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A \(1380-\mathrm{kg}\) car is moving due east with an initial speed of \(27.0 \mathrm{~m} / \mathrm{s}\). After \(8.00 \mathrm{~s}\) the car has slowed down to \(17.0 \mathrm{~m} / \mathrm{s}\). Find the magnitude and direction of the net force that produces the deceleration.

Short Answer

Expert verified
The force is 1725 N due west.

Step by step solution

01

Identify Given Information

The mass of the car is given as \( m = 1380 \, \text{kg} \). The initial velocity \( v_i = 27.0 \, \text{m/s} \), final velocity \( v_f = 17.0 \, \text{m/s} \), and the time over which the change occurs is \( t = 8.00 \, \text{s} \).
02

Calculate Change in Velocity

Find the change in velocity \( \Delta v \) by subtracting the final velocity from the initial velocity: \[ \Delta v = v_f - v_i = 17.0 \, \text{m/s} - 27.0 \, \text{m/s} = -10.0 \, \text{m/s}. \]
03

Determine Acceleration

Using the change in velocity and the time, calculate the acceleration \( a \) using the formula for acceleration: \[ a = \frac{\Delta v}{t} = \frac{-10.0 \, \text{m/s}}{8.00 \, \text{s}} = -1.25 \, \text{m/s}^2. \] Note that the acceleration is negative, indicating deceleration.
04

Apply Newton's Second Law

Use Newton's second law to find the net force acting on the car: \[ F = m \times a = 1380 \, \text{kg} \times (-1.25 \, \text{m/s}^2) = -1725 \, \text{N}. \]
05

Determine Magnitude and Direction of Force

The magnitude of the force is \( 1725 \, \text{N} \). Since the force is negative, it acts in the opposite direction of the initial motion, which is due west.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Deceleration
Deceleration is a type of acceleration where an object is slowing down. It occurs when the velocity of an object decreases over time. In other words, it is negative acceleration. This is crucial when analyzing problems involving vehicles, such as calculating the force needed to reduce speed. When a car decelerates, its velocity decreases, resulting in a negative change in velocity. This negative change is represented mathematically by a negative acceleration value. In the exercise provided, a car is slowing down from 27.0 m/s to 17.0 m/s. The term 'deceleration' is used because the car is reducing speed over 8 seconds. This negative acceleration signifies that the applied net force is in the opposite direction of the car's initial motion.
Net Force Calculation
The net force acts on an object to cause a change in its motion. According to Newton’s Second Law, the net force can be calculated using the formula:
  • \( F = m \times a \)
  • Where:
  • \( F \) is the net force,
  • \( m \) is the mass, and
  • \( a \) is the acceleration.
In the example, the car has a mass of 1380 kg and an acceleration of \(-1.25 \, \text{m/s}^2\). The calculation gives a force of \(-1725 \, \text{N}\). The negative value indicates the force direction is opposite to the initial motion, which is due west, while the car was moving east initially.
Change in Velocity
The change in velocity \( (\Delta v) \) is the difference between the final velocity \( (v_f) \) and the initial velocity \( (v_i) \). It's an essential part of dynamics, which allows us to determine the acceleration of an object. This is calculated with the equation:
  • \( \Delta v = v_f - v_i \)
In the given problem, the car's final velocity is 17.0 m/s, and its initial velocity is 27.0 m/s. Therefore, the change in velocity is \(-10.0 \, \text{m/s}\), which tells us the car's speed is decreasing, thus leading to deceleration.Understanding the change in velocity is critical in predicting the future state of motion of an object and helps in calculating the forces working on it using further dynamics principles.
Acceleration
Acceleration refers to the rate of change of velocity of an object. It involves speeding up, slowing down, or changing direction. In a deceleration scenario, the acceleration is negative as it works against the direction of motion. The formula to calculate acceleration is:
  • \( a = \frac{\Delta v}{t} \)
  • Where:
  • \( a \) is the acceleration,
  • \( \Delta v \) is the change in velocity, and
  • \( t \) is the time taken.
For the car that was examined, the acceleration is \(-1.25 \, \text{m/s}^2\), indicating that it is reducing its speed at this rate every second. Understanding acceleration is fundamental in predicting how long it will take for an object to reach a certain velocity or come to a stop. It also directly relates to the force exerted, as shown by Newton's Second Law.

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