/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 A ship is floating on a lake. It... [FREE SOLUTION] | 91Ó°ÊÓ

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A ship is floating on a lake. Its hold is the interior space beneath its deck; the hold is empty and is open to the atmosphere. The hull has a hole in it, which is below the water line, so water leaks into the hold. The effective area of the hole is \(8.0 \times 10^{-3} \mathrm{m}^{2}\) and is located 2.0 \(\mathrm{m}\) beneath the surface of the lake. What volume of water per second leaks into the ship?

Short Answer

Expert verified
Approximately 0.050 m³/s of water leaks into the ship.

Step by step solution

01

Understanding the Problem

We need to calculate the volume of water entering through a hole in a ship's hull per second. The problem involves fluid dynamics, specifically the calculation of flow based on the hole size and its depth underwater.
02

Identify Known Quantities

The effective area of the hole, \(A = 8.0 \times 10^{-3} \text{ m}^2\). The depth below the water surface is \(h = 2.0 \text{ m}\). The density of water \(\rho\) is approximately \(1000 \text{ kg/m}^3\), and gravitational acceleration \(g = 9.8 \text{ m/s}^2\).
03

Using Bernoulli's Principle

Apply Bernoulli's equation to find the velocity of water entering the hole. The equation simplifies to \(v = \sqrt{2gh}\), where \(v\) is the velocity of water through the hole.
04

Calculate the Velocity

Using the formula \(v = \sqrt{2gh}\), substitute \(g = 9.8 \text{ m/s}^2\) and \(h = 2.0 \text{ m}\). So, \(v = \sqrt{2 \times 9.8 \times 2.0} = \sqrt{39.2} \approx 6.26 \text{ m/s}\).
05

Calculate the Volume Flow Rate

The volume flow rate \(Q\) is given by \(Q = A \cdot v\). Substituting \(A = 8.0 \times 10^{-3} \text{ m}^2\) and \(v = 6.26 \text{ m/s}\), we have \(Q = 8.0 \times 10^{-3} \cdot 6.26 \approx 0.050 \text{ m}^3/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's Principle
Bernoulli's Principle is a fundamental concept in fluid dynamics. It describes the behavior of a fluid moving along a streamline. The principle can be expressed mathematically by Bernoulli's equation, which combines the pressure, velocity, and height of the fluid at different points. When applied to fluids entering a hole or opening, this principle allows us to determine the velocity of the fluid as it passes through the opening.

In our problem, we use Bernoulli’s equation to derive the velocity of water flowing through a hole in the ship's hull. Since the ship's hold is open to the atmosphere and the hole is below the waterline, we can assume that the pressure difference drives the flow. We focus on simplifying the equation to get the velocity:
  • Bernoulli's equation: \[ P_1 + \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh_2 \]
  • Simplified for this scenario: \[ v = \sqrt{2gh} \]
Only gravitational forces and the opening's depth are considered to find the velocity. This simplification makes Bernoulli’s principle extremely handy for many practical applications in engineering and physics.
Volume Flow Rate
Volume flow rate describes how much fluid passes through an area in a given time. It is often symbolized by the letter \(Q\) and is measured in cubic meters per second (\(\text{m}^3/\text{s}\)). The volume flow rate can be calculated if we know the velocity of the fluid flow and the cross-sectional area through which it flows.

In the exercise, we calculate the volume flow rate of water entering the ship's hold using the formula:
  • \[ Q = A \cdot v \]
  • \(A\) is the area of the hole \(= 8.0 \times 10^{-3} \text{ m}^2\)
  • \(v\) is the velocity of water through the hole, approximately \(6.26 \text{ m/s}\)
By multiplying these two values, we find that \(Q\) is approximately \(0.050 \text{ m}^3/s\), explaining how fast water accumulates in the ship due to the hole.
Gravitational Acceleration
Gravitational acceleration is the acceleration due to Earth's gravity, denoted as \(g\), and is approximately \(9.8 \text{ m/s}^2\). This constant plays a crucial role in determining the behavior of objects in free fall and, importantly, affects the behavior of fluids.

In the context of our exercise, gravitational acceleration is a key factor influencing the velocity of water entering the ship through the hole. Bernoulli's equation simplified for this problem involves gravitational acceleration because the force driving the water flow comes from the weight of the water above the hole.
  • The potential energy per unit volume due to gravity is calculated as \( \rho gh \), where \(\rho\) is the water's density.
  • As water flows from a higher to a lower point (from the lake surface to the entrance of the hole), the potential energy converts into kinetic energy, giving the water velocity.
Understanding gravitational acceleration helps comprehend why fluids speed up when flowing downhill or entering openings below the waterline.

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Most popular questions from this chapter

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