/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A piece of copper wire is formed... [FREE SOLUTION] | 91Ó°ÊÓ

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A piece of copper wire is formed into a single circular loop of radius \(12 \mathrm{~cm}\). A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to \(0.60 \mathrm{~T}\) in a time of \(0.45 \mathrm{~s}\). The wire has a resistance per unit length of \(3.3 \times 10^{-2} \Omega / \mathrm{m}\). What is the average electrical energy dissipated in the resistance of the wire?

Short Answer

Expert verified
The average electrical energy dissipated is approximately 0.0657 J.

Step by step solution

01

Calculate the Circumference of the Loop

First, we need to find the total length of the wire, which is the circumference of the circular loop. The formula for the circumference of a circle is given by \( C = 2\pi r \), where \( r \) is the radius. With a radius \( r = 12 \text{ cm} = 0.12 \text{ m} \), the circumference is \( C = 2 \pi \times 0.12 \text{ m} = 0.24\pi \text{ m} \approx 0.7536 \text{ m} \).
02

Calculate the Total Resistance of the Wire

The resistance of the wire is calculated by multiplying the resistance per unit length by the length of the wire. Therefore, \( R = \text{resistance per unit length} \times \text{length of wire} = 3.3 \times 10^{-2} \Omega/\text{m} \times 0.7536 \text{ m} \approx 0.02486 \Omega \).
03

Calculate the Change in Magnetic Flux

The magnetic flux \( \Phi \) through the loop is given by \( \Phi = B \times A \), where \( B \) is the magnetic field and \( A \) is the area of the loop. The area \( A \) is \( \pi r^2 \), giving \( A = \pi \times (0.12)^2 \text{ m}^2 \approx 0.04524 \text{ m}^2 \). The change in magnetic field is from 0 to \( 0.60 \text{ T} \), so the change in flux is \( \Delta \Phi = 0.60 \text{ T} \times 0.04524 \text{ m}^2 = 0.027144 \text{ Wb} \).
04

Calculate the Induced EMF

According to Faraday's Law, the induced electromotive force (EMF) is equal to the rate of change of magnetic flux through the loop, expressed as \( \varepsilon = -\frac{\Delta \Phi}{\Delta t} \). Substituting the known values, \( \varepsilon = -\frac{0.027144 \text{ Wb}}{0.45 \text{ s}} \approx -0.06032 \text{ V} \).
05

Calculate the Average Power Dissipated

The power dissipated in the loop, \( P \), is given by \( P = \frac{\varepsilon^2}{R} \). Substituting the known EMF and resistance, we get \( P = \frac{(0.06032)^2}{0.02486} \approx 0.146 \text{ W} \).
06

