/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 The drawing shows a copper wire ... [FREE SOLUTION] | 91Ó°ÊÓ

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The drawing shows a copper wire (negligible resistance) bent into a circular shape with a radius of \(0.50 \mathrm{~m} .\) The radial section \(B C\) is fixed in place, while the copper bar \(A C\) sweeps around at an angular speed of \(15 \mathrm{rad} / \mathrm{s}\). The bar makes electrical contact with the wire at all times. The wire and the bar have negligible resistance. A uniform magnetic field exists everywhere, is perpendicular to the plane of the circle, and has a magnitude of \(3.8 \times 10^{-3} \mathrm{~T}\). Find the magnitude of the current induced in the \(\operatorname{loop} A B C .\)

Short Answer

Expert verified
The induced current in the loop is approximately 0.007125 A.

Step by step solution

01

Use Faraday's Law of Induction

First, we need to apply Faraday's Law of Electromagnetic Induction. Faraday's Law states that the emf (electromotive force) induced in a loop is equal to the negative rate of change of magnetic flux through the loop. The formula is given by \ \( \mathcal{E} = -\frac{d\Phi_B}{dt} \).
02

Calculate the Change in Magnetic Flux

The magnetic flux \( \Phi_B \) through the loop is given by \( \Phi_B = B \cdot A \), where \( B \) is the magnetic field and \( A \) is the area of the sector swept by bar \( AC \). Since \( A = \frac{1}{2} r^2 \theta \) for a circle sector, we have \ \( \frac{d\Phi_B}{dt} = B \cdot \frac{dA}{dt} = B \cdot \frac{1}{2} r^2 \frac{d\theta}{dt} \). \( \frac{d\theta}{dt} \) is the angular speed \( \omega \), which is given as 15 rad/s.
03

Calculate the Induced Emf

Substitute the known values to find the induced emf: \ \( \mathcal{E} = B \cdot \frac{1}{2} r^2 \omega = 3.8 \times 10^{-3} \times \frac{1}{2} \times (0.50)^2 \times 15 \). Calculate \( \mathcal{E} \) to find the total induced emf in the loop.
04

Calculate Induced Current Using Ohm's Law

According to Ohm's Law, \( \mathcal{E} = I \cdot R \), where \( I \) is the current and \( R \) is resistance. Since the resistance is negligible, the emf \( \mathcal{E} \) equals the current \( I \). Therefore, the induced current \( I \approx \mathcal{E} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Induction
Electromagnetic induction is a fascinating phenomenon. It allows a changing magnetic field to generate an electric current in a conductor. This process is at the heart of Faraday's Law of Induction. The foundational principle here is that when magnetic flux through a loop or coil of wire changes, it induces an electromotive force (emf) in the loop. This change can happen due to varying the magnetic field strength, the area of the loop, or the orientation of the field relative to the loop.
In our exercise, the movement of the copper bar, sweeping around at a constant angular speed in a magnetic field, changes the magnetic flux through the loop. This incident provides a practical example of Faraday's Law, explaining how mechanical motion is transformed into electrical energy.
Magnetic Flux
Magnetic flux ( \[ \Phi_B \]) is a measure of the amount of magnetic field passing through a given area. Think of it as counting the number of magnetic field lines passing through a loop. In mathematical terms, it is defined as the product of the magnetic field ( \( B \)) and the area ( \( A \)) it penetrates, i.e., \( \Phi_B = B \cdot A \).
In the context of our scenario, the area is the sector area swept by the movable bar. This area changes as the bar rotates, altering the magnetic flux through the loop. The rate at which this flux changes is crucial for inducing emf. Therefore, understanding how magnetic flux varies with respect to the area and magnetic field is vital for solving such problems.
Angular Speed
Angular speed is the rate at which an object rotates or revolves relative to another point. In our situation, it describes how fast the copper bar rotates around the circle's center. Angular speed is conveyed in radians per second (rad/s), a unit that makes sense in circular motion contexts because of the natural relationship with the angle's arc length.
For the rotating bar, the angular speed ( \( \omega \)) is constant at 15 rad/s, directly affecting the calculation of changing area swept by the bar. Knowing the angular speed allows us to determine how quickly the area and thus the magnetic flux is changing. This rate is key to determining the induced emf in the loop through Faraday’s principle. Therefore, angular speed is an integral part of linking mechanical movement to electromagnetic outcomes.
Ohm's Law
Ohm's Law is a fundamental principle in electronics and electricity. It states that the current ( \( I \)) flowing through a conductor between two points is directly proportional to the voltage ( \( \, \mathcal{E} \, \)) across the two points and inversely proportional to the resistance ( \( R \)). Expressed as \( \mathcal{E} = I \cdot R \), it becomes a linchpin for understanding electrical circuits.
In the exercise scenario, the goal is to determine the current induced by the emf due to changing magnetic flux. If resistance is negligible, as it is in our copper wire setup, the induced emf equals the induced current. This simplification means that \( I \approx \mathcal{E} \), highlighting how the rotatory system transforms its motion into an almost instant current in the loop. Understanding this relationship through Ohm’s Law is crucial for connecting the dots from mechanical rotation, through electromagnetic induction, to electrical current generation.

