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A \(2.00\) -kg rock is released from rest at a height of \(20.0 \mathrm{~m}\). Ignore air resistance and determine the kinetic energy, gravitational potential energy, and total mechanical energy at each of the following heights: \(20.0,10.0\), and \(0 \mathrm{~m}\).

Short Answer

Expert verified
At 20m: KE=0 J, PE=392.2 J, TME=392.2 J; at 10m: KE=196.1 J, PE=196.1 J, TME=392.2 J; at 0m: KE=392.2 J, PE=0 J, TME=392.2 J.

Step by step solution

01

Understand the Problem

We need to calculate the kinetic energy (KE), gravitational potential energy (PE), and total mechanical energy (TME) of a rock at different heights. The rock is released from rest, meaning it initially has zero kinetic energy at the release point (20 m above ground).
02

Calculate Potential Energy at Each Height

The formula for gravitational potential energy is \( PE = mgh \), where \( m \) is mass, \( g \) is gravitational acceleration (\(9.81 \, \text{m/s}^2\)), and \( h \) is height. - At 20 m: \( PE = 2.00 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 20.0 \, \text{m} = 392.2 \, \text{J} \)- At 10 m: \( PE = 2.00 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 10.0 \, \text{m} = 196.1 \, \text{J} \)- At 0 m: \( PE = 2.00 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 0 \, \text{m} = 0 \, \text{J} \)
03

Determine Initial Total Mechanical Energy

The total mechanical energy is the sum of kinetic and potential energy. Initially, at 20 m, \( TME = KE + PE = 0 + 392.2 = 392.2 \, \text{J} \). Total mechanical energy remains constant if there is no air resistance.
04

Calculate Kinetic Energy at Each Height

Since total mechanical energy is conserved, use the formula \( KE = TME - PE \).- At 20 m: \( KE = 392.2 \, \text{J} - 392.2 \, \text{J} = 0 \, \text{J} \)- At 10 m: \( KE = 392.2 \, \text{J} - 196.1 \, \text{J} = 196.1 \, \text{J} \)- At 0 m: \( KE = 392.2 \, \text{J} - 0 \, \text{J} = 392.2 \, \text{J} \)
05

Review Total Mechanical Energy at Each Height

Total Mechanical Energy should remain constant with TME = 392.2 J at all heights, verifying the principle of conservation of energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is one of the fundamental forms of energy associated with the motion of an object. Whenever an object moves, it possesses kinetic energy, which depends on two main factors:
  • Mass of the object (\(m\)
  • Velocity of the object (\(v\)
The formula for calculating kinetic energy (\(KE\)) is:\[ KE = \frac{1}{2}mv^2 \]Initially, when the rock is released from a height of 20 meters, its velocity is zero because it is at rest. This means its initial kinetic energy is zero. As the rock falls, it gains speed, and its kinetic energy increases. At a height of 10 meters, the rock has some kinetic energy because of its increasing velocity. By the time it reaches the ground, the kinetic energy reaches a maximum due to its maximum velocity at this point.
Ultimately, kinetic energy reflects how much work an object in motion can potentially perform due to its speed and mass.
Gravitational Potential Energy
Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. It is directly related to the height of the object relative to a reference point, often taken as the ground. The formula for calculating gravitational potential energy (\(PE\)) is:\[ PE = mgh \]where:
  • \(m\) is the mass of the object
  • \(g\) is the acceleration due to gravity, approximately 9.81 \(\text{m/s}^2\)
  • \(h\) is the height above the reference point
At the start, when the rock is at 20 meters, it holds the maximum potential energy because it is as high as it gets, storing more energy due to its elevated position. As the rock descends to 10 meters and eventually to the ground, its potential energy decreases, because its height above the ground decreases. When the rock finally hits the ground, its potential energy becomes zero.
Mechanical Energy
Mechanical energy is the sum of kinetic and gravitational potential energy that an object possesses. Due to the conservation of energy principle, if external forces like air resistance are negligible, the total mechanical energy remains constant throughout the motion. Mathematically, it can be expressed as:\[ TME = KE + PE \]For the rock falling from 20 meters, the total mechanical energy at each height should remain at 392.2 J, based on the conservation of energy law. Although the individual amounts of kinetic and potential energy change as the rock falls, their sum remains constant. At 20 meters, mechanical energy is entirely potential since kinetic energy is zero. As the rock descends to 10 meters, part of its mechanical energy converts into kinetic energy, while the rest remains as potential energy. Upon reaching the ground, all the potential energy is transformed into kinetic energy, maximizing the rock's kinetic energy while the total mechanical energy stays unchanged.

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Most popular questions from this chapter

The (nonconservative) force propelling \(1.50 \times 10^{3}-\mathrm{kg}\) a car up a mountain road does \(4.70 \times 10^{6} \mathrm{~J}\) of work on the car. The car starts from rest at sea level and has a speed of \(27.0 \mathrm{~m} / \mathrm{s}\) at an altitude of \(2.00 \times 10^{2} \mathrm{~m}\) above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.

Refer to Concept Simulation 6.1 at for a review of the concepts with which this problem deals. A \(0.075-\mathrm{kg}\) arrow is fired horizontally. The bowstring exerts an average force of \(65 \mathrm{~N}\) on the arrow over a distance of \(0.90 \mathrm{~m}\). With what speed does the arrow leave the bow?

Multiple-Concept Example 5 reviews many of the concepts that play a role in this problem. An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of \(25.0^{\circ}\) with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200 . She coasts down a distance of \(10.4 \mathrm{~m}\) before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point whose vertical distance is \(3.50 \mathrm{~m}\) below the edge. How fast is she going just before she lands?

Relative to the ground, what is the gravitational potential energy of a 55.0 -kg person who is at the top of the Sears Tower, a height of \(443 \mathrm{~m}\) above the ground?

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