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Water is circulating through a closed system of pipes in a two-floor apartment. On the first floor, the water has a gauge pressure of \(3.4 \times 10^{5} \mathrm{Pa}\) and a speed of 2.1 \(\mathrm{m} / \mathrm{s}\) . However, on the second floor, which is 4.0 \(\mathrm{m}\) higher, the speed of the water is 3.7 \(\mathrm{m} / \mathrm{s}\) . The speeds are different because the pipe diameters are different. What is the gauge pressure of the water on the second floor?

Short Answer

Expert verified
The gauge pressure on the second floor is \(3.0 \times 10^5\) Pa.

Step by step solution

01

Understand Bernoulli’s Equation

Bernoulli's equation is given by: \(P_1 + \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho gh_2\). This equation can be utilized to relate the pressures, velocities, and heights of a fluid at two points within a streamline.
02

Assign Values for the First Floor

We know from the problem statement: \(P_1 = 3.4 \times 10^{5} \) Pa, \(v_1 = 2.1\) m/s, and \(h_1 = 0\) m.
03

Assign Values for the Second Floor

For the second floor, we know: \(v_2 = 3.7\) m/s and \(h_2 = 4.0\) m. We need to find the pressure \(P_2\).
04

Assume Constant Density

The density \(\rho\) of water is approximately \(1000\, \mathrm{kg/m^3}\) and is constant throughout the scenario.
05

Rearrange Bernoulli's Equation

Rearrange the equation to solve for \(P_2\): \(P_2 = P_1 + \frac{1}{2} \rho v_1^2 - \frac{1}{2} \rho v_2^2 + \rho g(h_1 - h_2)\).
06

Substitute Known Values into the Equation

Substitute the known values into the equation: \(P_2 = 3.4 \times 10^{5} + \frac{1}{2}(1000)(2.1)^2 - \frac{1}{2}(1000)(3.7)^2 + (1000)(9.8)(0 - 4)\).
07

Calculate Pressure Difference

Calculate the difference in the kinetic and potential energy terms: \(\Delta KE = \frac{1}{2}(1000 \times (2.1)^2 - 3.7^2)\) and \(\Delta PE = (1000) \times (9.8) \times (0 - 4)\).
08

Solve for Gauge Pressure on Second Floor

Calculate \(P_2\) from the expression: \(P_2 = 3.4 \times 10^{5} - 5320 - 39200\), which simplifies to \(P_2 = 3.4 \times 10^{5} - 44520\). Therefore, \(P_2 = 3.0 \times 10^{5}\) Pa.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Dynamics
Fluid dynamics is the study of how fluids move and behave under various conditions. It is a branch of physics concerned with the motion and flow of liquids and gases. This field helps us understand how fluids interact with their surroundings, change directions, and exert forces on surfaces they flow over.

A critical concept in fluid dynamics is the idea of a streamline, which is a path followed by the particles of a fluid. In the given problem, Bernoulli's equation applies to the flow of water in a closed system of pipes within an apartment. By analyzing the speeds and pressures at different points along the streamline, we can predict changes in the flow behavior based on Bernoulli's principles.
  • Steady Flow: The properties of the fluid (e.g., speed, pressure) do not change over time at a given location.
  • Incompressible Fluid: The density of the fluid remains constant, as is typically the case with liquids like water.
  • Non-viscous Flow: The fluid has no internal resistance to flow, simplifying calculations.
Understanding these conditions helps us apply Bernoulli's equation effectively to solve problems involving fluid dynamics.
Gauge Pressure
Gauge pressure is used to measure the pressure of a fluid above atmospheric pressure. It is different from absolute pressure, which includes the atmospheric pressure. Gauge pressure is particularly useful in scenarios like plumbing systems, where it is crucial to know the pressure difference compared to the ambient environment.

In this exercise, we start with the known gauge pressure on the first floor and seek the gauge pressure on the second floor. This involves applying Bernoulli's equation to account for differences in velocity and height as the water moves from one point to another.

When calculating gauge pressure, it's important to remember:
  • Gauge pressure is expressed as \(P_g = P - P_{atm} \), where \(P\) is the total pressure, and \(P_{atm}\) is the atmospheric pressure.
  • In our problem, since both gauge pressures are measured in the same system, atmospheric pressure cancels out, simplifying the use of Bernoulli's equation.
  • Knowing gauge pressure helps determine whether a fluid can move efficiently through a pipeline without the risk of leaks or bursts.
Potential Energy in Fluids
Potential energy in fluids refers to the energy stored within a fluid due to its position in a gravitational field. In the context of Bernoulli's equation, potential energy is associated with the height of the fluid flow.

For our problem, the potential energy change is evaluated as the water rises from the first to the second floor. This energy change is represented by the term \[ \rho gh \] in Bernoulli's equation, where \( \rho \) is the fluid's density, \( g \) is the acceleration due to gravity, and \( h \) is the height.

Key aspects of potential energy in fluids include:
  • Potential energy increases with an increase in fluid height. More work is done against gravity to move the fluid upward.
  • As the fluid rises, its mechanical energy distribution changes; kinetic energy might decrease as potential energy increases, as seen in this problem.
  • In Bernoulli's principle, changes in potential energy are balanced with changes in pressure and kinetic energy to maintain energy conservation along a streamline.
Potential energy changes are essential for understanding fluid systems, especially when designing structures like water towers or adjusting for elevation changes in piping systems.

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Most popular questions from this chapter

The drawing shows a hydraulic system used with disc brakes. The force \(\overrightarrow{\mathbf{F}}\) is applied perpendicularly to the brake pedal. The pedal rotates about the axis shown in the drawing and causes a force to be applied perpendicularly to the input piston (radius \(=9.50 \times 10^{-3} \mathrm{m} )\) in the master cylinder. The resulting pressure is transmitted by the brake fluid to the output plungers (radii \(=1.90 \times 10^{-2} \mathrm{m}\) ), which are covered with the brake linings. The linings are pressed against both sides of a disc attached to the rotating wheel. Suppose that the magnitude of \(\overrightarrow{\mathbf{F}}\) is 9.00 \(\mathrm{N}\) . Assume that the input piston and the output plungers are at the same vertical level, and find the force applied to each side of the rotating disc.

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Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.020 m. Water enters the hydrant through an underground pipe of radius 0.080 m. In this pipe the water has a speed of 3.0 m/s. (a) How many kilograms of water are poured onto a fire in one hour by all three hoses? (b) Find the water speed in each hose.

A suitcase (mass \(m=16 \mathrm{kg} )\) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50 \(\mathrm{m} \times 0.15 \mathrm{m}\) . The elevator is moving upward with an acceleration of magnitude 1.5 \(\mathrm{m} / \mathrm{s}^{2}\) . What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

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