/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A neutron star has a mass of \(2... [FREE SOLUTION] | 91Ó°ÊÓ

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A neutron star has a mass of \(2.0 \times 10^{30} \mathrm{~kg}\) (about the mass of our sun) and a radius of \(5.0 \times 10^{3} \mathrm{~m}\) (about the height of a goodsized mountain). Suppose an object falls from rest near the surface of such a star. How fast would it be moving after it had fallen a distance of \(0.010 \mathrm{~m} ?\) (Assume that the gravitational force is constant over the distance of the fall, and that the star is not rotating.)

Short Answer

Expert verified
The object would be moving at approximately \( 3.267 \times 10^5 \ \mathrm{m/s} \) after falling 0.010 m.

Step by step solution

01

Identify the Known Values

We need to calculate the velocity of an object after it falls a distance of 0.010 m on a neutron star. The mass of the neutron star is given as \( 2.0 \times 10^{30} \) kg and the radius is \( 5.0 \times 10^{3} \) m. The object starts from rest.
02

Calculate Gravitational Acceleration

Use the formula for gravitational force to find the acceleration due to gravity on the neutron star's surface: \[ g = \frac{G M}{R^2} \]where \( G = 6.674 \times 10^{-11} \ \mathrm{Nm}^2/\mathrm{kg}^2 \) is the gravitational constant, \( M = 2.0 \times 10^{30} \) kg is the mass of the neutron star, and \( R = 5.0 \times 10^{3} \) m is its radius. Substituting these values in gives:\[ g = \frac{(6.674 \times 10^{-11}) \times (2.0 \times 10^{30})}{(5.0 \times 10^{3})^2} \approx 5.3392 \times 10^{12} \ \mathrm{m/s^2} \]
03

Calculate Final Velocity

We use the kinematic equation connecting initial velocity, acceleration, and distance to find the final velocity:\[ v^2 = u^2 + 2as \]where \( u = 0 \ \mathrm{m/s} \) is the initial velocity, \( a \) is the acceleration due to gravity calculated in Step 2, and \( s = 0.010 \) m is the distance fallen. Substituting these values gives:\[ v^2 = 0 + 2 \cdot 5.3392 \times 10^{12} \cdot 0.010 \]\[ v^2 = 1.06784 \times 10^{11} \]Taking the square root gives the final velocity:\[ v \approx 3.267 \times 10^5 \ \mathrm{m/s} \]
04

Concluding Result

The final velocity of the object after falling 0.010 m on the neutron star's surface is approximately \( 3.267 \times 10^5 \ \mathrm{m/s} \). This high velocity is due to the strong gravitational field of the neutron star.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is the field of physics that describes the motion of objects without considering the forces that cause the motion. It focuses on the movement regarding parameters like displacement, velocity, and acceleration. In the exercise presented, the kinematic equations have been employed to determine how an object accelerates and reaches a particular velocity as it falls. These equations are crucial in describing the behavior of any object in motion, providing a mathematical framework that helps predict and analyze the object's path.

Kinematics involves several key concepts:
  • Displacement: A vector quantity that refers to the change in position of an object.
  • Velocity: The rate at which an object changes its position.
  • Acceleration: The rate of change of velocity over time.
A fundamental understanding of these concepts is essential in solving any kinematic problem — whether on Earth or in more extreme environments like a neutron star.
Gravitational Acceleration
Gravitational acceleration refers to the acceleration of an object due to the influence of a gravitational force. On Earth, we experience a gravitational acceleration of approximately 9.8 m/s². However, when we examine celestial bodies such as a neutron star, this acceleration is drastically different due to its immense mass and small radius.

In our exercise, the gravitational acceleration on the surface of the neutron star is calculated using the formula:\[ g = \frac{G M}{R^2} \]where:
  • G is the gravitational constant, approximately \( 6.674 \times 10^{-11} \, \mathrm{Nm}^2/\mathrm{kg}^2 \).
  • M is the mass of the neutron star.
  • R is the radius of the neutron star.
This results in an acceleration of approximately \( 5.3392 \times 10^{12} \, \mathrm{m/s^2} \), which is vastly higher than what is experienced on Earth and illustrates the powerful gravitational pull exerted by a neutron star.
Neutron Star
A neutron star is a highly dense celestial object that remains after a massive star explodes in a supernova. These stars have incredibly high densities because they are composed almost entirely of neutrons packed closely together.

Some fascinating characteristics of neutron stars include:
  • They can have masses greater than the Sun while being only about 20 kilometers in diameter.
  • Their gravitational fields are immensely powerful due to the combination of high mass and small size.
  • Neutron stars can rotate at extremely high speeds.
In our problem, we're dealing with the gravitational effects of a neutron star, which are significant due to its massive gravitational forces. This exercise provides insights into how such a strong gravitational field affects an object's movement, even when falling a short distance.
Kinematic Equations
Kinematic equations are a set of mathematics formulas used to predict the future position or speed of an object moving under constant acceleration. These equations help to extract quantitative information about motion along a straight line.

The fundamental kinematic equation used in our exercise is:\[ v^2 = u^2 + 2as \]where:
  • v is the final velocity of the object.
  • u is the initial velocity.
  • a is the acceleration acting on the object.
  • s is the displacement.
This equation enabled us to compute the object's speed after falling 0.010 m on the neutron star. Understanding how to manipulate and apply these kinematic equations is essential in solving physics problems, especially when analyzing motion in extraordinary environments such as the intense gravitational field of a neutron star.

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Most popular questions from this chapter

A person is trying to judge whether a picture \((\mathrm{mass}=1.10 \mathrm{~kg})\) is properly positioned by temporarily pressing it against a wall. The pressing force is perpendicular to the wall. The coefficient of static friction between the picture and the wall is \(0.660 .\) What is the minimum amount of pressing force that must be used?

When a 58 -g tennis ball is served, it accelerates from rest to a speed of \(45 \mathrm{~m} / \mathrm{s}\). The impact with the racket gives the ball a constant acceleration over a distance of \(44 \mathrm{~cm} .\) What is the magnitude of the net force acting on the ball?

A fisherman is fishing from a bridge and is using a "45-N test line." In other words, the line will sustain a maximum force of \(45 \mathrm{~N}\) without breaking. (a) What is the weight of the heaviest fish that can be pulled up vertically when the line is reeled in (a) at a constant speed and (b) with an acceleration whose magnitude is \(2.0 \mathrm{~m} / \mathrm{s}^{2} ?\)

In preparation for this problem, review Conceptual Example 7 . A space traveler whose mass is \(115 \mathrm{~kg}\) leaves earth. What are his weight and mass (a) on earth and (b) in interplanetary space where there are no nearby planetary objects?

Concept Simulation 4.1 at reviews the concepts that are important in this problem. The speed of a bobsled is increasing because it has an acceleration of \(2.4 \mathrm{~m} / \mathrm{s}^{2}\). At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total \(450 \mathrm{~N}\). The mass of the bobsled and its riders is \(270 \mathrm{~kg}\). (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

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