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Concept Questions (a) Two diffraction gratings are located at the same distance from observation screens. Light with the same wavelength \(\lambda\) is used for each. The principal maxima of grating A are observed to be closer together on the screen than the principal maxima of grating B. Which grating diffracts the light to a greater extent? (b) Which grating has the smaller slit separation \(d ?\) (c) Which grating has the greater number of lines permeter? Justify each of your answers. Problem The separation between adjacent principal maxima for grating \(\mathrm{A}\) is \(2.7 \mathrm{~cm},\) and for grating \(\mathrm{B}\) it is \(3.2 \mathrm{~cm}\). Grating A has 2000 lines per meter. How many lines per meter does grating B have? The diffraction angles are small enough that \(\sin \theta \approx \tan \theta .\) Be sure that your answer is consistent with your answers to the Concept Questions.

Short Answer

Expert verified
Grating B diffracts light more, has smaller slit separation and more lines per meter (approximately 2300 lines/m).

Step by step solution

01

Analyzing Diffraction Extent

The principal maxima are closer together for grating A, which indicates it diffracts less. Therefore, grating B diffracts to a greater extent as its maxima are further apart, suggesting larger angles of diffraction.
02

Relating Slit Separation to Diffraction

According to the grating equation \(d \sin(\theta) = m \lambda\), a smaller slit separation \(d\) results in larger angles \(\theta\) for principal maxima, and thus further spaced maxima. Since B's maxima are further apart, grating B must have a smaller slit separation.
03

Determining Lines per Meter

The number of lines per meter \(N\) and slit separation \(d\) are related by \(d = \frac{1}{N}\). Therefore, if B has a smaller slit separation, it has more lines per meter compared to grating A.
04

Using Experimental Data for Grating B

Given grating A has 2000 lines/m, and the difference in separation of maxima is given, use the formula \(\Delta x = \frac{\lambda L}{d}\). Rearrange to find \(d_B\):\[ d_B = \frac{d_A \cdot \Delta x_B}{\Delta x_A} \] where \(d_A = \frac{1}{2000}\). Substitute \(\Delta x_A = 2.7\, \text{cm}\) and \(\Delta x_B = 3.2\, \text{cm}\).
05

Calculate Number of Lines for Grating B

Finding \(d_B\), use it to calculate \(N_B = \frac{1}{d_B}\) for the number of lines per meter for grating B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Maxima
In the context of diffraction gratings, **principal maxima** refer to the bright spots where constructive interference of light waves occurs. These maxima appear on a screen after light passes through a diffraction grating. The location of these maxima can be determined by using the equation: \[ d \sin(\theta) = m \lambda \] where:
  • \(d\) is the slit separation,
  • \(\theta\) is the angle of diffraction,
  • \(m\) is the order of the maxima (an integer),
  • \(\lambda\) is the wavelength of the light.
In a practical scenario, the position of principal maxima is observed as light and dark fringes on a screen.
The key point is that closer principal maxima indicate smaller angles of diffraction. This means the grating does not diffract light as much. Conversely, when maxima are further apart, it indicates greater diffraction.
By observing the distance between these bright spots, we can infer the diffraction behavior of the grating being examined.
Slit Separation
Slit separation, denoted as \(d\), is the distance between adjacent slits in a diffraction grating. It plays a crucial role in determining the diffraction pattern observed. In a diffraction experiment, the smaller the slit separation, the larger the angle \(\theta\) at which lines appear. This is due to the grating condition equation: \[ d \sin(\theta) = m \lambda \]
This equation implies that for a fixed wavelength \(\lambda\), a smaller \(d\) results in larger angles, causing the maxima (bright spots) to spread further apart on the observing screen. Hence, if a grating causes principal maxima to appear further apart, it likely has a smaller slit separation. Grating B, with its more widely spaced maxima than Grating A, would thus have a smaller \(d\). Understanding this concept helps in analyzing and comparing diffraction gratings based on their physical spacings.
Lines Per Meter
The concept of **lines per meter** is a way to describe the density or compactness of lines in a diffraction grating. It is the inverse of the slit separation \(d\), expressed as: \[ N = \frac{1}{d} \] where \(N\) represents lines per meter. A grating with a higher number of lines per meter has more closely spaced slits.
This increased density results in greater diffraction, as more lines create a larger cumulative interference effect. Therefore, a greater number of lines per meter will align with grating producing wider spaced maxima.
To find the number of lines per meter for a grating, if you know the slit separation from other physical parameters, just invert \(d\). For instance, if Grating B requires calculation, first determine \(d_B\) based on known parameters of Grating A and their separation differences, then use the above relationship to calculate \(N_B\).
Given the relationships covered, Grating B having maxima further apart reflects its higher lines per meter compared to Grating A, which has known 2000 lines/m.

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Most popular questions from this chapter

There are 5620 lines per centimeter in a grating that is used with light whose wavelength is \(471 \mathrm{~nm}\). A flat observation screen is located at a distance of \(0.750 \mathrm{~m}\) from the grating. What is the minimum width that the screen must have so the centers of all the principal maxima formed on either side of the central maximum fall on the screen?

A nonreflective coating of magnesium fluoride \((n=1.38)\) covers the glass \((n=1.52)\) of a camera lens. Assuming that the coating prevents reflection of yellow-green light (wavelength in vacuum \(=565 \mathrm{~nm}\) ), determine the minimum nonzero thickness that the coating can have.

Review Conceptual Example 2 before attempting this problem. Two slits are \(0.158 \mathrm{~mm}\) apart. A mixture of red light (wavelength \(=665 \mathrm{~nm}\) ) and yellow-green light (wavelength \(=565 \mathrm{~nm}\) ) falls on the slits. A flat observation screen is located \(2.24 \mathrm{~m}\) away. What is the distance on the screen between the third-order red fringe and the thirdorder yellow-green fringe?

A uniform layer of water \((n=1.33)\) lies on a glass plate \((n=1.52)\). Light shines perpendicularly on the layer. Because of constructive interference, the layer looks maximally bright when the wavelength of the light is \(432 \mathrm{~nm}\) in vacuum and also when it is \(648 \mathrm{~nm}\) in vacuum. (a) Obtain the minimum thickness of the film. (b) Assuming that the film has the minimum thickness and that the visible spectrum extends from 380 to \(750 \mathrm{~nm}\), determine the visible wavelength(s) (in vacuum) for which the film appears completely dark.

Three, and only three, bright fringes can be seen on either side of the central maximum when a grating is illuminated with light \((\lambda=510 \mathrm{~nm}) .\) What is the maximum number of lines \(/ \mathrm{cm}\) for the grating?

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