Calculate the Total Energy Dissipated

The total energy dissipated is the average power multiplied by the time duration: \( E = P \times \Delta t = 0.146 \text{ W} \times 0.45 \text{ s} \approx 0.0657 \text{ J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, considering the strength and extent of a magnetic field. It is often denoted by the symbol \( \Phi \) and is calculated by the product of the magnetic field \( B \) and the perpendicular area \( A \) through which it passes.
In mathematical terms, magnetic flux is given by the formula:
  • \( \Phi = B \times A \)
For a circular loop with a radius, the area \( A \) is calculated using the formula for the area of a circle, \( A = \pi r^2 \). In our example, this results in \( 0.04524 \text{ m}^2 \), where \( r = 0.12 \text{ m}\).
As the magnetic field changes from 0 to 0.60 T, the change in magnetic flux \( \Delta \Phi \) becomes \( 0.027144 \text{ Wb} \) (Weber is the unit for magnetic flux).
This change in magnetic flux is key to understanding the induced electrical effects in conductive loops.
Faraday's Law
Faraday's Law of electromagnetic induction plays a crucial role in determining how electrical energy is generated via a changing magnetic field.
This law states that the induced electromotive force (EMF) in any closed circuit is equal to the negative rate of change of the magnetic flux through the circuit. The expression for Faraday's Law is:
  • \( \varepsilon = -\frac{\Delta \Phi}{\Delta t} \)
The negative sign indicates the direction of the induced EMF and current resulting from Lenz's Law, which opposes the change in magnetic flux.
In our scenario, the change in magnetic flux \( (0.027144 \text{ Wb}) \) over the period \( (0.45 \text{ s}) \) results in an induced EMF of approximately \( -0.06032 \text{ V} \).
This induced EMF is what drives current through the wire, allowing us to explore further electrical phenomena.
EMF (Electromotive Force)
The electromotive force, or EMF, is not actually a force but a potential difference that drives current in a circuit. It is a critical concept when considering circuits where magnetic fields change, as it represents the energy per unit charge that is made available by the power source.
From Faraday's Law, we know that the EMF is directly linked to the change in magnetic flux. The formula, \( \varepsilon = -\frac{\Delta \Phi}{\Delta t} \), helps calculate this induced EMF.
For our example, this turns out to be \( -0.06032 \text{ V} \). This represents the average voltage generated across the loop as the magnetic field varies.
Understanding EMF is vital because it tells us how much energy is available to drive the current around the loop, overcoming the circuit's total resistance and leading to energy dissipation.
Resistance
Resistance is a measure of the opposition to the flow of current in an electric circuit. It is denoted by the symbol \( R \) and measured in Ohms \( \Omega \). In our problem, the wire's resistance per unit length affects how much overall resistance the circuit has.
To find the total resistance of the loop, you multiply the resistance per unit length by the circumference of the loop:
  • Total resistance formula: \( R = \text{resistance per unit length} \times \text{length of wire} \)
Given a resistance per unit length of \( 3.3 \times 10^{-2} \Omega/\text{m} \) and a circumference of \( 0.7536 \text{ m} \), the total resistance of the loop is approximately \( 0.02486 \Omega \).
This resistance impacts how efficiently electrical power is converted into other forms such as thermal energy when current flows through the wire.
Power Dissipation
Power dissipation refers to the process of electric energy being converted into heat in a resistive element, resulting in energy being 'dissipated' as waste heat. This occurs in any circuit with resistance, and the power dissipated is calculated using the formula:
  • \( P = \frac{\varepsilon^2}{R} \)
Here, \( P \) is the power (in watts), \( \varepsilon \) is the induced EMF, and \( R \) is the resistance. For our circuit, substituting \( \varepsilon = 0.06032 \text{ V} \) and \( R = 0.02486 \Omega \), the power dissipated is about \( 0.146 \text{ W} \).
The total energy dissipated over time can then be found by multiplying the power by the time duration \( \Delta t \), giving us a total energy dissipation of \( 0.0657 \text{ J} \).
Understanding power dissipation is important in all electrical and electronic applications as it helps gauge efficiency and reliability over time.

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Most popular questions from this chapter

Two coils of wire are placed close together. Initially, a current of 2.5 A exists in one of the coils, but there is no current in the other. The current is then switched off in a time of \(3.7 \times 10^{-2} \mathrm{~s}\). During this time, the average emf induced in the other coil is \(1.7 \mathrm{~V}\). What is the mutual inductance of the two-coil system?

Concept Questions The drawing shows a straight wire carrying a current \(I\). Above the wire is a rectangular loop that contains a resistor \(R\). (a) Does the magnetic field produced by the current \(I\) penetrate the loop and generate a magnetic flux? (b) When is there an induced current in the loop, if the current \(I\) is constant or if it is decreasing in time? (c) When there is an induced magnetic field produced by the loop, does it always have a direction that is opposite to the direction of the magnetic field produced by the current \(I\) ? Provide a reason for each answer. Problem If the current \(I\) is decreasing in time, what is the direction of the induced current through the resistor \(R\) - left to right or right to left? Give your reasoning.

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is \(50: 1\). The primary coil is plugged into a standard \(120-V\) outlet. The current in the secondary coil is \(1.7 \times 10^{-3} \mathrm{~A}\). Find the power consumed by the air filter.

A magnetic field is passing through a loop of wire whose area is \(0.018 \mathrm{~m}^{2}\). The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of \(0.20 \mathrm{~T} / \mathrm{s}\). (a) Determine the magnitude of the emf induced in the loop. (b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in \(\mathrm{m}^{2} / \mathrm{s}\) ) should the area be changed at the instant when \(B=1.8 \mathrm{~T}\) if the induced emf is to be zero? Explain whether the area is to be enlarged or shrunk.

A magnetic field has a magnitude of \(12 \mathrm{~T}\). What is the magnitude of an electric field that stores the same energy per unit volume as this magnetic field?

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