/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11. A car traveling at 95 km/h is 21... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Q11. (page 43)

A car traveling at 95 km/h is 210 m behind a truck traveling at 75 km/h. How long will it take for the car to reach the truck?

Short Answer

Expert verified

The car takes 37.77 s to reach the truck.

Step by step solution

01

Step 1. Finding the car’s and truck’s velocity in the SI unit

The velocity of a body is defined as the displacement of the body in unit time. The velocity of a body is a scalar quantity and has the same unit as that of speed.

Given data.

The speed of the car is

vc=95kmh=95kmh脳1000m1km脳1h3600s=26.39ms

The speed of the truck is

vt=75kmh=75kmh脳1000m1km脳1h3600s=20.83ms

The car is 210 m behind the truck.

Assumption.

Assume that the car takes t time to reach the truck.

02

Step 2. Calculation of the time using the relation between distance, speed, and time

Then, the distance traveled by the car in time t is dc=鈥�vc鈥�t, and the distance traveled by the truck in time t is dt=鈥�vt鈥�t.

Now, after t time, they are in the same position. Then,

vct=vtt+210mvc-vtt=210m26.39ms-20.83mst=210mt=37.77s

Therefore, the car takes 37.77 s to reach the truck.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A rocket rises vertically, from rest, with an acceleration of3.2m/s2until it runs out of fuel at an altitude of 775 m. After this point, its acceleration is that of gravity, downward.(a) What is the velocity of the rocket when it runs out of fuel?(b) How long does it take to reach this point?(c) What maximum altitude does the rocket reach?(d) How much time (total) does it take to reach the maximum altitude?(e) With what velocity does it strike the earth?(f) How long (total) is it in the air?

A helicopter is ascending vertically with a speed of 5.40 m/s. At a height of 105 m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?]

If particle A at t1=-2.0s is at x1=4.8cm, and at t2=4.5s is at x2=8.5cm, what is its average velocity over this time interval? Can you calculate its average speed from these data? Why or why not?

A light plane must reach a speed of 35 m/s for takeoff. What length of a runway is needed if the (constant) acceleration is 3.0 m/s2?

Can an object have zero acceleration and non-zero velocity at the same time? Give examples.
See all solutions

Recommended explanations on Physics Textbooks

Engineering Physics

Read Explanation

Nuclear Physics

Read Explanation

Magnetism

Read Explanation

Astrophysics

Read Explanation

Circular Motion and Gravitation

Read Explanation

Space Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.