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For an arsenic donor atom in a doped silicon semiconductor, assume that the "extra" electron moves in a Bohr orbit about the arsenic ion. For this electron in the ground state, take into account the dielectric constant \(K=12\) of the Si lattice (which represents the weakening of the Coulomb force due to all the other atoms or ions in the lattice), and estimate \((a)\) the binding energy, and \((b)\) the orbit radius for this extra electron. [Hint: Substitute \(\epsilon=K \epsilon_{0}\) in Coulomb's law; see Section \(\left.24-5 .\right]\)

Short Answer

Expert verified
The orbit radius is 12 times the Bohr radius; binding energy is approximately 0.094 eV.

Step by step solution

01

Understand the Problem

We are tasked with finding the binding energy and orbit radius of an electron bound to an arsenic donor in silicon. This involves modifications to the Bohr model for hydrogen, accounting for the silicon lattice's dielectric constant, which impacts the Coulomb force.
02

Modify the Coulomb's Law

The Coulomb's law force with dielectric constant is given by \( F = \frac{e^2}{4\pi K \epsilon_0 r^2} \) where \( K = 12 \). This modifies the usual constant in the Bohr model for hydrogen, affecting binding energy and orbit radius calculations.
03

Calculate the Modified Bohr Radius

The Bohr radius for the hydrogen atom is given by \( a_0 = \frac{4\pi \epsilon_0 \hbar^2}{m_e e^2} \). In silicon, the radius \( a_Si \) becomes \( a_{Si} = K \times a_0 \). Substitute \( K = 12 \) to find \( a_{Si} = 12 \times a_0 \).
04

Calculate the Binding Energy

The binding energy for a hydrogen atom is approximately 13.6 eV. In a silicon lattice, the energy is multiplied by \( \frac{1}{K^2} \), thus \( E_{Si} = \frac{13.6}{12^2} \) eV. Calculate \( E_{Si} \) to find the binding energy for the electron in silicon.
05

Compute and Conclude

With \( a_{Si} = 12 \times a_0 \) and \( E_{Si} = \frac{13.6}{144} \), compute the exact values to estimate the orbit radius and binding energy of the electron.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bohr Model
The Bohr Model is a fundamental theory which explains the behavior of electrons in atoms. It depicts the atom as a small nucleus surrounded by electrons in circular orbits. For our problem with a doped silicon semiconductor, we imagine an extra electron orbiting an arsenic ion. This approach involves tweaks to the traditional Bohr model used in hydrogen atoms. The original model relies on the Coulomb force between the electron and the nucleus, predicting quantized orbits where electrons can reside.
In this scenario, we adapt the model to consider influences from the silicon lattice, which impacts forces acting on the electron. The presence of arsenic, a donor atom, introduces an extra electron in specific orbit levels defined by the adjusted Bohr formula. This model helps us determine essential properties like the orbit radius and binding energy of the electron in the doped semiconductor. The Bohr Model's simplicity provides valuable insights into the basic structure and behavior of atoms, even modified as seen here.
Dielectric Constant
A Dielectric Constant is a measure of a substance's ability to insulate charges from each other. In our case, the silicon lattice is given a dielectric constant of 12. This factor remarkably influences the calculations of forces between charged particles. When dealing with semiconductors, the dielectric constant represents how effectively the material reduces the Coulomb force between charged entities due to its internal structure.
The dielectric constant in this calculation is crucial as it modifies Coulomb's law, altering the force and energy levels of an electron in a silicon environment. By using a higher dielectric constant, the internal interactions are weaker, reflecting on the energy and radius values obtained for the electron's orbit. It's well noted that adjusting for this constant is typical when working with semiconductors since these materials have quite the different electrical properties compared to free space.
Coulomb's Law
Coulomb's Law describes the force between two charged bodies as being proportional to the product of their charges, and inversely proportional to the square of the distance between them. For our semiconductor problem, Coulomb's Law appears altered to include the dielectric constant, written as:\[ F = \frac{e^2}{4\pi K \epsilon_0 r^2} \] where \( K \) is the dielectric constant reducing the effective force felt by the electron.
This modified form impacts both the orbit radius and binding energy calculations. The dielectric constant, which arises from silicon's properties, adjusts the forces involved, showcasing how an insulating environment dampens interactions. In essence, through the modified Coulomb's law, we gain insights into the inner workings of the semiconductor and how the arsenic doping influences electron dynamics.
Binding Energy
The Binding Energy is the energy required to remove an electron from its orbit around an atom or ion. It gives us an idea of how tightly an electron is held. In the case of a silicon semiconductor with arsenic doping, the binding energy for an electron is notably different from that in a regular hydrogen atom.
For hydrogen, the binding energy is around 13.6 eV. However, in silicon, due to the dielectric constant, this value gets modified to:\[ E_{Si} = \frac{13.6}{K^2} \]where \( K = 12 \). Performing this calculation, the resulting binding energy is significantly reduced, indicating that the electron in silicon requires less energy to be freed compared to hydrogen. This reduced energy is vital for understanding conductivity in doped semiconductors, where easier movement of electrons facilitates electrical conduction.
Orbit Radius
In examining the Orbit Radius, we look at the distance at which the extra electron orbits the arsenic ion. This radius differs substantially for silicon compared to hydrogen due to material properties like the dielectric constant.
The formula for the orbit radius in a hydrogen atom's ground state is the Bohr radius \( a_0 \). When adjusted for silicon’s properties, this becomes:\[ a_{Si} = K \times a_0 \]where \( K = 12 \) in our case. This makes the orbit radius larger in silicon than in hydrogen, demonstrating how electron orbits are more spread out in a semiconductor lattice. Understanding the changed orbit radii informs us about how semiconductors behave with added impurity atoms and also reflects the ease of electron flow within their frameworks.

