/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 A painter climbs a ladder leanin... [FREE SOLUTION] | 91Ó°ÊÓ

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A painter climbs a ladder leaning against a smooth wall. At a certain height, the ladder is on the verge of slipping. (a) Explain why the force exerted by the vertical wall on the ladder is horizontal. (b) If the ladder of length \(L\) leans at an angle \(\theta\) with the horizontal, what is the lever arm for this horizontal force with the axis of rotation taken at the base of the ladder? (c) If the ladder is uniform, what is the lever arm for the force of gravity acting on the ladder? (d) Let the mass of the painter be \(80 \mathrm{~kg}, L=4.0 \mathrm{~m}\), the ladder's mass be \(30 \mathrm{~kg}, \theta=53^{\circ}\), and the coefficient of friction between ground and ladder be \(0.45\). Find the maximum distance the painter can climb up the ladder.

Short Answer

Expert verified
Maximum distance the painter can climb is calculated using the formula mentioned in Step 4.

Step by step solution

01

Explanation of force direction

The wall is smooth, which means it does not exert any vertical force (no friction). The only force it can exert is perpendicular to the wall, which is always horizontal.
02

Calculation of lever arm for wall force

The lever arm for the force by the wall is the perpendicular distance from force line of action to the axis of rotation. In this case, it would be \(L \sin \theta\), where \(L\) is the length of the ladder and \(\theta\) is the angle the ladder makes with the horizontal.
03

Calculation of lever arm for gravity on the ladder

The lever arm for the force of gravity acting on the ladder is the perpendicular distance from the center of mass of the ladder to the axis of rotation. Since the ladder is uniform, its center of mass is in the middle: \(L/2 \cos \theta\)
04

Determine the maximum distance the painter can climb

The system is in static equilibrium, which means the sum of all torques must be zero. Based on the distances of all forces from the base of the ladder, we can write the equilibrium condition as \((F_P \cdot d) + (M_Lg/2 \cdot L \cos \theta )= (M_Pg + M_Lg) \cdot f_sL\), where \(F_P\) is the painter's force, \(d\) is the maximum distance the painter can climb, \(M_P\) and \(M_L\) are masses of the painter and ladder respectively, \(g\) is the acceleration due to gravity, and \(f_s\) is the friction coefficient. Reorganizing terms, we get \(d = \frac{(M_Pg + M_Lg) \cdot f_sL - M_Lg/2 \cdot L \cos \theta}{F_P}\). Substituting given values, \(d\) can be calculated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque and Equilibrium
Understanding the balance of forces and rotational effects is crucial for safety in everyday structures, such as a ladder against a wall. Torque, a measure of the rotational force, plays a pivotal role in static equilibrium—the condition where an object remains at rest with no rotation.

Each force acting on a system can create its own torque about a pivot point, which depends on two aspects: the magnitude of the force and the distance from the pivot, known as the lever arm. In the case of a ladder, the pivot point is usually at the base. The condition for static equilibrium is met when the net sum of all torques around the pivot is zero, implying that no net rotational motion will occur.

For example, when a painter climbs a ladder, their weight creates a torque that could potentially tip the ladder over. To prevent this, the friction between the ladder's base and the ground, along with the horizontal force exerted by the wall, create opposing torques. When these torques balance, we have achieved static equilibrium.
Forces on an Inclined Plane
Inclined planes are a common physical setup in physics problems, involving objects like ladders leaning against walls. These scenarios employ several forces, including gravity, friction, and normal forces, each acting in different directions. Specifically, the force of gravity will cause an object on an incline to accelerate down the slope unless opposed by friction or another force.

The component of gravitational force acting down the inclined plane depends on the sine of the angle \( \theta \) between the plane and the horizontal, while the component perpendicular to the plane depends on the cosine of that angle. It's crucial to decompose these forces correctly to determine how they'll affect the object's motion and the net torque exerted on the system.
Coefficient of Friction
Friction is the resistant force encountered when one surface slides over another, and it's vital for maintaining stability in various situations, such as walking or driving. The coefficient of friction, denoted by \( \mu \), is a dimensionless value representing the ratio of the force of friction between two bodies and the force pressing them together.

There are two types of coefficient: static (\(\mu_s\)) and kinetic (\(\mu_k\)). In our case, the static coefficient pertains to the initial frictional force needed to make the ladder start moving against the ground. It is generally greater than the kinetic coefficient because more force is required to overcome initial inertia compared to keeping the object moving. This coefficient is essential in calculations to ensure the ladder remains stable and the painter can safely climb it without slipping.
Center of Mass
The center of mass is the point at which the mass of an object or system is thought to be concentrated. In physics, it's the point where external forces and torques can be considered to apply for the purpose of translational and rotational motion analyses.

For regular objects with uniform density, like a uniform ladder, the center of mass is located at its geometric center. For instance, the center of mass of a uniform ladder resting against a wall would be at its midpoint, horizontally from the wall. This is significant when considering the ladder's tendency to rotate under the influence of gravity, as the center of mass determines a pivotal aspect of the ladder's torque around its base.

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Most popular questions from this chapter

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