/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 A series RCL circuit includes a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A series RCL circuit includes a resistance of \(275 \Omega,\) an inductive reactance of \(648 \Omega\), and a capacitive reactance of \(415 \Omega\). The current in the circuit is 0.233 A. What is the voltage of the generator?

Short Answer

Expert verified
The voltage of the generator is approximately 84.00 V.

Step by step solution

01

Calculate Impedance

The impedance \( Z \) in a RCL series circuit can be calculated using the formula: \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \] where \( R \) is the resistance, \( X_L \) is the inductive reactance, and \( X_C \) is the capacitive reactance. Let's substitute the values: \[ Z = \sqrt{275^2 + (648 - 415)^2} \] Simplifying inside the parentheses first: \( 648 - 415 = 233 \). Now substitute back: \[ Z = \sqrt{275^2 + 233^2} \] Calculate \( 275^2 = 75625 \) and \( 233^2 = 54289 \). Thus, \[ Z = \sqrt{75625 + 54289} = \sqrt{129914} \approx 360.36 \Omega \].
02

Calculate Voltage

Using Ohm's Law, the voltage \( V \) across the circuit can be calculated as \( V = I \times Z \), where \( I \) is the current. Given \( I = 0.233 \) A and \( Z \approx 360.36 \Omega \), we calculate \[ V = 0.233 \times 360.36 \approx 84.00 \text{ V} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impedance Calculation
Understanding impedance in a series RCL circuit is essential to analyze how the circuit behaves when connected to an AC source. Impedance, symbolized by \( Z \), is the total opposition a circuit offers to the flow of alternating current. It combines the effects of resistance \( R \), inductive reactance \( X_L \), and capacitive reactance \( X_C \).

In this context, impedance is calculated using the formula:
  • \( Z = \sqrt{R^2 + (X_L - X_C)^2} \)
This formula shows that impedance is not simply the sum of the resistances, like in DC circuits. Instead, it accounts for the phase differences caused by the inductive and capacitive reactances. In the original exercise, substituting the values for \( R \), \( X_L \), and \( X_C \) into the formula, we find:

  • \( 648 - 415 = 233 \) for reactance difference,
  • \( Z = \sqrt{275^2 + 233^2} \approx 360.36 \Omega \).
Thus, this calculated impedance represents how the RCL circuit reacts to an AC source.
Ohm's Law
Ohm's Law is a fundamental principle used to relate voltage, current, and resistance in electrical circuits. The law is expressed as:
  • \( V = I \times Z \)
where \( V \) is the voltage, \( I \) is the current, and \( Z \) is impedance. In AC circuits, this equation is particularly useful and helps in calculating how much voltage is needed across a component or a whole circuit to sustain a specific current flow.

In the problem provided, we use Ohm's Law to find the voltage supplied by the generator. Given the current \( I = 0.233 \text{ A} \) and the impedance \( Z \approx 360.36 \Omega \), the voltage is:

  • \( V = 0.233 \times 360.36 \approx 84.00 \text{ V} \)
This calculated voltage is what the generator must supply to keep the current constant through the circuit with the given impedance.
Inductive Reactance
Inductive reactance, symbolized as \( X_L \), is a measure of a coil or inductor's opposition to changes in current. It takes into account the frequency of the alternating current and the inductance of the coil. The formula is:
  • \( X_L = 2\pi f L \)
where \( f \) is the frequency and \( L \) is the inductance.

In an AC circuit, inductors create a phase shift between voltage and current. This phase shift results in energy being temporarily stored in the magnetic field and then returned to the circuit. The opposition to AC, the inductive reactance \( X_L \), affects the overall impedance \( Z \). For the exercise, it affects the total impedance calculation as given.

It's important to note that unlike regular resistive opposition, inductive reactance is frequency-dependent, increasing as the frequency of the AC source increases. The given value \( 648 \Omega \) highlights the significant role of this component in opposition.
Capacitive Reactance
Capacitive reactance, symbolized as \( X_C \), is the opposition that a capacitor presents to the flow of alternating current. It is a function of the capacitance and the frequency of the AC source. Mathematically, it is expressed as:
  • \( X_C = \frac{1}{2\pi f C} \)
where \( C \) is the capacitance.

