/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 (a) Two diffraction gratings are... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Two diffraction gratings are located at the same distance from observation screens. Light with the same wavelength \(\lambda\) is used for each. The principal maxima of grating \(\mathrm{A}\) are observed to be closer together on the screen than the principal maxima of grating \(\mathrm{B}\). Which grating diffracts the light to a greater extent? (b) Which grating has the smaller slit separation \(d ?(\mathrm{c})\) Which grating has the greater number of lines permeter? Justify each of your answers. The separation between adjacent principal maxima for grating \(\mathrm{A}\) is \(2.7 \mathrm{~cm}\), and for grating \(\mathrm{B}\) it is \(3.2 \mathrm{~cm}\). Grating \(\mathrm{A}\) has 2000 lines per meter. How many lines per meter does grating B have? The diffraction angles are small enough that \(\sin \theta \approx \tan \theta .\) Be sure that your answer is consistent with your answers to the Concept Questions.

Short Answer

Expert verified
Grating A diffracts more and has smaller slit separation. Grating B (1687.5 lines/m) has fewer lines than Grating A.

Step by step solution

01

Understanding Diffraction Maximum Spacing

Diffraction gratings produce principal maxima whose spacing is related to the slit separation \(d\), angle \(\theta\), and wavelength \(\lambda\) through the relationship \(d \cdot \sin \theta = m \cdot \lambda\), where \(m\) is the order of the maximum. For small angles, \(\sin \theta \approx \tan \theta\). Thus, the spacing \(x\) of the maxima on a screen at distance \(L\) is \(x = m \cdot \lambda \cdot L / d\). A larger \(d\) results in smaller \(\theta\) and larger spacing \(x\).
02

Comparing Grating Diffraction

Given the spacings of \(2.7\,\mathrm{cm}\) for Grating A and \(3.2\,\mathrm{cm}\) for Grating B, Grating A creates maxima that are closer together. This implies Grating A has smaller \(x\), indicating a larger diffraction angle \(\theta\). Therefore, Grating A diffracts light to a greater extent.
03

Relating Slit Separation and Line Density

A smaller slit separation \(d\) results in a greater diffraction angle \(\theta\), resulting in closer maxima spacing. Since Grating A has closer maxima, it implies a smaller slit separation than Grating B, so Grating A has the smaller slit separation.
04

Calculating Line Density for Grating B

Line density (\(N\), number of lines per meter) is the inverse of slit separation: \(N = 1/d\). Since Grating A has 2000 lines/m, \(d_A = 1/2000\). Given the spacing relationship for small angles, \(x_A/x_B = d_B/d_A\). Solving \(d_B/d_A = x_B/x_A = 3.2/2.7\), gives \(d_B = d_A \cdot (3.2/2.7)\). Therefore, \(N_B = 1/d_B = 2000 \cdot (2.7/3.2)\). Calculating gives \(N_B \approx 1687.5\) lines per meter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Maxima
In the context of diffraction gratings, principal maxima refer to the bright bands observed on a screen due to light interference. These maxima are formed when the path difference between light waves from adjacent slits results in constructive interference. This condition occurs when the path difference is a multiple of the wavelength, meaning that the waves from different slits align perfectly. Each bright band is associated with a particular order (\( m \)), and higher orders correspond to larger angles.

The position and spacing of principal maxima are crucial because they provide insights into the properties of the diffraction grating. For instance, closer spaced principal maxima, as seen with Grating A in the original exercise, suggest a more significant diffraction effect due to smaller slit separation or higher line density. Understanding these concepts helps in determining characteristics like the slit separation and diffraction angle, particularly when analyzing or designing experiments that involve light diffraction.
Line Density
Line density in a diffraction grating is a measure of the number of lines or slits per unit length, typically expressed as lines per meter. It's an inverse relationship with the slit separation, given by:\( N = \frac{1}{d} \) where \( N \) is the line density and \( d \) is the slit separation.

Line density is directly related to the grating's ability to diffract light. Gratings with a higher line density (\( N \)) will have smaller slit separations, resulting in greater angular spreading of light and closer principal maxima on the screen. This is why Grating A has a higher diffraction angle because it has higher line density due to 2000 lines per meter, compared to Grating B which has calculated to approximately 1687.5 lines per meter.
  • Higher line density = smaller \( d \)
  • Greater diffraction angle
  • Closer maxima spacing
Understanding line density is key to analyzing and differentiating between how different gratings interact with light.
Slit Separation
Slit separation, denoted by \( d \), is the distance between adjacent slits in a diffraction grating. It plays a critical role in determining the diffraction properties of the grating. The equation \(d \cdot \sin \theta = m \cdot \lambda\) shows that slit separation, in association with the diffraction angle, defines how much the light spreads after passing through the grating.

With smaller slit separations, the grating produces larger diffraction angles for the same order \( m \) and wavelength \( \lambda \), resulting in closely packed principal maxima. Conversely, larger slit separations yield smaller angles and thus more widely spaced maxima.

