/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A simple pendulum consists of a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A simple pendulum consists of a small object of mass 3.0 kg hanging at the end of a \(2.0\) -m-long light string that is connected to a pivot point. (a) Calculate the magnitude of the torque (due to the force of gravity) about this pivot point when the string makes a \(5.0^{\circ}\) angle with the vertical. (b) Does the torque increase or decrease as the angle increases? Explain.

Short Answer

Expert verified
The torque applied when the string makes a 5.0° angle with the vertical is 5.1 N·m. The torque will increase as the angle increases from 0 to 90 degrees, then start to decrease again as the angle increases past 90 degrees as it is directly proportional to the sin of the angle.

Step by step solution

01

Understand the problem and identify the given values

The given scenario involves a simple pendulum with a mass m = 3.0 kg at the end of a 2.0 m light string. Gravity is applying force on it that would produce some torque when the string makes a 5.0° angle with the vertical.
02

Formula for torque

The formula for the torque \( \tau \) due to the force of gravity is given by \( \tau = r F \sin(\theta) \), where r is the distance from the pivot point (the length of the string), F is the force applied, and \( \theta \) is the angle between the string and the vertical in degrees.
03

Calculate the force

The force due to gravity (weight of the pendulum) can be calculated using the formula F = mg where m is the mass and g is the acceleration due to gravity. Substituting the given values, F = (3.0 kg)(9.8 m/s²) = 29.4 N.
04

Plug the values into the torque formula

Substitute the calculated force and the given values into the formula for torque. With the given values, \( \tau = (2.0 m)(29.4 N) \sin(5.0°) = 5.1 N·m \) (rounded to the nearest tenth).
05

Relation between angle and torque

We know from the formula for torque that the magnitude of the torque \( \tau \) is directly proportional to the sine of the angle \( \theta \). Hence, as the angle \( \theta \) increases, the torque also increases, until \( \theta \) reaches 90° at which point it will begin to decrease again because the sine of the angle starts to decrease. The reason for this is the force exerted that creates torque is at its maximum when the pendulum is at a right angle to the force of gravity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque in Physics
Torque, often symbolized as \( \tau \), is a measure of the rotational force applied to an object. It's the product of the force applied and the distance from the point of rotation to the point where the force is applied, essentially the radius, denoted by \( r \). When we look at a simple pendulum, such as the one in the given problem, the torque caused by the gravitational force is calculated as \( \tau = r F \sin(\theta) \).

This equation incorporates not only the gravitational force \( F \) and the length of the pendulum \( r \), but also the \( \sin(\theta) \) term, which represents the efficiency of the force in creating rotational movement around the pivot point. The angle \( \theta \) is critical because it determines the component of the gravitational force that actually contributes to the rotation (the perpendicular component). As the angle deviates from 0°, the perpendicular component, and therefore the torque, increases, reaching a peak at 90°.
Gravitational Force
Gravitational force is the attractive force between two bodies due to their mass. In physics, we often approximate this force near the Earth's surface as the weight of an object, which is the mass multiplied by the acceleration due to gravity \( (F = mg) \).

In the context of the simple pendulum problem, gravity is the force that's responsible for the torque that causes the pendulum to swing. This force acts at the center of mass of the pendulum bob and points directly towards the Earth's center. When performing calculations like those in our given problem, it is essential to remember that only the component of the gravitational force that acts perpendicular to the radius (the line from the pivot point to the mass) contributes to the pendulum's torque.
Angular Displacement
Angular displacement is the angle through which a point or line has been rotated in a specified sense about a specified axis. It is different from linear displacement, which measures the distance directly from one point to another. In the case of our simple pendulum, angular displacement is measured by the angle \( \theta \) between the string of the pendulum and the vertical.

The sine of the angular displacement, \( \sin(\theta) \), in the torque formula, determines how much of the gravitational force is effectively producing the rotational motion of the pendulum. If the angle is 0°, sin(0°) equals 0, and so there is no torque because the force is acting entirely along the line of the string and not perpendicularly. As \( \theta \) increases, so does sin(\theta), and accordingly, the torque until reaching the maximum at 90°, beyond which \( \sin(\theta) \) decreases.
Simple Harmonic Motion
Simple harmonic motion (SHM) describes a type of periodic motion or oscillation motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement. A simple pendulum is a classic example of SHM if we assume that the amplitude of the swing is small.

When we pull the pendulum to one side and release it, the gravitational force pulls it back towards the midpoint, which is its equilibrium position. As it moves past the equilibrium, the gravitational force acts to slow it down and pull it back again, creating an oscillating motion. The period of a simple pendulum undergoing SHM depends only on the length of the string and the acceleration due to gravity and is independent of the mass of the pendulum bob. This characteristic oscillating behavior is fundamental in understanding phenomena across various scientific disciplines.

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