/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 A \(58-\mathrm{kg}\) skier is go... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(58-\mathrm{kg}\) skier is going down a slope oriented \(35^{\circ}\) above the horizontal. The area of each ski in contact with the snow is 0.13 \(\mathrm{m}^{2}\) Determine the pressure that each ski exerts on the snow.

Short Answer

Expert verified
Pressure exerted by each ski is approximately 1790.42 Pa.

Step by step solution

01

Understand the Problem

We need to calculate the pressure that each ski exerts on the snow. Pressure is calculated using the formula \( P = \frac{F}{A} \), where \( P \) is pressure, \( F \) is force, and \( A \) is the area. In this problem, the force is due to the weight of the skier acting through gravity.
02

Calculate the Weight of the Skier

The force due to the weight of the skier can be calculated using the equation \( F = m \times g \), where \( m \) is the mass of the skier and \( g \) is acceleration due to gravity (approx. \( 9.8 \, \text{m/s}^2 \)). For a 58 kg skier, \( F = 58 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 568.4 \, \text{N} \).
03

Calculate the Normal Force Component

The normal force is the component of the skier's weight that acts perpendicular to the slope. This is given by \( F_{\text{normal}} = F \times \cos(\theta) \), where \( \theta = 35^{\circ} \). Thus, \( F_{\text{normal}} = 568.4 \, \text{N} \times \cos(35^{\circ}) \approx 465.31 \, \text{N} \).
04

Determine the Pressure Exerted by Each Ski

Since this force is distributed over both skis, each ski experiences half of the normal force: \( F_{\text{single ski}} = \frac{465.31}{2} \, \text{N} \approx 232.655 \, \text{N} \). Using the formula \( P = \frac{F}{A} \) where \( A = 0.13 \, \text{m}^2 \), the pressure exerted by each ski is: \( P = \frac{232.655 \, \text{N}}{0.13 \, \text{m}^2} \approx 1790.42 \, \text{Pa} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force due to Gravity
The force due to gravity is a fundamental concept in physics, impacting everything from falling objects to the behavior of skiers on a slope. Gravity is the force that attracts two bodies toward each other, with Earth's gravitational pull acting on objects near its surface. It's responsible for the weight we experience. The gravitational force acting on an object can be calculated using the equation:
  • \( F = m \times g \)
where \( m \) is the object's mass and \( g \) is the acceleration due to gravity, typically \(9.8 \, \text{m/s}^2\) on Earth.
For example, if a skier has a mass of 58 kg, the force due to gravity acting on this skier is \( 58 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 568.4 \, \text{N} \). This force is crucial in determining how much pressure the skier exerts on their skis and the snow beneath.
Normal Force
The normal force is a key player when analyzing forces on a slope. This force acts perpendicular to the surface with which an object is in contact.
For a skier traveling down a slope at an angle, the normal force is not the same as the gravitational force due to the slope's orientation.

To determine the normal force, we need to consider the angle of the slope, denoted as \( \theta \). The formula for the normal force is:
  • \( F_{\text{normal}} = F \times \cos(\theta) \)
where \( F \) is the gravitational force and \( \theta \) is the slope angle.
For a skier with a gravitational force of 568.4 N on a 35-degree slope, the normal force becomes \( 568.4 \, \text{N} \times \cos(35^\circ) \approx 465.31 \, \text{N} \). This force affects the pressure exerted on the snow.
Slope Orientation
The orientation of a slope significantly influences the forces acting on a skier. Slope orientation refers to the angle at which the slope rises above the horizontal.
This angle, denoted \( \theta \), impacts both the normal force and the component of gravitational force acting along the slope.

Here are a few key concepts:
  • A steeper slope (larger \( \theta \)) decreases the normal force, leading to less friction and potentially higher speeds.
  • The gravitational force along the slope's surface causes the skier to accelerate downhill.
In our example, the slope is oriented at \( 35^\circ \). This angle requires careful calculation of both the skier's normal force and the component of gravity that propels the skier downwards. Understanding the influence of slope orientation is important for calculating the normal force and resultant pressure in real-world scenarios.
Weight of a Skier
A skier's weight plays a central role in calculating pressure exerted on skis. While often used interchangeably with mass, weight is technically the force exerted by gravity on an object.
  • Weight is calculated by the equation: \( \text{Weight} = m \times g \), where \( m \) is mass and \( g \) is the acceleration due to gravity.
In the case of the 58-kg skier, their weight is the gravitational force of \( 568.4 \, \text{N} \). This weight generates the normal force and is crucial for understanding how skis distribute pressure over snow.
Each ski carries half the normal force, which is \( 232.655 \, \text{N} \), over an area of 0.13 \( \text{m}^2 \).
Recognizing the relationship between a skier's weight and the pressure they exert helps illuminate the physics behind skiing dynamics and highlights the impact of an individual's characteristics on skiing behavior.

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Most popular questions from this chapter

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