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When EM radiation is incident on diamond, it is found that light with wavelengths shorter than \(226 \mathrm{nm}\) will cause the diamond to conduct. What is the energy gap between the valence band and the conduction band for diamond?

Short Answer

Expert verified
The energy gap is approximately 5.5 eV.

Step by step solution

01

Identify the Given Information

We know that the diamond conducts when light has a wavelength shorter than \(226 \mathrm{nm}\). This wavelength corresponds to the threshold energy required for conduction.
02

Convert Wavelength to Frequency

First, convert the given wavelength into frequency using the speed of light \(c = 3 \times 10^8 \mathrm{m/s}\) and the formula \(c = \lambda \times u\), where \(\lambda\) is the wavelength and \(u\) is the frequency. Rearrange to find \(u = \frac{c}{\lambda}\), where \(\lambda = 226 \times 10^{-9} \mathrm{m}\).
03

Calculate the Photon Energy

Use the formula for energy \(E = h \times u\), where \(h = 6.626 \times 10^{-34} \mathrm{Js}\) is Planck's constant. Substitute \(u\) from the previous step to find the energy \(E\) of the photons with wavelength \(226 \mathrm{nm}\).
04

Express Energy in Electron Volts

Convert the energy obtained from Joules to electron volts (eV) using the conversion factor \(1 \mathrm{eV} = 1.602 \times 10^{-19} \mathrm{J}\). This final value will represent the energy gap between the valence band and the conduction band for diamond.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Band Theory
In the context of semiconductors, band theory is an essential framework used to understand how electricity is conducted. Unlike metals, semiconductors have distinct energy bands: the valence band and the conduction band.
  • The valence band is the highest range of electron energies where electrons are typically present at absolute zero temperature.
  • The conduction band is above the valence band and is typically empty at absolute zero.
  • The energy gap, or band gap, is the energy difference between these two bands.
To turn a semiconductor into a conductor, electrons must gain enough energy to jump from the valence band to the conduction band, making them free to move and thus conduct electricity.
In diamond, which is an insulator under normal conditions, light can provide the necessary energy to boost electrons across this energy gap, particularly if the light's photon energy matches or exceeds the band gap.
Photon Energy
Photons are fundamental particles of light that carry energy, which depends on their frequency. The relationship between the energy of a photon and its frequency is given by Planck's equation: \[E = h \times u\]
  • The symbol \(E\) represents the photon energy.
  • The symbol \(h\) stands for Planck's constant, valued at approximately \(6.626 \times 10^{-34} \text{Js}\).
  • The symbol \(u\) is the frequency of the photon.
By using this equation, you can determine the energy carried by photons of specific light. For diamond, light with shorter wavelengths such as 226 nm has photons with just enough energy. When these photons strike the diamond, they can excite electrons across the gap, leading to conduction.
Therefore, knowing the energy of photons helps us understand and calculate the minimum threshold energy needed to excite electrons in materials like diamond.
Wavelength to Frequency Conversion
The conversion of wavelength to frequency is a crucial step in evaluating the energy of photons impacting a material. Light's speed is always constant in a vacuum and is given by \[c = \lambda \times u\]
  • \(c\) is the speed of light \((3 \times 10^8 \text{m/s})\).
  • \(\lambda\) represents the wavelength.
  • \(u\) represents the frequency.
By rearranging the formula, you can express frequency as\[u = \frac{c}{\lambda}\]This equation is used to convert the wavelength of the light into its frequency. For example, with a wavelength of 226 nm, the frequency can be calculated to find out how much energy the light carries. This conversion forms the basis for calculating photon energy, as detailed in previous sections. Understanding these conversions enables us to precisely determine whether a material will absorb or conduct the energy provided by incoming photons.

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Most popular questions from this chapter

(II) Common salt, NaCl, has a density of 2.165 \(\mathrm{g} / \mathrm{cm}^{3} .\) The molecular weight of \(\mathrm{NaCl}\) is \(58.44 .\) Estimate the distance between nearest neighbor \(\mathrm{Na}\) and \(\mathrm{Cl}\) ions. \([\)Hint: Each ion can be considered to have one "cube" or "cell" of side \(s\) (our unknown) extending out from it.

Show that the probability for the state at the Fermi energy being occupied is exactly \(\frac{1}{2}\), independent of temperature.

(II) Estimate the energy associated with the repulsion of the electron shells of a lithium fluoride (LiF) molecule. The ionization energy of lithium is \(5.39 \mathrm{eV},\) and it takes 3.41 \(\mathrm{eV}\) to remove the extra electron from an \(\mathrm{F}^{-}\) ion. The bond length is \(0.156 \mathrm{nm},\) and the binding energy of LiF is 5.95 \(\mathrm{eV} .\)

(III) A \(120-\mathrm{V}\) rms \(60-\mathrm{Hz}\) voltage is to be rectified with a full-wave rectifier as in Fig. \(40,\) where \(R=28 \mathrm{k} \Omega\) , and \(C=35 \mu \mathrm{F}\) (a) Make a rough estimate of the average current. \((b)\) What happens if \(C=0.10 \mu \mathrm{F} ?\)

The band gap of silicon is \(1.14 \mathrm{eV}\). \((a)\) For what range of wavelengths will silicon be transparent? (See Example \(40-14 .)\) In what region of the electromagnetic spectrum does this transparent range begin? (b) If window glass is transparent for all visible wavelengths, what is the minimum possible band gap value for glass (assume \(\lambda=450 \mathrm{nm}\) to \(750 \mathrm{nm}\) )? [Hint: If the photon has less energy than the band gap, the photon will pass through the solid without being absorbed.

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