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One displacement vector \(\overrightarrow{\mathrm{A}}\) has a magnitude of \(2.43 \mathrm{~km}\) and points due north. A second displacement vector \(\overrightarrow{\mathbf{B}}\) has a magnitude of \(7.74 \mathrm{~km}\) and also points due north. (a) Find the magnitude and direction of \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}} \cdot(\mathrm{b})\) Find the magnitude and direction of \(\overrightarrow{\mathrm{B}}-\overrightarrow{\mathrm{A}}\)

Short Answer

Expert verified
(a) 5.31 km south, (b) 5.31 km north.

Step by step solution

01

Understand the Problem

We are given two displacement vectors \(\overrightarrow{\mathrm{A}}\) and \(\overrightarrow{\mathrm{B}}\) pointing due north with magnitudes of 2.43 km and 7.74 km, respectively. The task involves finding the magnitude and direction of \(\overrightarrow{\mathrm{A}} - \overrightarrow{\mathrm{B}}\) and \(\overrightarrow{\mathrm{B}} - \overrightarrow{\mathrm{A}}\).
02

Calculate \(\overrightarrow{\mathrm{A}} - \overrightarrow{\mathrm{B}}\)

When subtracting vectors that are collinear (point in the same or exact opposite direction), we simply subtract their magnitudes, keeping the sign according to their directions. Since both vectors point north, \(\overrightarrow{\mathrm{A}} - \overrightarrow{\mathrm{B}}\) results in: \[\overrightarrow{\mathrm{A}} - \overrightarrow{\mathrm{B}} = 2.43\, \mathrm{km} - 7.74\, \mathrm{km} = -5.31\, \mathrm{km}\] The negative sign indicates that the resultant vector points south.
03

Calculate \(\overrightarrow{\mathrm{B}} - \overrightarrow{\mathrm{A}}\)

Similarly, \(\overrightarrow{\mathrm{B}} - \overrightarrow{\mathrm{A}}\) involves subtracting the magnitude of \(\overrightarrow{\mathrm{A}}\) from \(\overrightarrow{\mathrm{B}}\): \[\overrightarrow{\mathrm{B}} - \overrightarrow{\mathrm{A}} = 7.74\, \mathrm{km} - 2.43\, \mathrm{km} = 5.31\, \mathrm{km}\]Since the result is positive, the resultant vector points north.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement Vectors
Displacement vectors are used to represent movement from one position to another in a particular direction. These vectors not only have a magnitude, which represents the distance, but also a direction, pointing from the starting location to the end location.
In physics, and especially in this particular problem, displacement vectors are very helpful in simplifying complex problems to simple linear movements along a specified path.
  • Magnitude: This tells us how far an object has moved.
  • Direction: Gives us the path of movement, such as north or east.
In our exercise, we worked with two displacement vectors, \(\overrightarrow{\mathrm{A}}\) and \(\overrightarrow{\mathbf{B}}\), both pointing due north. Each vector indicates a specific movement along the north-south line. The task was to find the resultant displacement when we subtract these vectors from one another.
Magnitude and Direction
When dealing with vectors, finding the magnitude and direction of the resultant vector is crucial. The magnitude of a vector is found by calculating the scalar length of the vector. The direction describes where the vector points relative to a reference direction (e.g., north, south).
For the problem at hand, the magnitude and direction are determined by subtracting the respective vector components, as both vectors are aligned:
  • Resultant Magnitude: Subtract the smaller magnitude from the larger one.
  • Direction of Resultant: Assign the direction based on the sign of the result. A positive result leads to a northward direction, while a negative result reflects a southward direction.
In step 2 of our solution, \(\overrightarrow{\mathrm{A}} - \overrightarrow{\mathrm{B}}\) gives us a magnitude of -5.31 km, indicating a southward direction, while \(\overrightarrow{\mathbf{B}} - \overrightarrow{\mathrm{A}}\) results in +5.31 km, pointing north.
Collinear Vectors
Collinear vectors refer to vectors that lie along the same line. This means they either point in the same direction or directly opposite directions. Understandably, their manipulation simplifies into mere algebraic addition or subtraction, primarily because their directional components align perfectly.
For vectors like \(\overrightarrow{\mathrm{A}}\) and \(\overrightarrow{\mathbf{B}}\), both moving due north, they are collinear.
This establishes some simplifying rules:
  • Additive Nature: When vectors point similarly, their magnitudes add up.
  • Subtractive Nature: For opposite directions, magnitudes subtract, revealing a difference indicating either a reverse direction or a lesser magnitude.
In our task, since \(\overrightarrow{\mathrm{A}}\) and \(\overrightarrow{\mathbf{B}}\) align, their subtraction was straightforward, resulting in either a positive (northward) or negative (southward) direction, based solely on the subtraction sequence.

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Most popular questions from this chapter

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply force \(\overrightarrow{\mathbf{F}}_{\mathbf{A}}\), as part \(a\) of the drawing shows. By itself, however, force \(\overrightarrow{\mathbf{F}}_{\mathbf{A}}\) is insufficient. Therefore, two additional forces \(\overrightarrow{\mathbf{F}}_{\mathbf{B}}\) and \(\overrightarrow{\mathbf{F}}_{\mathbf{C}}\) are applied, as in part \(b\) of the drawing. Each of these additional forces has the same magnitude \(F\). The magnitude of the resultant force acting on the elephant in part \(b\) of the drawing is twice that in part \(a\). Find the ratio \(F / F_{\mathrm{A}}\).

The gondola ski lift at Keystone, Colorado, is \(2830 \mathrm{~m}\) long. On average, the ski lift rises \(14.6^{\circ}\) above the horizontal. How high is the top of the ski lift relative to the base?

Two ropes are attached to a heavy box to pull it along the floor. One rope applies a force of 475 newtons in a direction due west; the other applies a force of 315 newtons in a direction due south. As we will see later in the text, force is a vector quantity. (a) How much force should be applied by a single rope, and (b) in what direction (relative to due west), if it is to accomplish the same effect as the two forces added together?

Three forces are applied to an object, as indicated in the drawing. Force \(\overrightarrow{\mathbf{F}}_{1}\) has a magnitude of 21.0 newtons \((21.0 \mathrm{~N})\) and is directed \(30.0^{\circ}\) to the left of the \(+y\) axis. Force \(\overrightarrow{\mathbf{F}}_{2}\) has a magnitude of \(15.0 \mathrm{~N}\) and points along the \(+x\) axis. What must be the magnitude and direction (specified by the angle \(\theta\) in the drawing) of the third force \(\overrightarrow{\mathrm{F}} 3\) such that the vector sum of the three forces is \(0 \mathrm{~N}\) ?

Before starting this problem, review Interactive Solution \(\underline{1.29}\) at. Vector \(\overrightarrow{\mathrm{A}}\) has a magnitude of 12.3 units and points due west. Vector \(\vec{B}\) points due north. (a) What is the magnitude of \(\overrightarrow{\mathbf{B}}\) if \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) has a magnitude of 15.0 units? (b) What is the direction of \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) relative to due west? (c) What is the magnitude of \(\overrightarrow{\mathrm{B}}\) if \(\overrightarrow{\mathrm{A}} \overrightarrow{\mathrm{B}}\) has a magnitude of 15.0 units? (d) What is the direction of \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\) relative to due west?

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