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When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is \(915 \mathrm{~N}\) and the drag force has a magnitude of \(1027 \mathrm{~N}\). The mass of the sky diver is \(93.4 \mathrm{~kg} .\) What are the magnitude and direction of his acceleration?

Short Answer

Expert verified
The acceleration is $1.20 \text{ m/s}^2$ upward.

Step by step solution

01

Identify the Forces

First, identify the forces acting on the skydiver. There are two primary forces: the weight of the skydiver (\(915 \text{ N}\), acting downward) and the drag force from the parachute (\(1027 \text{ N}\), acting upward).
02

Calculate the Net Force

The net force acting on the skydiver can be calculated using the formula:\[ F_{ ext{net}} = F_{ ext{drag}} - F_{ ext{weight}} \]Substitute the given values:\[ F_{ ext{net}} = 1027 \text{ N} - 915 \text{ N} = 112 \text{ N} \]
03

Determine the Direction of the Net Force

Since the drag force (\(1027 \text{ N}\)) is greater than the weight (\(915 \text{ N}\)), the net force is upward, indicating that the acceleration will also be upward.
04

Calculate the Acceleration

Use Newton's second law of motion:\[ a = \frac{F_{ ext{net}}}{m} \]where \(a\) is the acceleration, \(F_{ ext{net}} \text{ is } 112 \text{ N}\), and \(m \text{ is } 93.4 \text{ kg}\).Substitute the known values to find the acceleration:\[ a = \frac{112 \text{ N}}{93.4 \text{ kg}} \approx 1.20 \text{ m/s}^2 \]
05

Conclusion

The magnitude of the skydiver's acceleration is \(1.20 \text{ m/s}^2\), and its direction is upward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Drag Force and Its Role
When a skydiver opens their parachute, an interesting phenomenon occurs thanks to what's known as **drag force**. This force is essentially air resistance that acts in the opposite direction of the skydiver's motion. In the described scenario, the drag force reaches a magnitude of \(1027 \, \text{N}\), pointing upwards. This is a bit stronger than the simple weight force acting on the skydiver, which is \(915 \, \text{N}\) downward. So, what's going on here?
The drag force is pivotal because it impacts the speed and direction of the skydiver's movement. In this case, it is powerful enough to stop the skydiver from continuing downward at the same speed, resulting in a deceleration or a slowing down of the descent. This helps the skydiver come to a safer stop, using a natural counteracting force—air pressure. Without it, falling would be rapid and unsafe.
  • Drag force acts against motion.
  • Considerably contributes to slowing objects down.
  • Its magnitude is influenced by speed and surface area.
Understanding Net Force
The concept of **net force** is crucial here. Net force is basically the sum of all forces acting on an object—it determines the object's overall motion direction and acceleration. In this problem, we have two key forces: the drag force and the weight of the skydiver.

To determine the net force \( (F_{\text{net}}) \), we use the equation:
The net force is calculated by subtracting the weight from the drag force:
\[ F_{\text{net}} = F_{\text{drag}} - F_{\text{weight}} = 1027 \, \text{N} - 915 \, \text{N} = 112 \, \text{N} \]
This results in a **net force of 112 N upwards**, because the drag force exceeds the downward weight force. This means the overall force is upward, indicating upward acceleration.
  • Net force determines motion.
  • It helps define the overall direction of movement.
  • A balance of forces implies zero net force and no acceleration.
Acceleration Calculation Using Newton’s Second Law
Acceleration is a change in velocity and is directly linked to the forces at play through **Newton's Second Law**. This physical law states that the acceleration of an object is equal to the net force acting upon it, divided by its mass. It's a key player in determining how fast or slow the skydiver will change speed and direction.

The specific formula applied here is:
\[ a = \frac{F_{\text{net}}}{m} \]where \(a\) represents acceleration, \(F_{\text{net}}\) is the net force, and \(m\) is the mass of the skydiver. By inserting the solved value of net force (\(112 \, \text{N}\)) and the mass (\(93.4 \, \text{kg}\)) into the equation, we find:
\[ a = \frac{112 \, \text{N}}{93.4 \, \text{kg}} \approx 1.20 \, \text{m/s}^2 \]
This result reveals that the skydiver's acceleration is indeed upward at approximately \(1.20 \, \text{m/s}^2\).
  • Newton's Second Law offers a blueprint for acceleration.
  • Net force is critical in determining acceleration's direction and magnitude.
  • Higher forces or lower mass result in greater acceleration.

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Most popular questions from this chapter

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