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The band gap of silicon is \(1.14 \mathrm{eV}\). \((a)\) For what range of wavelengths will silicon be transparent? (See Example \(40-14 .)\) In what region of the electromagnetic spectrum does this transparent range begin? (b) If window glass is transparent for all visible wavelengths, what is the minimum possible band gap value for glass (assume \(\lambda=450 \mathrm{nm}\) to \(750 \mathrm{nm}\) )? [Hint: If the photon has less energy than the band gap, the photon will pass through the solid without being absorbed.

Short Answer

Expert verified
Silicon is transparent above 1090 nm, in the infrared region. Glass needs a band gap of at least 2.75 eV.

Step by step solution

01

Understand the Photon Energy and Wavelength Relationship

The energy of a photon is related to its wavelength by the formula \( E = \frac{hc}{\lambda} \), where \( E \) is energy, \( h \) is Planck's constant (\(6.626 \times 10^{-34} \) Js), \( c \) is the speed of light (\(3 \times 10^8 \) m/s), and \( \lambda \) is wavelength. If the photon's energy is less than the band gap energy, it doesn't get absorbed.
02

Calculate Maximum Transparent Wavelength for Silicon

Given that the band gap of silicon equals \(1.14\, \mathrm{eV}\), we convert this to energy in joules: \(1.14\, \mathrm{eV} = 1.14 \times 1.602 \times 10^{-19} \) J. Substitute into the formula: \( E = \frac{hc}{\lambda} \) to solve for \( \lambda \), which is \( \lambda = \frac{hc}{E} \). This calculates the longest wavelength for which silicon is opaque (when photon energy equals band gap).
03

Solve for Wavelength

Using \( h = 6.626 \times 10^{-34} \), \( c = 3 \times 10^8 \), and \( E = 1.14 \times 1.602 \times 10^{-19} \), \( \lambda = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{1.14 \times 1.602 \times 10^{-19}} \approx 1.09 \times 10^{-6} \) m, or \( 1090 \) nm.
04

Identify Region of Electromagnetic Spectrum

Wavelengths greater than \(1090 \) nm where silicon remains transparent fall in the infrared region of the spectrum.
05

Determine Minimum Band Gap of Durable Materials like Glass

For glass to be transparent to visible light (wavelengths 450 nm to 750 nm), the band gap should at least be as large as the energy of the shortest wavelength light (450 nm). Using \( \lambda = 450 \) nm, solve for energy: \( E = \frac{hc}{\lambda} \) using \(450 \times 10^{-9} \) m:\[ E = \frac{(6.626 \times 10^{-34})(3 \times 10^8)}{450 \times 10^{-9}} \].
06

Convert and Interpret Energy

Resulting energy in joules needs conversion: \( E \approx 4.41 \times 10^{-19} \) J, corresponding to \( \frac{4.41 \times 10^{-19}}{1.602 \times 10^{-19}} = 2.75 \) eV. Thus, glass should have at least a \(2.75\, \mathrm{eV}\) band gap to be transparent in this range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Photon Energy and Wavelength Relationship
Understanding the connection between a photon's energy and its wavelength is crucial in the study of optics. The energy of a photon, denoted as \( E \), is calculated using the equation \( E = \frac{hc}{\lambda} \). Here, \( h \) represents Planck's constant \( (6.626 \times 10^{-34} \text{ Js}) \), \( c \) is the speed of light \( (3 \times 10^8 \text{ m/s}) \), and \( \lambda \) is the wavelength of the photon.
This formula reveals a fundamental relationship: energy and wavelength are inversely proportional. This means that shorter wavelengths have higher energy and vice versa. For instance, ultraviolet light has shorter wavelengths and thus, more energy compared to infrared light.
When photon energy is less than a material's band gap energy, the photon isn't absorbed, allowing it to pass through. This principle explains why certain materials are transparent to specific wavelengths.
Silicon Transparency
Silicon, a widely used semiconductor material, has a band gap of \( 1.14 \, \mathrm{eV} \). This implies that photons with energy lower than \( 1.14 \, \mathrm{eV} \) will not be absorbed by silicon, making it transparent to those photons.
To find out which wavelengths silicon is transparent to, we need to calculate the maximum wavelength of light with an energy of \( 1.14 \, \mathrm{eV} \). Using the formula \( \lambda = \frac{hc}{E} \), where energy \( E\) is first converted to joules, the maximum wavelength is determined to be approximately \( 1090 \) nm.
Thus, silicon remains transparent at wavelengths greater than \( 1090 \) nm, which are primarily in the infrared region of the electromagnetic spectrum. This property is significant for infrared applications where unobstructed light passage through silicon is required.
Electromagnetic Spectrum Regions
The electromagnetic spectrum consists of various regions distinguished by their wavelengths and frequencies. These regions include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays.
Each region possesses distinct characteristics:
  • Radio Waves: Longest wavelengths, used for communication.
  • Microwaves: Used in cooking and radar technology.
  • Infrared: Experienced as heat, often used in night-vision devices.
  • Visible Light: The spectrum detectable by the human eye, ranges from about 400 nm to 700 nm.
  • Ultraviolet: Beyond visible light, with applications in sterilization and fluorescent lighting.
  • X-rays: Used in medical imaging.
  • Gamma Rays: Shortest wavelength, produced by radioactive materials.
Wavelengths longer than \( 1090 \) nm fall into the infrared region, where silicon remains transparent, highlighting the importance of understanding different electromagnetic spectrum regions for technological applications.
Visible Light Transparency
Transparency in materials, like window glass, depends on their band gap in relation to visible light. Visible light spans wavelengths from roughly \( 400 \text{ nm} \) to \( 700 \text{ nm} \).
For a material to be transparent throughout this visible range, it must have a band gap that exceeds the energy of the shortest visible wavelengths, which is around \( 450 \text{ nm} \). Solving for this wavelength gives a band gap of at least \( 2.75 \, \mathrm{eV} \).
When glass exhibits a band gap greater than \( 2.75 \, \mathrm{eV} \), it allows visible light to pass without absorption, resulting in transparency. This is why glass is commonly used in windows and optical instruments, as it transmits visible light effectively, enabling clear vision and permitting natural illumination.

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