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In \(2.0\) minutes, a ski lift raises four skiers at constant speed to a height of \(140 \mathrm{~m}\). The average mass of each skier is \(65 \mathrm{~kg}\). What is the average power provided by the tension in the cable pulling the lift?

Short Answer

Expert verified
The average power provided is approximately 2973 W.

Step by step solution

01

Determine the Total Mass of Skiers

Each skier has a mass of 65 kg, and there are four skiers. Therefore, the total mass \( m \) is calculated by multiplying the mass of one skier by the number of skiers: \( m = 65 \mathrm{~kg} \times 4 = 260 \mathrm{~kg} \).
02

Calculate the Gravitational Force

The gravitational force \( F \) is given by \( F = m \cdot g \), where \( g = 9.8 \mathrm{~m/s^2} \) is the acceleration due to gravity. Substituting the values, we get \( F = 260 \mathrm{~kg} \times 9.8 \mathrm{~m/s^2} = 2548 \mathrm{~N} \).
03

Find the Work Done

Work \( W \) is calculated by the formula \( W = F \cdot h \), where \( h = 140 \mathrm{~m} \) is the height the skiers are lifted. Substituting the values, we get \( W = 2548 \mathrm{~N} \times 140 \mathrm{~m} = 356720 \mathrm{~J} \) (Joules).
04

Convert Time from Minutes to Seconds

Since the time \( t \) is given in minutes, we need to convert it into seconds for use in the power formula. Because there are 60 seconds in a minute, \( t = 2 \mathrm{~min} \times 60 \mathrm{~s/min} = 120 \mathrm{~s} \).
05

Calculate the Average Power

Power \( P \) is defined as the work done per unit time, given by \( P = \frac{W}{t} \). Substituting the work done and time, \( P = \frac{356720 \mathrm{~J}}{120 \mathrm{~s}} = 2972.67 \mathrm{~W} \) (Watts).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

work done
In physics, the concept of work plays a crucial role when we need to determine how much energy is used in applying a force over a distance. Work is defined as the product of the force applied to an object and the distance over which this force acts, specifically in the direction of the force. Mathematically, this is represented as:
  • Work (W) = Force (F) × Distance (d)
When calculating the work done in raising objects to a certain height, as seen in the ski lift problem, we often deal with gravitational force. Since work is a measure of energy transfer, it is expressed in Joules (J). In our problem, the calculation of work involves multiplying the gravitational force by the height of the lift:
  • W = F × h
This ensures we account for all the energy expended in overcoming gravity to raise the skiers to the desired altitude.
gravitational force
Gravitational force is the attractive force exerted by the Earth (or any other large mass) on objects toward its center. It is what keeps us grounded and determines the weight of an object. This force is calculated based on the mass of the object and the gravitational acceleration on Earth:
  • Gravitational Force (F) = Mass (m) × Gravitational Acceleration (g)
The standard gravitational acceleration, denoted as "g," is approximately 9.8 m/s² on Earth's surface. In our exercise, the gravitational force acts on the skiers, and is crucial in determining the work required to lift them. It is because of this force that any lifting effort must counteract the weight of the objects, hence requiring energy to perform work. Understanding gravitational force helps in realizing why force and energy are necessary to raise objects to a higher altitude.
constant speed
When an object moves at constant speed, it means that its velocity remains unchanged over time. For the ski lift scenario, constant speed implies steady energy usage without acceleration or deceleration. This is significant in the calculation of average power required to perform the work of lifting the skiers. A key point is that when speed is constant, the forces acting on the object are balanced. The upward pulling force by the lift's cable matches the downward gravitational force. Thus, the net force on the object is zero, ensuring no change in speed. Constant speed simplifies power calculations, because the work done depends only on the height achieved and not on any changes in kinetic energy. As a result, the average power is a straightforward division of the work done by the time taken to complete the task. This concept links directly to efficiency and cost-effectiveness in energy use, essential considerations in engineering and physics.

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Most popular questions from this chapter

A \(2.00\) -kg rock is released from rest at a height of \(20.0 \mathrm{~m}\). Ignore air resistance and determine the kinetic energy, gravitational potential energy, and total mechanical energy at each of the following heights: \(20.0,10.0\), and \(0 \mathrm{~m}\).

The concepts in this problem are similar to those in Multiple-Concept Example \(4,\) except that the force doing the work in this problem is the tension in the cable. A rescue helicopter lifts a 79 -kg person straight up by means of a cable. The person has an upward acceleration of \(0.70 \mathrm{~m} / \mathrm{s}^{2}\) and is lifted from rest through a distance of \(11 \mathrm{~m}\). (a) What is the tension in the cable? How much work is done by (b) the tension in the cable and (c) the person's weight? (d) Use the work- energy theorem and find the final speed of the person.

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. (a) Is the direction of the force the same as or opposite to the direction of the displacement of the asteroid? Why? (b) Does the force do positive, negative, or zero work? Justify your answer. (c) What type of energy is changing as the object slows down? (d) What is the relationship between the work done by this force and the change in the object's energy? The asteroid has a mass of \(4.5 \times 10^{4} \mathrm{~kg}\), and the force causes its speed to change from 7100 to \(5500 \mathrm{~m} / \mathrm{s}\). (a) What is the work done by the force? (b) If the asteroid slows down over a distance of \(1.8 \times 10^{6} \mathrm{~m}\), determine the magnitude of the force. Verify that your answers are consistent with the answers to the Concept Questions.

Two pole-vaulters just clear the bar at the same height. The first lands at a speed of \(8.90 \mathrm{~m} / \mathrm{s},\) and the second lands at a speed of \(9.00 \mathrm{~m} / \mathrm{s} .\) The first vaulter clears the bar at a speed of \(1.00 \mathrm{~m} / \mathrm{s}\). Ignore air resistance and friction and determine the speed at which the second vaulter clears the bar.

You are trying to lose weight by working out on a rowing machine. Each time you pull the rowing bar (which simulates the "oars") toward you, it moves a distance of \(1.2 \mathrm{~m}\) in a time of \(1.5 \mathrm{~s}\). The readout on the display indicates that the average power you are producing is \(82 \mathrm{~W}\). What is the magnitude of the force that you exert on the handle?

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