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Three, and only three, bright fringes can be seen on either side of the central maximum when a grating is illuminated with light \((\lambda=510 \mathrm{~nm}) .\) What is the maximum number of lines \(/ \mathrm{cm}\) for the grating?

Short Answer

Expert verified
The maximum number of lines per cm is approximately 65359 lines/cm.

Step by step solution

01

Understand the diffraction grating formula

The diffraction grating formula is given by \(d \sin \theta = m\lambda\), where \(d\) is the distance between grating lines, \(\theta\) is the angle of diffraction, \(m\) is the order of the fringe, and \(\lambda\) is the wavelength of the light. The maximum order \(m\) is given as 3, since three bright fringes are observed on each side of the central maximum.
02

Calculate maximum grating line density

To maximize the number of lines per centimeter, we need the smallest possible distance \(d\). For optical fringe visibility up to the third order (\(m = 3\)), and for the angle \(\theta = 90^\circ\) at maximum, we apply \(\sin \theta = 1\). So, the equation \(d = \frac{m\lambda}{\sin \theta}\) becomes \(d = 3\times 510~\text{nm}\) or \(d = 1530~\text{nm}\).
03

Convert distance to lines per centimeter

The line density \(N\), in lines/cm is given by \(N = \frac{1}{d}\), where \(d\) is converted to cm. Use \(1~\text{nm} = 1 \times 10^{-7}~\text{cm}\), so \(d = 1530~\text{nm} = 1530 \times 10^{-7}~\text{cm}\). Calculating \(N\), we have \(N = \frac{1}{1530 \times 10^{-7}}\approx 65359 \text{ lines/cm}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interference Pattern
When light passes through a diffraction grating, it creates an interference pattern. This pattern comprises alternating bright and dark regions known as fringes. The creation of these fringes is a result of the superposition of multiple light waves that diffract through the closely spaced lines of the grating.

In a typical experiment, a central bright fringe appears at the zero-order position, where light waves add constructively. On either side of this central fringe, you will find higher-order fringes that decrease in intensity the further they are from the center. Three bright fringes on each side indicate up to three orders of constructive interference, providing insight into the properties of both the grating and the light used.
  • Constructive interference produces bright fringes.
  • Destructive interference results in dark fringes.
The pattern helps us analyze the property of light waves including the wavelength and the geometry of the grating.
Wavelength
Wavelength is a fundamental concept in understanding diffraction patterns. It is the physical length of one complete oscillation of a light wave, often denoted by the Greek letter \(\lambda\). In the given exercise, the wavelength is noted as 510 nm (nanometers), depicting the type of light illuminating the grating.

Shorter wavelengths diffract less than longer wavelengths for a given slit separation, affecting the distribution and count of visible fringes. Thus, the wavelength of light in experiments not only influences the position of the fringes but also the maximum observable order of interference.
  • Wavelength is crucial for determining fringe positions.
  • Higher wavelengths lead to wider spacing between fringes.
In practical applications, knowing the exact wavelength of light allows for precise calculations and setups in optical experiments.
Order of Fringe
The order of fringe, represented by \(m\), refers to the sequential number of the fringe in an interference pattern. For instance, the central bright fringe is the zero-order fringe, while subsequent bright fringes are first order, second order, and so on. In the exercise, an interference pattern showing three bright fringes on either side corresponds to a third-order fringe.

This ordinal classification is not arbitrary; it correlates directly with how much the path difference between waves corresponds to whole multiples of the light's wavelength. The order of the fringe helps determine the geometry of the fringe pattern, especially its relationship with the angle \(\theta\) in the diffraction grating formula:
\[d \sin \theta = m\lambda\]
  • Zero order fringe: Central and brightest.
  • First to third order fringes: Dependent on path difference.
Understanding this concept enables predictions about where and how fringes will appear when light interacts with structures like gratings.
Line Density
Line density, often denoted as \(N\), is a measure of how many lines per centimeter are present on a diffraction grating. It plays a critical role in determining the resolution and effectiveness of the grating in producing an interference pattern. The greater the line density, the higher the angle at which higher-order fringes appear.

In the context of this exercise, line density is calculated using the minimum distance between lines \(d\). This value represents the inverse of \(d\) after converting it to a metric compatible with the line density formula. Here, higher line density translates into a finer grating that can separate more closely spaced spectral lines.
  • Higher line density leads to better spectral resolution.
  • Calculated as: \(N = \frac{1}{d}\).
Recognizing the importance of line density helps in designing experiments and devices where precise control over light is needed, such as spectrometers and various optical instruments.

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Most popular questions from this chapter

In Young's experiment a mixture of orange light \((611 \mathrm{nm})\) and blue light \((471 \mathrm{nm})\) shines on the double slit. The centers of the first- order bright blue fringes lie at the outer edges of a screen that is located \(0.500 \mathrm{~m}\) away from the slits. However, the first-order bright orange fringes fall off the screen. By how much and in which direction (toward or away from the slits) should the screen be moved, so that the centers of the first-order bright orange fringes just appear on the screen? It may be assumed that \(\theta\) is small, so that \(\sin \theta \approx \tan \theta\).

Two in-phase sources of waves are separated by a distance of \(4.00 \mathrm{~m}\). These sources produce identical waves that have a wave length of \(5.00 \mathrm{~m}\). On the line between them, there are two places at which the same type of interference occurs. (a) Is it constructive or destructive interference, and (b) where are the places located?

Light shines on a diffraction grating, and a diffraction pattern is produced on a viewing screen that consists of a central bright fringe and higher-order bright fringes (see the drawing). (a) From trigonometry, how is the distance \(y\) from the central bright fringe to the second-order bright fringe related to the diffraction angle \(\theta\) and the distance \(L\) between the grating and the screen? (b) From physics, how is \(\theta\) related to the order \(m\) of the bright fringe, the wavelength \(\lambda\) of the light, and the separation \(d\) between the slits? (c) In this problem, the angle \(\theta\) is small (less than a few degrees). When the angle is small, \(\tan \theta\) is approximately equal to \(\sin \theta\), or \(\tan \theta \approx \sin \theta\). Using this approximation, obtain an expression for \(y\) in terms of \(L, m, \lambda\), and \(d\). (d) If the entire apparatus in the drawing is submerged in water, would you expect the distance \(y\) to increase, decrease, or remain unchanged? Why? Light of wavelength \(480 \mathrm{~nm}\) (in vacuum) is incident on a diffraction grating that has a slit separation of \(5.0 \times 10^{-7} \mathrm{~m}\). The distance between the grating and the viewing screen is \(0.15 \mathrm{~m}\). (a) Determine the distance \(y\) from the central bright fringe to the second-order bright fringe. (b) If the entire apparatus is submerged in water \(\left(n_{\text {water }}=1.33\right)\), what is the distance \(y ?\) Be sure your answer is consistent with part (d) of the Concept Questions.

A sheet that is made of plastic \((n=1.60)\) covers one slit of a double slit (see the drawing). When the double slit is illuminated by monochromatic light \(\left(\lambda_{\text {vacuum }}=586 \mathrm{nm}\right),\) the center of the screen appears dark rather than bright. What is the minimum thickness of the plastic?

Under these conditions the pupils of your eyes have diameters of about \(7.0 \mathrm{~mm}\). The taillights of this car are separated by a distance of \(1.2 \mathrm{~m}\) and emit red light (wavelength \(=660 \mathrm{~nm}\) in vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction?

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