{cm}\) in diameter is to be filled with pure oxygen at \(22.0^{\circ} \mathrm{C}\) to sture in a space station. To hold as thuch gas as possible, the absolute pressure of the oxygen will be 21.0 atm. The molar mass of oxygen is 32.0 \(\mathrm{g} / \mathrm{mol}\) . (a) How many tholes of oxygen does this canister hold? (b) For someone lifting this canister, by how many kilo-grams does this gas increase the mass to be lifted?

Short Answer

Expert verified
(a) The canister holds approximately 824 moles of oxygen. (b) The gas increases the mass by about 26.4 kg.

Step by step solution

01

Convert Units

First, convert all measurements into SI units. The diameter of the cylinder is given in centimeters. Convert this to meters: \(90.0\, \text{cm} = 0.90\, \text{m}\). Thus, the radius \(r = \frac{0.90}{2} = 0.45\, \text{m}\). The pressure is given in atm, convert this to Pascals using the conversion \(1 \, \text{atm} = 101325 \, \text{Pa}\): \(21.0 \, \text{atm} = 21.0 \times 101325 = 2127825 \, \text{Pa}\). The temperature is \(22.0^{\circ}\, \text{C}\), so convert this to Kelvin: \(22.0 + 273.15 = 295.15 \, \text{K}\).
02

Calculate the Volume

Find the volume of the cylindrical canister using the formula for the volume of a cylinder, \( V = \pi r^2 h \), where \( r \) is the radius and \( h \) is the height of the cylinder.\[ V = \pi (0.45 \, \text{m})^2 (1.50 \, \text{m}) = \pi \times 0.2025 \times 1.50 \approx 0.955 \; \text{m}^3 \]
03

Use Ideal Gas Law to find Moles of Oxygen

Apply the ideal gas law \( PV = nRT \) to find the number of moles \( n \). Here \( P \) is the pressure in Pascals, \( V \) is the volume in cubic meters, \( R = 8.314 \, \text{J/(mol}\cdot\text{K)} \), and \( T \) is the temperature in Kelvin.\[ n = \frac{PV}{RT} = \frac{(2127825)(0.955)}{8.314 \times 295.15} \]\[ n \approx 824.22 \; \text{moles} \]
04

Calculate Mass of the Gas

Using the number of moles calculated, determine the mass of the gas using the formula \( m = n \times M \), where \( M \) is the molar mass of oxygen (32.0 \( \text{g/mol} \) or 0.032 \( \text{kg/mol} \)).\[ m = 824.22 \times 0.032 = 26.375 \; \text{kg} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cylindrical Geometry
Understanding cylindrical geometry is crucial when working on problems involving objects like canisters. A cylinder is a 3-dimensional shape with two parallel circular bases and a specific height.
To calculate the volume of a cylinder, the formula is:
  • \( V = \pi r^2 h \)
In this equation:
  • \( V \) is the volume, which tells us how much space is inside the cylinder.
  • \( r \) is the radius of the circular base, which is half of the diameter.
  • \( h \) is the height or length of the cylinder.
For example, if you have a cylindrical canister that is 1.50 meters long and has a diameter of 0.90 meters, you first need to find the radius, which is 0.45 meters, since radius is the diameter divided by 2. Then, you plug these into the formula to calculate the volume. This volume helps in determining how much of something, like gas, the cylinder can hold.
Understanding this concept allows you to handle various problems involving cylindrical shapes efficiently.
Mole Calculation
Mole calculations are fundamental in chemistry, especially when dealing with gases. A mole is a unit that measures the amount of a substance. It provides a bridge between the atomic world and the real world.
When you are tasked to find out how many moles of a gas are present in a container, you'll often use the ideal gas law. The ideal gas law formula is:
  • \( PV = nRT \)
Where:
  • \( P \) is the pressure exerted by the gas.
  • \( V \) is the volume the gas occupies.
  • \( n \) is the number of moles.
  • \( R \) is the ideal gas constant, equal to 8.314 J/(mol·K).
  • \( T \) is the temperature, measured in Kelvin.
By rearranging the equation, you can solve for the number of moles:
  • \( n = \frac{PV}{RT} \)
For instance, in an exercise where you know the volume, pressure, and temperature of the gas, you can simply place these values into the formula to determine the number of moles present in the container. This step is vital when trying to understand how gases behave under certain conditions.
Unit Conversion
Unit conversion is an essential skill in science, as it allows you to translate measurements into different units, making them easier to use in calculations. This is particularly important when your given measurements are not in the desired units.
Let's look at common unit conversions related to gases. Pressure may be given in atmospheres (atm) but often needs to be converted to Pascals (Pa) when working with the ideal gas law. The conversion is:
  • 1 atm = 101325 Pa
Similarly, temperature is frequently provided in degrees Celsius but must be converted to Kelvin for gas law calculations. The conversion is:
  • \( K = °C + 273.15 \)
For lengths, you may convert from centimeters to meters by simply dividing by 100, as 1 meter equals 100 centimeters.
These conversions may seem trivial, but precise and careful unit conversion ensures that calculations are accurate and meaningful. Incorrect conversions can lead to errors in data interpretation, so mastering this skill is essential in scientific problem-solving.

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Most popular questions from this chapter

The speed of propagation of a sound wave in air at \(27^{\circ} \mathrm{C}\) is about 350 \(\mathrm{m} / \mathrm{s}\) . Calculate, for comparison, (a) \(v_{\mathrm{ms}}\) for nitrogen molecules and (b) the rms value of \(v_{x}\) at this temperature. The molar mass of nitrogen \(\left(\mathrm{N}_{2}\right)\) is \(28.0 \mathrm{g} / \mathrm{mol} .\)

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.200 \(\mathrm{m}\) . (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is \(20.0^{\circ} \mathrm{C} ?\) (b) What is the force when the temperature of the gas is increased to \(100.0^{\circ} \mathrm{C}\) ?

It is possible to make crystalline solids that are only one layer of atoms thick. Such "two-dimensional" crystals can be created by depositing atoms on a very flat surface. (a) If the atoms in such a two-dimensional crystal can move only within the plane of the crystal, what will be its molar heat capacity near room temperature? Give your answer as a multiple of \(R\) and in \(\mathrm{J} / \mathrm{nol} \cdot \mathrm{K}\) . (b) At very low temperatures, will the molar heat capacity of a two- dimensional crystal be greater than, less than, or equal to the result you found in part (a)? Explain why.

The total lung volume for a typical physics student is 6.00 \(\mathrm{L}\) . A physics student fills her lungs with air an absolute pressure of 1.00 atm. Then, holding her breath, she compresses her chest cavity, decreasing her lung volume to 5.70 \(\mathrm{L}\) . What is the pressure of the air in her lungs then? Assume that temperature of the air remains constant.

A physicist places a piece of ice at \(0.00^{\circ} \mathrm{C}\) and a beaker of water at \(0.00^{\circ} \mathrm{C}\) inside a glass box and closes the lid of the box. All the air is then removed from the box. If the ice, water, and beaker are all maintained at a temperature of \(0.00^{\circ} \mathrm{C},\) describe the final equilibrium state inside the box.

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