Capacitors store energy in an electric field, and this energy gives rise to capacitive reactance in AC circuits. This introduces a phase shift where the current leads the voltage in phase. Capacitive reactance decreases with an increase in frequency, as opposed to inductive reactance.

In the exercise, \( X_C = 415 \Omega \) indicates how much opposition is provided by the capacitive element. It plays a key role in determining the net reactance and impedance. Understanding \( X_C \) is vital, as it influences how the circuit responds at different frequencies.

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Most popular questions from this chapter

At what frequency (in \(\mathrm{Hz}\) ) are the reactances of a \(52-\mathrm{mH}\) inductor and a \(76-\mu \mathrm{F}\) capacitor equal?

A charged capacitor and an inductor are connected as shown in the drawing (this circuit is the same as that in Figure \(23-16 a\) ). There is no resistance in the circuit. As Section \(23.4\) discusses, the electrical energy initially present in the charged capacitor then oscillates back and forth between the inductor and the capacitor. (a) What is the amount of electrical energy initially stored in the capacitor? Express your answer in terms of its capacitance \(C\) and the magnitude \(q\) of the charge on each plate. (b) A little later, this energy is transferred completely to the inductor (see Figure \(23-16 b\) ). Write down an expression for the energy stored in the inductor. Give your answer in terms of its inductance \(L\) and the magnitude \(I_{\max }\) of the maximum current in the inductor. (c) If values for \(q, C\), and \(L\) are known, how could one obtain a value for the maximum current in the inductor? Remember that energy is conserved. Problem The initial charge on the capacitor has a magnitude of \(q=2.90 \mu \mathrm{C}\). The capacitance is \(C=3.60 \mu \mathrm{F}\), and the inductance is \(L=75.0 \mathrm{mH}\). (a) What is the electrical energy stored initially in the charged capacitor? (b) Find the maximum current in the inductor.

A series RCL circuit has a resonant frequency of \(1500 \mathrm{~Hz}\). When operating at a frequency other than \(1500 \mathrm{~Hz}\), the circuit has a capacitive reactance of \(5.0 \Omega\) and an inductive reactance of \(30.0 \Omega .\) What are the values of (a) \(L\) and (b) \(C ?\)

Refer to Interactive Solution \(\underline{23.23}\) at for help with problems like this one. A series RCL circuit contains only a capacitor \((C=6.60 \mu \mathrm{F}),\) an inductor \((L=7.20 \mathrm{mH}),\) and a generator (peak voltage \(=32.0 \mathrm{~V},\) frequency \(=1.50 \times 10^{3} \mathrm{~Hz}\) ). When \(t=0 \mathrm{~s},\) the instantaneous value of the voltage is zero, and it rises to a maximum one-quarter of a period later. (a) Find the instantaneous value of the voltage across the capacitor/inductor combination when \(t=1.20 \times 10^{-4} \mathrm{~s}\). (b) What is the instantaneous value of the current when \(t=1.20 \times 10^{-4} \mathrm{~s}\) ? (Hint: The instantaneous values of the voltage and current are, respectively, the vertical components of the voltage and current phasors.)

Part \(a\) of the drawing shows a resistor and a charged capacitor wired in series. When the switch is closed, the capacitor discharges as charge moves from one plate to the other. Part \(b\) shows a plot of the amount of charge remaining on each plate of the capacitor as a function of time. (a) What does the time constant \(\tau\) of this resistor-capacitor circuit physically represent? (b) How is the time constant related to the resistance \(R\) and the capacitance \(C ?(\mathrm{c})\) In part \(c\) of the drawing, the switch has been removed and an ac generator has been inserted into the circuit. What is the impedance \(Z\) of this circuit? Express your answer in terms of the resistance \(R\), the time constant \(\tau\), and the frequency \(f\) of the generator. Problem The circuit elements in the drawing have the following values: \(R=18 \Omega\) \(V_{\mathrm{rms}}=24 \mathrm{~V}\) for the generator, and \(f=380 \mathrm{~Hz}\). The time constant for the circuit is \(\tau=3.0 \times 10^{-4} \mathrm{~s}\). What is the rms current in the circuit?

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