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Most popular questions from this chapter

The batteries in a portable CD player are recharged by a unit that plugs into a wall socket. Inside the unit is a step-down transformer with a turns ratio of \(1: 13 .\) The wall socket provides \(120 \mathrm{~V}\). What voltage does the secondary coil of the transformer provide?

A flat coil of wire has an area \(A\), \(N\) turns, and a resistance \(R\). It is situated in a magnetic field such that the normal to the coil is parallel to the magnetic field. The coil is then rotated through an angle of \(90^{\circ}\), so that the normal becomes perpendicular to the magnetic field. (a) Why is an emf induced in the coil? (b) What determines the amount of induced current in the coil? (c) How is the amount of charge \(\Delta q\) that flows related to the induced current \(I\) and the time interval \(t-t_{0}\) during which the coil rotates? The coil has an area of \(1.5 \times 10^{-3} \mathrm{~m}^{2}, 50\) turns, and a resistance of \(140 \Omega\). During the time when it is rotating, a charge of \(8.5 \times 10^{-5} \mathrm{C}\) flows in the coil. What is the magnitude of the magnetic field?

Two \(0.68\) -m-long conducting rods are rotating at the same speed in opposite directions, and both are perpendicular to a 4.7-T magnetic field. As the drawing shows, the ends of these rods come to within \(1.0 \mathrm{~mm}\) of each other as they rotate. Moreover, the fixed ends about which the rods are rotating are connected by a wire, so these ends are at the same electric potential. If a potential difference of \(4.5 \times 10^{3} \mathrm{~V}\) is required to cause a \(1.0\) -mm spark in air, what is the angular speed (in \(\mathrm{rad} / \mathrm{s}\) ) of the rods when a spark jumps across the gap?

Mutual induction can be used as the basis for a metal detector. A typical setup uses two large coils that are parallel to each other and have a common axis. Because of mutual induction, the ac generator connected to the primary coil causes an emf of \(0.46 \mathrm{~V}\) to be induced in the secondary coil. When someone without metal objects walks through the coils, the mutual inductance and, thus, the induced emf do not change much. But when a person carrying a hand gun walks through, the mutual inductance increases. The change in emf can be used to trigger an alarm. If the mutual inductance increases by a factor of three, find the new value of the induced emf.

A piece of copper wire is formed into a single circular loop of radius \(12 \mathrm{~cm}\). A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to \(0.60 \mathrm{~T}\) in a time of \(0.45 \mathrm{~s}\). The wire has a resistance per unit length of \(3.3 \times 10^{-2} \Omega / \mathrm{m}\). What is the average electrical energy dissipated in the resistance of the wire?

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