/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Two identical containers are ope... [FREE SOLUTION] | 91Ó°ÊÓ

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Two identical containers are open at the top and are connected at the bottom via a tube of negligible volume and a valve that is closed. Both containers are filled initially to the same height of 1.00 m, one with water, the other with mercury, as the drawing indicates. The valve is then opened. Water and mercury are immiscible. Determine the fluid level in the left container when equilibrium is reestablished.

Short Answer

Expert verified
The fluid level in the left container is 0.22 m.

Step by step solution

01

Understanding the System

This problem involves two containers connected by a tube at the bottom filled with different fluids: water and mercury. Since the fluids are immiscible, they do not mix. The containers will reach equilibrium when the pressures at the bottom are equal.
02

Initial Conditions and Equilibrium

Initially, both fluids are at the same height of 1.00 m. We need to find the new heights of the fluids when equilibrium is reached. We'll use the principle that the pressure exerted by each column of fluid must be the same at the bottom due to the open valve.
03

Calculate Pressure Exerted by Water

The pressure exerted by the water column is given by the equation \( P_{water} = \rho_{water} \cdot g \cdot h_{water} \), where \( \rho_{water} = 1000 \, \text{kg/m}^3 \), \( g = 9.81 \, \text{m/s}^2 \), and \( h_{water} \) is the height of the water column.
04

Calculate Pressure Exerted by Mercury

Similarly, the pressure exerted by the mercury column is given by \( P_{mercury} = \rho_{mercury} \cdot g \cdot h_{mercury} \), where \( \rho_{mercury} = 13600 \, \text{kg/m}^3 \) and \( h_{mercury} \) is the height of the mercury column.
05

Equalize Pressures

Since the system is in equilibrium, set the pressures equal: \( \rho_{water} \cdot g \cdot h_{water} = \rho_{mercury} \cdot g \cdot h_{mercury} \). Simplifying, \( h_{water} \cdot \rho_{water} = h_{mercury} \cdot \rho_{mercury} \).
06

Solve the Equation for Heights

Given that each container was initially filled to a height of 1.00 m, but with different fluids, set \( h_{water} = 1.00 - x \) and \( h_{mercury} = 1.00 + x \). Solve the equation \( (1.00 - x) \cdot 1000 = (1.00 + x) \cdot 13600 \) to find \( x \).
07

Final Calculation

Rearrange the equation to isolate \( x \): \( 1.00 - x = \frac{13600}{1000} (1.00 + x) \). Solving gives \( x = \frac{13600 - 1000}{13600 + 1000} \), which is approximately \( x = 0.78044 \). This means the water level decreases by about 0.78 m.
08

Determine Fluid Level in Left Container

The fluid level in the left container (water) when equilibrium is reestablished is \( 1.00 - 0.78 = 0.22 \text{ m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure Calculation
Pressure in a fluid is the force exerted per unit area within the fluid. It is essential to understand pressure calculation in fluid systems to analyze equilibrium and stability. In this context, pressure depends on several parameters:
  • Density of the fluid (\( \rho \))
  • Gravitational acceleration (\( g \))
  • Height of the fluid column (\( h \))
The pressure caused by a column of fluid at any depth is calculated by the formula:\[P = \rho \cdot g \cdot h\]In the exercise, each container exerts pressure at its bottom based on the height and density of its respective fluid. Matching the pressures establishes equilibrium, allowing us to find the new fluid levels.
Immiscible Fluids
Immiscible fluids, like water and mercury, do not mix, even when placed in direct contact with each other. This characteristic arises because of differences in their molecular structures and properties such as polarity and density.
When immiscible fluids are placed in containers that are connected, they form separate layers based on density. The denser fluid (mercury in this case) settles at the bottom. This characteristic is essential for solving equilibrium problems involving immiscible fluids, where the pressure from each fluid must be balanced independently. When the problem states that water and mercury are immiscible, it implies that these two fluids will each retain their own distinct layers and characteristics even in a connected double-container system.
Hydrostatics
Hydrostatics is the branch of physics that studies fluids at rest and the forces and pressure they exert. A fundamental principle of hydrostatics is that fluid at rest in a container applies equal pressure in all directions at a given depth.
In the exercise, the principle of hydrostatics is applied to achieve equilibrium. When the valve is open, the pressure at the bottom of both containers needs to balance. Hence, the height adjustment of fluids happens based on their densities, showing the core concept of equalizing pressure in connected containers with immiscible fluids.
  • Pressure is only due to the fluid column above.
  • Fluids self adjust to equalize pressure at the connecting point (valve).
Understanding hydrostatics helps predict how fluids behave when the system conditions, like container height, change.
Fluid Dynamics
Fluid dynamics refers to the study of fluids in motion. In this case, dynamics influences the initial movement towards equilibrium. While the ultimate goal is achieving a static state (or no movement), understanding fluid dynamics considerations can help contextualize the system behavior just after the valve is opened.
Once the valve opens, the difference in pressure causes fluid movement, but as the fluid reaches new heights, it gradually comes to rest, reflecting a balance of forces. During the stabilization process:
  • High-pressure fluid flows to lower-pressure areas.
  • The change in fluid levels continues until pressures equalize at the bottoms of both containers.
This interaction showcases how initial fluid dynamics transitions into hydrostatic equilibrium, ultimately determining the new, stable fluid levels.

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