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At what frequency (in \(\mathrm{Hz}\) ) are the reactances of a \(52-\mathrm{mH}\) inductor and a \(76-\mu \mathrm{F}\) capacitor equal?

Short Answer

Expert verified
The reactances are equal at approximately 80.15 Hz.

Step by step solution

01

Define Reactance Formulas

The reactance of an inductor is given by the formula \(X_L = 2 \pi f L\), where \(X_L\) is the inductive reactance, \(f\) is the frequency, and \(L\) is the inductance. The reactance of a capacitor is \(X_C = \frac{1}{2 \pi f C}\), where \(X_C\) is the capacitive reactance, and \(C\) is the capacitance.
02

Set Reactances Equal

To find the frequency where the reactances are equal, set the equations equal to each other: \(2 \pi f L = \frac{1}{2 \pi f C}\).
03

Solve for Frequency

Rearrange the equation to solve for \(f\): \(f^2 = \frac{1}{(2\pi)^2 LC}\). Taking the square root, we get \(f = \frac{1}{2\pi\sqrt{LC}}\).
04

Substitute Values

Substitute \(L = 52 \times 10^{-3} \text{ H}\) and \(C = 76 \times 10^{-6} \text{ F}\) into the equation: \[f = \frac{1}{2\pi\sqrt{52 \times 10^{-3} \times 76 \times 10^{-6}}}\].
05

Calculate the Frequency

Perform the calculation inside the square root: \(52 \times 10^{-3} \times 76 \times 10^{-6} = 3.952 \times 10^{-6}\). Then take the square root: \(\sqrt{3.952 \times 10^{-6}} = 1.987 \times 10^{-3}\), so \[f = \frac{1}{2\pi \times 1.987 \times 10^{-3}}\]. Finally, compute the result: \(f \approx 80.15 \text{ Hz}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductive Reactance
Inductive reactance, symbolized by \(X_L\), is an important concept in alternating current (AC) circuits involving inductors. It measures how much an inductor opposes the flow of AC current. This opposition comes from the inductor's magnetic field generated when current flows through it.
\(X_L\) is calculated using the formula:
  • \(X_L = 2 \pi f L\)
This formula shows that inductive reactance depends on both the frequency \(f\) of the AC signal and the inductance \(L\) itself.
As frequency increases, so does the inductive reactance, making it harder for AC signals to pass through. Consequently, inductors are more effective at blocking higher frequencies. This principle is critical in designing filters and tuning circuits.
Capacitive Reactance
The concept of capacitive reactance, \(X_C\), involves a capacitor's opposition to changes in voltage in an AC circuit. Unlike resistance, which affects both AC and direct current (DC), reactance varies with frequency.
Capacitive reactance can be calculated using the formula:
  • \(X_C = \frac{1}{2 \pi f C}\)
In this equation, \(f\) is the frequency of the AC signal and \(C\) is the capacitance.
An important point is that capacitive reactance decreases as frequency increases, allowing higher frequencies to pass through more easily. This property makes capacitors useful for applications such as filtering and signal coupling, where the passage of high-frequency signals is often required.
Frequency Calculation
Frequency calculation in circuits with both inductors and capacitors involves setting their reactances equal to find a specific frequency where they balance each other out. This particular frequency is known as the resonant frequency.
To find this resonant frequency \(f\), use:
  • Set \(2 \pi f L = \frac{1}{2 \pi f C}\)
  • Solve for \(f\): \(f^2 = \frac{1}{(2\pi)^2 LC}\)
  • Finally, \(f = \frac{1}{2\pi\sqrt{LC}}\).
This equivalent frequency is critical in many applications like radios and TVs, where it is exploited to select specific frequencies out of a broad spectrum of signals.
Inductor
An inductor is a passive electrical component that stores energy within a magnetic field created by the flow of electric current. It typically consists of a coil made from wire, often wrapped around a core of ferromagnetic material.
Inductors are characterized by their inductance, \(L\), measured in Henries (H). This parameter indicates how effectively the inductor can store energy. In AC circuits, inductors have inductive reactance that increases with frequency, impeding the flow of current.
These components are essential in:
  • Inductive loops for sensing applications
  • Chokes in power supply to block high-frequency interference
  • Tuning devices for adjusting signal frequencies in communication devices
Capacitor
A capacitor is a passive electrical device that stores energy in a static electric field. It comprises two conductive plates separated by an insulating material or dielectric. The ability of a capacitor to store charge is measured as capacitance, \(C\), expressed in Farads (F).
Unlike resistors, capacitors do not dissipate energy; instead, they temporarily hold and release it, playing a crucial role in AC circuits where rapid voltage changes occur. Capacitive reactance decreases with increasing frequency, thus facilitating the passage of AC signals over sections of the circuit where DC is blocked.
Capacitors find applications in:
  • Decoupling circuits to smooth power supply voltages
  • Filter circuits to allow or block specific frequencies
  • Timing devices in oscillators and clocks

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Most popular questions from this chapter

When a resistor is connected by itself to an ac generator, the average power delivered to the resistor is \(1.000 \mathrm{~W}\). When a capacitor is added in series with the resistor, the power delivered is \(0.500 \mathrm{~W}\). When an inductor is added in series with the resistor (without the capacitor), the power delivered is \(0.250 \mathrm{~W}\). Determine the power delivered when both the capacitor and the inductor are added in series with the resistor. Section 23.4 Resonance in Electric Circuits

A series RCL circuit has a resonant frequency of \(1500 \mathrm{~Hz}\). When operating at a frequency other than \(1500 \mathrm{~Hz}\), the circuit has a capacitive reactance of \(5.0 \Omega\) and an inductive reactance of \(30.0 \Omega .\) What are the values of (a) \(L\) and (b) \(C ?\)

A capacitor is connected across an ac generator whose frequency is \(750 \mathrm{~Hz}\) and whose peak output voltage is \(140 \mathrm{~V}\). The rms current in the circuit is \(3.0 \mathrm{~A}\). (a) What is the capacitance of the capacitor? (b) What is the magnitude of the maximum charge on one plate of the capacitor?

A capacitor is connected across the terminals of an ac generator that has a frequency of \(440 \mathrm{~Hz}\) and supplies a voltage of \(24 \mathrm{~V}\). When a second capacitor is connected in parallel with the first one, the current from the generator increases by 0.18 A. Find the capacitance of the second capacitor.

A \(2700-\Omega\) resistor and a \(1.1-\mu F\) capacitor are connected in series across a generator \((60.0 \mathrm{~Hz}, 120 \mathrm{~V}) .\) Determine the power delivered to the circuit.

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