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A full can of black cherry soda has a mass of 0.416 \(\mathrm{kg}\) . It contains \(3.54 \times 10^{-4} \mathrm{m}^{3}\) of liquid. Assuming that the soda has the same density as water, find the volume of aluminum used to make the can.

Short Answer

Expert verified
The volume of aluminum is approximately \(2.296 \times 10^{-5} \text{ m}^3\).

Step by step solution

01

Understanding the Problem

We have a can of black cherry soda with a mass of 0.416 kg, containing 3.54 x 10^{-4} m^3 of liquid. Our goal is to find the volume of aluminum used to make the can, assuming the soda has the same density as water.
02

Calculate the Mass of the Soda

Since the soda's density equals that of water, which is 1000 kg/m^3, we use the formula \( \text{Mass} = \text{Density} \times \text{Volume} \) to find the mass of the soda. Thus, the mass of the soda is \( 1000 \times 3.54 \times 10^{-4} = 0.354 \text{ kg} \).
03

Determine the Mass of the Aluminum

The total mass of the can and soda is 0.416 kg. By subtracting the mass of the soda, we find the mass of the aluminum: \( 0.416 - 0.354 = 0.062 \text{ kg} \).
04

Calculate the Volume of the Aluminum

To find the volume of the aluminum, use the formula \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \). Assuming the density of aluminum is 2700 kg/m^3, calculate: \( \frac{0.062}{2700} = 2.296 \times 10^{-5} \text{ m}^3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Calculation
When tasked with calculating the mass of an object or a substance, it's essential to know two things: the density and the volume. Mass is simply the product of these two quantities. The formula is expressed as \( \text{Mass} = \text{Density} \times \text{Volume} \).
For example, in the problem involving the can of black cherry soda, knowing that the soda has the same density as water (1000 kg/m³), we can easily find the mass. Given the volume of the soda is \( 3.54 \times 10^{-4} \) m³, the mass is calculated by multiplying these quantities, resulting in 0.354 kg. This step represents the core principle of mass calculation in physics, allowing us to break down more complex problems by finding the mass one component at a time.
Always remember:
  • Check if the density is provided or needs to be referenced from known data.
  • Ensure the units are consistent before performing calculations.
  • Recollect that density can vary with conditions like temperature, especially in practical applications.
Volume Calculation
Volume calculation can mean figuring out the total space that an object or a substance occupies. It's often done by using the formula \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \).
This formula tells us that if you know the mass of a substance and its density, you can find out its volume. In our soda can example, after calculating the mass of aluminum and knowing its density as 2700 kg/m³, we calculated the volume of aluminum to be \( 2.296 \times 10^{-5} \) m³.
To streamline this:
  • Ensure the mass and density values are accurate and reflect the substance in question.
  • Watch out for unit conversions; they can be tricky but are vital for accuracy.
  • Volume measurement can sometimes include additional factors like hollowness or cavity, depending upon the material's shape and density variation.
Aluminum Density
Aluminum is known for its light weight and high strength, with a commonly accepted density of 2700 kg/m³. This property makes it an ideal material for numerous applications, including beverage cans.
When solving problems involving aluminum, the density acts as a key factor in converting between the mass and volume of the metal. As demonstrated in the soda can problem, once you know either the mass or volume of aluminum, this constant density allows you to find the other.
Points to consider:
  • Aluminum's density can slightly vary based on heat treatment or alloy mixtures, but 2700 kg/m³ is typically used for pure aluminum.
  • Knowing its density helps in anticipating the material's behavior in different structural and applied contexts.
  • Using correct density values is crucial in calculations involving conservation of mass and volume in physics.
Problem Solving in Physics
In physics, problem-solving often requires a systematic approach and a steady attention to detail. Let's break this down:
  • **Understand the Problem:** Begin by carefully reading the given data and understanding what is required, as we did with the soda can exercise.
  • **Identify Known and Unknown Variables:** Recognize the known values (like mass and density here) and what you need to find (volume of aluminum).
  • **Equation Utilization:** Use relevant equations, such as those relating mass, volume, and density, to formulate a path to the solution.
  • **Iteration and Verification:** After calculations, verify if the obtained values make sense and relate back correctly to all given data.
By developing and training in these methodologies, you ensure precise and efficient solutions in your physics work. Keep practice sessions diverse and use real-world examples to make connections clear and relatable.

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Most popular questions from this chapter

A spring is attached to the bottom of an empty swimming pool, with the axis of the spring oriented vertically. An 8.00-kg block of wood \(\left(\rho=840 \mathrm{kg} / \mathrm{m}^{3}\right)\) is fixed to the top of the spring and compresses it. Then the pool is filled with water, completely covering the block. The spring is now observed to be stretched twice as much as it had been compressed. Determine the percentage of the block's total volume that is hollow. Ignore any air in the hollow space.

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A patient recovering from surgery is being given fluid intravenously. The fluid has a density of \(1030 \mathrm{kg} / \mathrm{m}^{3},\) and \(9.5 \times 10^{-4} \mathrm{m}^{3}\) of it flows into the patient every six hours. Find the mass flow rate in \(\mathrm{kg} / \mathrm{s}\) .

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