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A suitcase (mass \(m=16 \mathrm{kg} )\) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50 \(\mathrm{m} \times 0.15 \mathrm{m}\) . The elevator is moving upward with an acceleration of magnitude 1.5 \(\mathrm{m} / \mathrm{s}^{2}\) . What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

Short Answer

Expert verified
The excess pressure applied to the floor is 2412.8 Pa.

Step by step solution

01

Determine the Force Exerted by the Suitcase

The force exerted by the suitcase is the sum of the gravitational force (weight) and the force due to the acceleration of the elevator. The gravitational force can be calculated using the formula \( F_g = m imes g \), where \( g = 9.81 \, \text{m/s}^2 \). Thus, \( F_g = 16 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 156.96 \, \text{N} \). The additional force due to the elevator's acceleration is \( F_a = m imes a \), where \( a = 1.5 \, \text{m/s}^2 \). Therefore, \( F_a = 16 \, \text{kg} \times 1.5 \, \text{m/s}^2 = 24 \, \text{N} \).
02

Calculate the Total Force

The total force \( F_t \) exerted by the suitcase on the floor is the sum of the gravitational force and the force due to acceleration. Thus, \( F_t = F_g + F_a = 156.96 \, \text{N} + 24 \, \text{N} = 180.96 \, \text{N} \).
03

Determine the Contact Area

The area over which the force is distributed is given by the dimensions of the contact surface of the suitcase, \( 0.50 \times 0.15 \, \text{m} \). Hence, the contact area \( A = 0.50 \, \text{m} \times 0.15 \, \text{m} = 0.075 \, \text{m}^2 \).
04

Calculate the Pressure Exerted

Pressure is defined as force per unit area, given by the formula \( P = \frac{F_t}{A} \). Substituting the known values, \( P = \frac{180.96 \, \text{N}}{0.075 \, \text{m}^2} = 2412.8 \, \text{Pa} \). This pressure is over and above atmospheric pressure, as it results from the combination of gravitational and acceleration forces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental force of nature. It is the force that attracts two masses toward each other. When calculating the gravitational force on an object (like the suitcase), we often refer to its weight. Weight can be determined by the formula: - \( F_g = m \times g \) - where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity, typically \( 9.81 \, \text{m/s}^2 \). - So, for a 16 kg suitcase, the gravitational force or weight is \( 16 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 156.96 \, \text{N} \). This force acts downward, pulling the suitcase toward the Earth's center.Understanding gravitational force helps in knowing how much force is applied by an object due to gravity alone. It is the starting point for comprehending more complex concepts like pressure and the effects of acceleration.
Contact Area
Contact area refers to the surface region where two objects touch. In the case of a suitcase sitting on a floor, this area is the bottom of the suitcase that's resting on the floor. Understanding contact area is crucial for calculating pressure because pressure is force distributed over an area. The contact area for our suitcase is found by multiplying the length and width of the part touching the floor: - \( 0.50 \, \text{m} \times 0.15 \, \text{m} = 0.075 \, \text{m}^2 \). - This means that the total force from the suitcase is spread over \( 0.075 \, \text{m}^2 \) of the floor.This concept is important because the larger the contact area, the more distributed the force, and the lower the pressure on the surface. Conversely, a smaller contact area means the pressure will be higher, assuming the same amount of force is applied.
Acceleration
Acceleration is defined as a change in velocity over time. It's an important factor in many physical scenarios, especially when objects are in motion like our elevator. In this problem, the elevator's movement impacts the forces acting on the suitcase.The additional force due to acceleration can be calculated using: - \( F_a = m \times a \) - where \( a \) is the acceleration of the elevator \( 1.5 \, \text{m/s}^2 \). - Thus, for our suitcase, \( F_a = 16 \, \text{kg} \times 1.5 \, \text{m/s}^2 = 24 \, \text{N} \). This additional force combines with the gravitational force, affecting the total force exerted on the floor.Understanding how acceleration contributes to force helps explain changes in pressure, especially when other forces, like gravitational force, are also acting on the object.
Elevator Physics
Elevator physics involves understanding how movement in an enclosed space can influence physical quantities like force and pressure. In this problem, as the elevator accelerates upwards, the suitcase also experiences an upward force in addition to gravity.When the elevator accelerates upwards with \( 1.5 \, \text{m/s}^2 \), the effective force acting on the suitcase increases. The total force exerted becomes: - \( F_t = F_g + F_a \). - Thus, the total force on the suitcase is \( 156.96 \, \text{N} + 24 \, \text{N} = 180.96 \, \text{N} \). This is higher than if the elevator were stationary or moving with uniform velocity.The concept of elevator physics uses principles like Newton's laws of motion and can help us calculate the resulting effects, such as pressure. In this case, we apply pressure by dividing total force by contact area: - \( P = \frac{F_t}{A} = \frac{180.96 \, \text{N}}{0.075 \, \text{m}^2} = 2412.8 \, \text{Pa} \).Elevator physics underscores how movement and acceleration can significantly alter force calculations in dynamic environments.

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Most popular questions from this chapter

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