/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 The vertical surface of a reserv... [FREE SOLUTION] | 91Ó°ÊÓ

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The vertical surface of a reservoir dam that is in contact with the water is 120 m wide and 12 m high. The air pressure is one atmosphere. Find the magnitude of the total force acting on this surface in a completely filled reservoir. (Hint: The pressure varies linearly with depth, so you must use an average pressure.)

Short Answer

Expert verified
The total force on the dam is 84,710,400 N.

Step by step solution

01

Understanding the Problem

We need to calculate the total force exerted by water against a reservoir dam. The dam is 120 m wide and 12 m high. The water pressure varies with depth, increasing linearly from 0 at the surface to a maximum value at the bottom. We will calculate the force by considering the average water pressure across the height of the dam.
02

Determining Water Pressure at Depth

Water pressure increases with depth according to the formula \( p = \rho g h \), where \( \rho \) is the density of water (approximately 1000 kg/m³), \( g \) is the acceleration due to gravity (9.81 m/s²), and \( h \) is the depth in meters. Since our height varies from 0 to 12 m, the pressure at the bottom of the dam is \( p_{bottom} = 1000 \times 9.81 \times 12 \).
03

Calculating Average Water Pressure

The pressure varies linearly with depth, so the average pressure \( p_{avg} \) over the height of the dam is half of the pressure at the bottom: \( p_{avg} = \frac{1}{2} \times p_{bottom} = \frac{1}{2} \times 1000 \times 9.81 \times 12 \).
04

Calculating the Total Force

The total force \( F \) is given by \( F = p_{avg} \times A \), where \( A \) is the area of the dam in contact with the water, which is \( 120 \times 12 \). Using the average pressure calculated earlier, we find \( F = \frac{1}{2} \times 1000 \times 9.81 \times 12 \times 120 \times 12 \).
05

Final Calculation and Solution

Perform the calculations: \( p_{avg} = \frac{1}{2} \times 1000 \times 9.81 \times 12 = 58860 \) Pa. The force is therefore \( F = 58860 \times (120 \times 12) = 58860 \times 1440 = 84710400 \) N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reservoir Dam
A reservoir dam is a substantial structure that holds back water in a reservoir. Its primary function is to manage water flow for purposes such as irrigation, flood prevention, and water storage. Constructed to withstand significant pressures and forces, reservoir dams must be designed using engineering principles that account for the forces exerted by the water they retain.

In this context, the dam's wall resists the water pressure which increases with depth, highlighting the importance of accurate force estimation in its design and safety assessment. Engineers must calculate the pressure exerted by the water to ensure the dam's material and construction can withstand these forces without risk of failure. In this exercise, we focus on understanding how to calculate the forces acting against a dam due to hydrostatic pressure.
Water Pressure Calculation
Water pressure in a reservoir increases linearly with depth and is determined using the formula: \( p = \rho g h \), where:
  • \( \rho \) is the density of water, usually 1000 kg/m³.
  • \( g \) is the acceleration due to gravity, roughly 9.81 m/s².
  • \( h \) is the depth in meters.
This formula allows us to estimate the pressure at any given depth beneath the water surface.

In a practical sense, calculating the water pressure at a certain depth lets engineers predict the total force exerted on structures submerged in, or holding back, water. Knowing that the pressure at the base of a dam is greatest helps inform the structural design to prevent failures. This linear increase with depth is crucial in deciding the thickness and materials needed for dam construction.
Force on a Dam
The force exerted by water on a dam is calculated by considering the average pressure. Since water pressure increases linearly with depth, the average pressure can be found by taking half of the pressure at the maximum depth. The equation for the force is: \( F = p_{avg} \times A \), where:
  • \( F \) is the total force.
  • \( p_{avg} \) is the average pressure, calculated as \( \frac{1}{2} \times p_{bottom} \).
  • \( A \) is the area of the dam in contact with the water.
In this problem, the height of the dam is 12 m and the width is 120 m. Thus, the average pressure and the total force are calculated using these dimensions. This allows us to determine how much force the dam must resist to ensure its structural integrity and safety.

Understanding this concept emphasizes the importance of rigorous engineering evaluations required to design safe water-retaining structures.
Pressure Variation with Depth
Water pressure variation with depth is a key concept in understanding how forces are distributed against a submerged structure like a dam. Hydrostatic pressure is not constant; instead, it grows linearly as depth increases because more water weight lies above deeper points. At 0 m depth (the surface), pressure is minimal, most often atmospheric. At 12 m depth (the bottom in our case), it is at its maximum value.

The linear variation means that pressure does not jump from surface level to maximum immediately but gradually increases. This behavior requires engineers to account for varying pressures when designing dams. An understanding of how pressure increases with depth ensures the correct averaging techniques are applied, and structures are adequately reinforced where necessary. Practical derivations from this characteristic can include the choice of materials and the thickness of structural components, ensuring that they can sustain these variations over time.

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Most popular questions from this chapter

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