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Most popular questions from this chapter

[The Problems in this Section are ranked I, II, or III according to estimated difficulty, with (I) Problems being easiest. Level (III) Problems are meant mainly as a challenge for the best students, for "extra credit." The Problems are arranged by Sections, meaning that the reader should have read up to and including that Section, but this Chapter also has a group of General Problems that are not arranged by Section and not ranked. 1 to 3 Molecular Bonds (I) Estimate the binding energy of a KCl molecule by calcu-lating the electrostatic potential energy when the \(\mathrm{K}^{+}\) and \(\mathrm{Cl}^{-}\) ions are at their stable separation of 0.28 \(\mathrm{nm} .\) Assume each has a charge of magnitude 1.0\(e .\)

(I) Calculate the longest-wavelength photon that can cause an electron in silicon \(\left(E_{g}=1.14 \mathrm{eV}\right)\) to jump from the valence band to the conduction band.

Do we need to consider quantum effects for everyday rotating objects? Estimate the differences between rotational energy levels for a spinning baton compared to the energy of the baton. Assume the baton consists of a uniform \(32-\mathrm{cm}-\) long bar with a mass of \(260 \mathrm{~g}\) and two small end masses, each of mass \(380 \mathrm{~g}\), and that it rotates at \(1.6 \mathrm{rev} / \mathrm{s}\) about the bar's center.

The band gap of silicon is \(1.14 \mathrm{eV}\). \((a)\) For what range of wavelengths will silicon be transparent? (See Example \(40-14 .)\) In what region of the electromagnetic spectrum does this transparent range begin? (b) If window glass is transparent for all visible wavelengths, what is the minimum possible band gap value for glass (assume \(\lambda=450 \mathrm{nm}\) to \(750 \mathrm{nm}\) )? [Hint: If the photon has less energy than the band gap, the photon will pass through the solid without being absorbed.

Calculate the Fermi energy and Fermi speed for sodium, which has a density of \(0.97 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\) and has one conduction electron per atom.

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