/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A circular coil \((950\) turns, ... [FREE SOLUTION] | 91Ó°ÊÓ

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A circular coil \((950\) turns, radius \(=0.060 \mathrm{~m})\) is rotating in a uniform magnetic field. At \(t=0 \mathrm{~s}\), the normal to the coil is per pendicular to the magnetic field. At \(t=0.010 \mathrm{~s}\) the normal makes an angle of \(\phi=45^{\circ}\) with the field because the coil has made oneeighth of a revolution. An average emf of magnitude \(0.065 \mathrm{~V}\) is induced in the coil. Find the magnitude of the magnetic field at the location of the coil.

Short Answer

Expert verified
The magnetic field magnitude is approximately 8.60 x 10^{-5} T.

Step by step solution

01

Understanding the Problem

We need to find the magnitude of the magnetic field (\( B \)) that causes an average electromotive force (emf) of 0.065 V to be induced in a coil. The coil has 950 turns and a radius of 0.060 m, and it rotates such that the normal to the coil makes an angle of 45° to the magnetic field at 0.010 seconds.
02

Calculate the Area of the Coil

The area (\( A \)) of the circular coil is given by the formula \( A = \pi r^2 \), where \( r \) is the radius.\[A = \pi (0.060)^2 = 0.0113 \text{ m}^2\]
03

Determine the Change in Magnetic Flux

The change in magnetic flux (\( \Delta \Phi \)) can be calculated using Faraday's Law. The average emf induced in the coil is given by:\[|\text{emf}| = N \frac{\Delta \Phi}{\Delta t}\]where \( N \) is the number of turns and \( \Delta t \) is the change in time (0.010 s). Given that \( |\text{emf}| = 0.065 \text{ V} \), we rearrange this to find \( \Delta \Phi \).\[\Delta \Phi = \frac{|\text{emf}| \cdot \Delta t}{N} = \frac{0.065 \times 0.010}{950} = 6.8421 \times 10^{-7} \text{ Wb}\]
04

Calculate the Magnetic Field Contribution

The change in magnetic flux is also given by:\[\Delta \Phi = B \cdot A \cdot \Delta(\cos \phi)\]Initially, \( \phi = 90^\circ \) (cos = 0), and at \( t = 0.010 \) s, \( \phi = 45^\circ \) (cos = \( \frac{1}{\sqrt{2}} \)). So,\[\Delta(\cos \phi) = \cos 45^\circ - \cos 90^\circ = \frac{1}{\sqrt{2}} - 0 = \frac{1}{\sqrt{2}}\]Rearranging to solve for \( B \) gives:\[B = \frac{\Delta \Phi}{A \cdot \Delta(\cos \phi)} = \frac{6.8421 \times 10^{-7}}{0.0113 \times \frac{1}{\sqrt{2}}} = 8.60 \times 10^{-5} \text{ T}\]
05

Conclusion

The magnitude of the magnetic field at the location of the coil is found to be approximately 8.60 \( \times 10^{-5} \) T (Teslas).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle in electromagnetism, which describes how a change in magnetic flux through a coil induces an electromotive force (emf). According to this law, the induced emf in any closed circuit is directly proportional to the rate of change of the magnetic flux through the circuit. Mathematically, this is expressed as: \[ \text{emf} = -\frac{d\Phi}{dt} \] where \( \Phi \) is the magnetic flux. The law highlights the interplay between electricity and magnetism and forms the basis for many electrical devices like generators and transformers. In the context of our exercise, the coil experiences a change in magnetic flux due to its rotation, leading to the generation of an induced emf.
Electromotive Force (emf)
Electromotive force, or emf, is the energy provided by a source to drive electric current through a circuit. It is measured in volts and often confused with the voltage, though emf is the source force, not the potential difference between two points. When a magnetic field through a loop or coil changes, it results in the generation of emf. In the given problem, the rotating coil experiences an average induced emf of 0.065 V. This is because the change in orientation of the coil with respect to the magnetic field alters the magnetic flux, thus creating emf as per Faraday's Law. This emf is what could drive current if the loop were connected in a circuit.
Circular Coil
A circular coil is a loop or series of loops arranged in a circular shape. In this exercise, the coil has 950 turns and a radius of 0.060 m. The geometry of a coil is significant in determining the area involved when calculating magnetic flux. The area \( A \) of a circular coil is calculated using the formula: \[ A = \pi r^2 \] where \( r \) is the radius of the coil. Greater number of turns and larger area increase the total magnetic flux that can pass through the coil, making it more efficient in inducing emf when subject to changes in magnetic fields.
Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking into account the strength and the extent of a magnetic field. It is represented by the symbol \( \Phi \) and measured in webers (Wb). The magnetic flux through a surface (such as a coil) is calculated as: \[ \Phi = B \cdot A \cdot \cos\phi \] where \( B \) is the magnetic field strength, \( A \) is the area through which the field lines pass, and \( \phi \) is the angle between the magnetic field lines and the normal (perpendicular) to the surface. In the problem, the coil rotates causing the angle \( \phi \) to change, thus changing the value of \( \cos\phi \) and the magnetic flux. The difference in flux over time is used to calculate the emf and ultimately helps in determining the magnetic field strength where the coil is located.

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Most popular questions from this chapter

A \(3.0-\mu\) F capacitor has a voltage of 35 V between its plates. What must be the current in a 5.0 -mH inductor, such that the energy stored in the inductor equals the energy stored in the capacitor?

Suppose there are two transformers between your house and the high-voltage transmission line that distributes the power. In addition, assume your house is the only one using electric power. At a substation the primary of a step- down transformer (turns ratio \(=1: 29\) ) receives the voltage from the high- voltage transmission line. Because of your usage, a current of \(48 \mathrm{~mA}\) exists in the primary of this transformer. The secondary is connected to the primary of another step-down transformer (turns ratio \(=1: 32\) ) somewhere near your house, perhaps up on a telephone pole. The secondary of this transformer delivers a 240-V emf to your house. How much power is your house using? Remember that the current and voltage given in this problem are rms values.

A vacuum cleaner is plugged into a \(120.0-\mathrm{V}\) socket and uses 3.0 A of current in normal operation when the back emf generated by the electric motor is \(72.0 \mathrm{~V}\). Find the coil resistance of the motor.

The drawing shows a copper wire (negligible resistance) bent into a circular shape with a radius of \(0.50 \mathrm{~m} .\) The radial section \(B C\) is fixed in place, while the copper bar \(A C\) sweeps around at an angular speed of \(15 \mathrm{rad} / \mathrm{s}\). The bar makes electrical contact with the wire at all times. The wire and the bar have negligible resistance. A uniform magnetic field exists everywhere, is perpendicular to the plane of the circle, and has a magnitude of \(3.8 \times 10^{-3} \mathrm{~T}\). Find the magnitude of the current induced in the \(\operatorname{loop} A B C .\)

A piece of copper wire is formed into a single circular loop of radius \(12 \mathrm{~cm}\). A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to \(0.60 \mathrm{~T}\) in a time of \(0.45 \mathrm{~s}\). The wire has a resistance per unit length of \(3.3 \times 10^{-2} \Omega / \mathrm{m}\). What is the average electrical energy dissipated in the resistance of the wire?

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