/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 A fisherman is fishing from a br... [FREE SOLUTION] | 91Ó°ÊÓ

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A fisherman is fishing from a bridge and is using a "45-N test line." In other words, the line will sustain a maximum force of \(45 \mathrm{~N}\) without breaking. (a) What is the weight of the heaviest fish that can be pulled up vertically when the line is reeled in (a) at a constant speed and (b) with an acceleration whose magnitude is \(2.0 \mathrm{~m} / \mathrm{s}^{2} ?\)

Short Answer

Expert verified
(a) 4.59 kg, (b) 3.81 kg.

Step by step solution

01

Identify Forces at Constant Speed

When pulling the fish up at a constant speed, the only force acting against the weight of the fish is the tension in the line. Under these conditions, the fish's weight (force due to gravity) must be equal to the maximum force that the line can sustain (45 N). Therefore, the gravity force is \( F = mg = 45 \text{ N} \).
02

Solve for Maximum Mass at Constant Speed

Using the relationship \( F = mg \), where \( g = 9.8 \text{ m/s}^2 \), we solve for mass \( m \):\[ m = \frac{F}{g} = \frac{45}{9.8} \approx 4.59 \text{ kg} \]Thus, the heaviest fish that can be pulled up at a constant speed weighs approximately \( 4.59 \) kg.
03

Identify Forces with Acceleration

When pulling the fish up with an acceleration of \(2.0 \text{ m/s}^2\), the tension in the line must support both the weight of the fish and provide the necessary additional force to accelerate it. The net force is given by \( F_{net} = T - mg \), where \( F_{net} = ma \).
04

Calculate the Net Force

Substitute \( T = ma + mg \) with \( T = 45 \text{ N} \), \( a = 2.0 \text{ m/s}^2 \) and \( g = 9.8 \text{ m/s}^2 \):\[ 45 = m(2.0 + 9.8) \]\[ 45 = m(11.8) \]
05

Solve for Maximum Mass with Acceleration

Solve the equation from Step 4:\[ m = \frac{45}{11.8} \approx 3.81 \text{ kg} \]So, the heaviest fish that can be pulled up with an acceleration of \(2.0 \text{ m/s}^2\) weighs approximately \( 3.81 \) kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension Force
Tension force is one of the fundamental concepts in physics, often encountered in situations involving ropes, strings, or lines that are pulled tight by forces acting from opposite ends. In our fishing scenario, tension is the force exerted by the fishing line to support or move the fish. It's crucial that the line can handle the forces without breaking.
The tension in the line has a maximum threshold, here represented as "45-N test line," meaning it can bear a maximum of 45 Newtons. When the fisherman reels in a fish with this line, the tension force counteracts the weight of the fish—the force due to gravity, which tries to pull the fish downward. If the tension exceeds 45 N, the line will snap, which underscores why it's essential to calculate tension correctly in practical applications such as fishing or engineering projects involving cables and wires.
Acceleration
Acceleration describes how quickly the speed of an object is changing. In physics, it is defined as the rate of change of velocity per unit time. In the fishing problem, acceleration comes into play when considering how quickly we are pulling the fish upwards.
At constant speed, the acceleration is zero, because the velocity isn't changing. Hence, the only force that needs to be provided by the tension in the line is the force to counteract gravity. However, when reeling the fish up with acceleration, additional force is needed because the fish is not only resisting its own weight due to gravity but also being moved faster against it. This means the tension must be greater than just balancing the weight of the fish to include the extra force for acceleration.
  • At constant speed: Zero acceleration, tension equals weight.
  • With acceleration: Tension needs to counteract both gravity and provide additional force to accelerate the fish.
This understanding helps us determine how much more force is necessary when accelerating, which directly affects how much weight a line can safely hold without breaking.
Net Force Calculation
Net force involves understanding the sum of all forces acting on an object. In any physical problem similar to our fishing scenario, net force is crucial for determining the dynamics of movement.
Net force ( F_{net} ) is what causes an object to accelerate, and can be calculated as the mass times the acceleration ( F_{net} = ma ). In our exercise, when the fisherman reels in the fish at an acceleration of 2.0 m/s², the net force needs to be carefully calculated to not exceed the tensile strength of the fishing line.
For the fish being pulled up, the forces include:
  • The gravitational force ( mg ): Acts downwards as the weight of the fish.
  • The tension force ( T ): Acts upwards to pull the fish up.
Considering these forces, the net force is given by the equation: F_{net} = T - mg . Therefore, when accelerating, the tension (T) must overcome not only the weight but also provide sufficient net force to achieve the required acceleration, all while ensuring T does not exceed 45 N. By calculating this carefully, we ensure the safety and integrity of the line and optimize the fishing process.

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