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A \(0.10-\mathrm{m} \times 0.20-\mathrm{m} \times 0.30-\mathrm{m}\) block is suspended from a wire and is completely under water. What buoyant force acts on the block?

Short Answer

Expert verified
The buoyant force acting on the block is 58.86 N.

Step by step solution

01

Understand the Concept of Buoyant Force

Buoyant force is the upward force exerted on an object submerged in a fluid, equal to the weight of the fluid displaced by the object. This principle is known as Archimedes' principle.
02

Calculate the Volume of the Block

The block has dimensions \(0.10\, \text{m} \times 0.20\, \text{m} \times 0.30\, \text{m}\). Calculate the volume \(V\) of the block using the formula for the volume of a rectangular prism: \(V = \text{length} \times \text{width} \times \text{height}\). Thus, \(V = 0.10 \times 0.20 \times 0.30 = 0.006 \text{ m}^3\).
03

Use Archimedes' Principle to Find Buoyant Force

According to Archimedes' principle, the buoyant force \(F_b\) is equal to the weight of the fluid displaced by the block. The displaced fluid's weight can be calculated as \(F_b = \text{density of water} \times V \times g\), where \(\text{density of water} = 1000 \text{ kg/m}^3\) and \(g = 9.81 \text{ m/s}^2\).
04

Substitute Values to Calculate Buoyant Force

Substitute the known values into the formula: \(F_b = (1000 \text{ kg/m}^3) \times (0.006 \text{ m}^3) \times (9.81 \text{ m/s}^2)\).
05

Perform the Calculation

Calculate the buoyant force: \(F_b = 1000 \times 0.006 \times 9.81 = 58.86 \text{ N}\). The buoyant force acting on the block is 58.86 newtons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' Principle
Archimedes' Principle is essential for understanding buoyant forces as it describes how objects behave in fluids. According to this principle, when an object is submerged in a fluid, it experiences an upward force known as buoyant force. This force is equal to the weight of the fluid displaced by the object.

The principle can be stated simply: the more fluid an object displaces, the greater the buoyant force acting upon it. This is why, for example, a heavy object made of a dense material might still float if it has a large enough shape to displace a sufficient amount of water.
  • If the buoyant force equals the object's weight, the object will float.
  • If the buoyant force is less than the object's weight, it will sink.
This fundamental principle explains why things like ships, boats, and even swimmers do not sink despite being heavier than water. It also forms the basis of buoyancy calculations often used in engineering and physics applications.
Volume Calculation
Calculating the volume of an object is crucial to determine the buoyant force that will act upon it in a fluid. For simple geometric shapes, such as a rectangular prism, the volume is easily calculated using straightforward formulas.

In the case of a rectangular block, volume (V) is determined by multiplying its length, width, and height:
  • \[ V = \text{length} \times \text{width} \times \text{height} \]
This formula provides the volume in cubic meters (m³), crucial for further buoyancy calculations. Knowing how to find this volume helps in understanding the amount of fluid displaced by the object and, subsequently, the buoyant force it experiences.

For odd shapes, the process may involve more complex mathematics or even experimental methods to find the submerged volume accurately.
Density and Weight of Fluid
Density plays a vital role in the calculations of buoyant forces. It is defined as the mass per unit volume of a substance and is usually denoted by the Greek letter \( \rho \).

When calculating the buoyant force, you need to know the fluid's density. For water, the density is typically 1000 kg/m³. This density is key in understanding how much force the fluid can exert on the submerged object.
  • The buoyant force \( F_b \) can be calculated using the formula: \[ F_b = \rho \times V \times g \]
  • Here, \( V \) is the volume of the displaced fluid, and \( g \) is the acceleration due to gravity, approximately 9.81 m/s².
Hence, an object's buoyancy can be analyzed by considering the liquid's density and the displaced volume, providing a complete picture of the interactions happening underwater. These basic concepts of density and weight further aid in determining whether an object will sink or float when placed in a fluid.

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Most popular questions from this chapter

A small crack occurs at the base of a \(15.0-\mathrm{m}\) -high dam. The effective crack area through which water leaves is \(1.30 \times 10^{-3} \mathrm{m}^{2}\) (a) Ignoring viscous losses, what is the speed of water flowing through the crack? (b) How many cubic meters of water per second leave the dam?

A water bed for sale has dimensions of 1.83 \(\mathrm{m} \times 2.13 \mathrm{m} \times 0.229 \mathrm{m} .\) The floor of the bedrroom will tolerate an additional weight of no more than 66660 \(\mathrm{N}\) . Find the weight of the water in the bed and determine whether the bed should be purchased.

A cylindrical air duct in an air conditioning system has a length of 5.5 \(\mathrm{m}\) and a radius of \(7.2 \times 10^{-2} \mathrm{m} . \mathrm{A}\) fan forces air \(\left(\eta=1.8 \times 10^{-5} \mathrm{Pa} \cdot \mathrm{s}\right)\) through the duct, so that the air in a room (volume \(=280 \mathrm{m}^{3} )\) is replenished every ten minutes. Determine the difference in pressure between the ends of the air duct.

A person who weighs 625 \(\mathrm{N}\) is riding a \(98-\mathrm{N}\) mountain bike. Suppose that the entire weight of the rider and bike is supported equally by the two tires. If the pressure in each tire is \(7.60 \times 10^{5} \mathrm{Pa},\) what is the area of contact between each tire and the ground?

An airplane wing is designed so that the speed of the air across the top of the wing is 251 \(\mathrm{m} / \mathrm{s}\) when the speed of the air below the wing is 225 \(\mathrm{m} / \mathrm{s}\) . The density of the air is 1.29 \(\mathrm{kg} / \mathrm{m}^{3} .\) What is the lifting force on a wing of area 24.0 \(\mathrm{m}^{2} ?\)

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