In the given exercise, we deduced that Grating A has a smaller slit separation than Grating B due to having greater diffraction angles. The observation that Grating A displayed maxima closer together was consistent with its smaller slit separation, which also aligns with what we found when computing their respective line densities.
Diffraction Angle
The diffraction angle, often denoted as \( \theta \), is the angle at which light exits the grating forming the principal maxima. This angle is a function of the order of the maximum, the wavelength of light, and the slit separation. For small angles, it is approximated that \( \sin \theta \approx \tan \theta \), allowing for simplified calculations of the positioning of the maxima on an observation screen.

Diffraction angle provides a direct measure of the light's spread caused by the grating. According to \(d \cdot \sin \theta = m \cdot \lambda\), smaller slit separations cause larger diffraction angles, leading to closely spaced bright fringes, as was the case with Grating A in this exercise.
  • Larger diffraction angles with smaller \( d \)
  • More spread out light pattern
  • Key in resolving light into its constituent parts
Understanding how to manipulate the diffraction angle via slit separation and light wavelength is essential for applications of diffraction gratings in spectroscopy and optics.

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Most popular questions from this chapter

Interactive LearningWare 27.2 at provides some pertinent background for this problem. A transparent film \((n=1.43)\) is deposited on a glass plate \((n=1.52)\) to form a nonreflecting coating. The film has a thickness that is \(1.07 \times 10^{-7} \mathrm{~m}\). What is the longest possible wavelength (in vacuum) of light for which this film has been designed?

The wavelength of the laser beam used in a compact disc player is \(780 \mathrm{~nm}\). Suppose that a diffraction grating produces first-order tracking beams that are \(1.2 \mathrm{~mm}\) apart at a distance of \(3.0 \mathrm{~mm}\) from the grating. Estimate the spacing between the slits of the grating.

In a single-slit diffraction pattern on a flat screen, the central bright fringe is \(1.2 \mathrm{~cm}\) wide when the slit width is \(3.2 \times 10^{-5} \mathrm{~m}\). When the slit is replaced by a second slit, the wavelength of the light and the distance to the screen remaining unchanged, the central bright fringe broadens to a width of \(1.9 \mathrm{~cm}\). What is the width of the second slit? It may be assumed that \(\theta\) is so small that \(\sin \theta \approx \tan \theta\).

Light shines on a diffraction grating, and a diffraction pattern is produced on a viewing screen that consists of a central bright fringe and higher-order bright fringes (see the drawing). (a) From trigonometry, how is the distance \(y\) from the central bright fringe to the second-order bright fringe related to the diffraction angle \(\theta\) and the distance \(L\) between the grating and the screen? (b) From physics, how is \(\theta\) related to the order \(m\) of the bright fringe, the wavelength \(\lambda\) of the light, and the separation \(d\) between the slits? (c) In this problem, the angle \(\theta\) is small (less than a few degrees). When the angle is small, \(\tan \theta\) is approximately equal to \(\sin \theta\), or \(\tan \theta \approx \sin \theta\). Using this approximation, obtain an expression for \(y\) in terms of \(L, m, \lambda\), and \(d\). (d) If the entire apparatus in the drawing is submerged in water, would you expect the distance \(y\) to increase, decrease, or remain unchanged? Why? Light of wavelength \(480 \mathrm{~nm}\) (in vacuum) is incident on a diffraction grating that has a slit separation of \(5.0 \times 10^{-7} \mathrm{~m}\). The distance between the grating and the viewing screen is \(0.15 \mathrm{~m}\). (a) Determine the distance \(y\) from the central bright fringe to the second-order bright fringe. (b) If the entire apparatus is submerged in water \(\left(n_{\text {water }}=1.33\right)\), what is the distance \(y ?\) Be sure your answer is consistent with part (d) of the Concept Questions.

Concept Questions Light shines on a diffraction grating, and a diffraction pattern is produced on a viewing screen that consists of a central bright fringe and higher-order bright fringes (see the drawing). (a) From trigonometry, how is the distance \(y\) from the central bright fringe to the second-order bright fringe related to the diffraction angle \(\theta\) and the distance \(L\) between the grating and the screen? (b) From physics, how is \(\theta\) related to the order \(m\) of the bright fringe, the wavelength \(\lambda\) of the light, and the separation \(d\) between the slits? (c) In this problem, the angle \(\theta\) is small (less than a few degrees). When the angle is small, \(\tan \theta\) is approximately equal to \(\sin \theta,\) or \(\tan \theta \approx \sin \theta .\) Using this approximation, obtain an expression for \(y\) in terms of \(L, m, \lambda,\) and \(d .\) (d) If the entire apparatus in the drawing is submerged in water, would you expect the distance \(y\) to increase, decrease, or remain unchanged? Why? Problem Light of wavelength \(480 \mathrm{nm}\) (in vacuum) is incident on a diffraction grating that has a slit separation of \(5.0 \times 10^{-7} \mathrm{~m}\). The distance between the grating and the viewing screen is \(0.15 \mathrm{~m}\). (a) Determine the distance \(y\) from the central bright fringe to the second-order bright fringe. (b) If the entire apparatus is submerged in water \(\left(n_{\text {water }}=1.33\right),\) what is the distance \(y\) ? Be sure your answer is consistent with part (d) of the Concept Questions.

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