/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 A circus performer begins his ac... [FREE SOLUTION] | 91Ó°ÊÓ

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A circus performer begins his act by walking out along a nearly horizontal high wire. He slips and falls to the safety net, \(25.0 \mathrm{ft}\) below. The magnitude of his displacement from the beginning of the walk to the net is \(26.7 \mathrm{ft}\). (a) How far out along the high wire did he walk? (b) Find the angle that his displacement vector makes below the horizontal.

Short Answer

Expert verified
The performer walked 9.38 ft along the wire and the angle is 68.46° below horizontal.

Step by step solution

01

Understand the Given Information

We need to find two pieces of information: the horizontal distance walked along the high wire (let's call it \(x\)) and the angle of displacement below the horizontal. We are given that the vertical distance fallen is \(25.0\) ft and the total displacement is \(26.7\) ft.
02

Use the Pythagorean Theorem

The displacement forms the hypotenuse of a right triangle, where the vertical drop is one side, and the walk along the wire is the other side. Using the Pythagorean theorem, \(x^2 + 25.0^2 = 26.7^2\).
03

Solve for the Horizontal Distance

Substitute the given values into the equation: \(x^2 + 625 = 712.89\). Subtract 625 from both sides to get \(x^2 = 87.89\). Take the square root of both sides to find \(x = \sqrt{87.89} \approx 9.38\) ft.
04

Find the Angle Using Trigonometry

To find the angle \(\theta\) below the horizontal, use the sine function. Since \(\) we know \(\sin(\theta) = \frac{25}{26.7}\), calculate \(\theta = \arcsin\left(\frac{25}{26.7}\right)\).
05

Calculate the Angle

Calculate \(\theta \approx \arcsin(0.9367) \approx 68.46^\circ\). The displacement vector is \(68.46^\circ\) below the horizontal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right Triangle
In trigonometry, a right triangle is one that has one angle measuring exactly 90 degrees. This triangle is pivotal in solving many problems involving trigonometric relationships. Each right triangle comprises three main components:
  • The hypotenuse: This is the longest side opposite the right angle.
  • The adjacent side: This is the side next to the angle being considered.
  • The opposite side: This side faces the angle being studied.
In many applied physics problems, right triangles serve as a model for motion and force vectors, making them essential for calculations. When a circus performer falls from a height, their path can often form a right triangle, where aspects like vertical drop and horizontal movement are sides, and the path of the fall forms the hypotenuse.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. Mathematically, it's expressed as: \[ c^2 = a^2 + b^2 \]Where:
  • \(c\) is the hypotenuse,
  • \(a\) and \(b\) are the triangle's other two sides.
In the exercise, this theorem helps us find the distance the performer walked on the wire. Knowing the vertical drop and the total displacement (hypotenuse), we can apply it to solve for the horizontal distance. By rearranging and solving the formula, we find how far the performer managed to walk before his fall. This process of inserting known values and solving for the unknown is a common strategy in physics.
Displacement
Displacement is a vector quantity that refers to the change in position of an object. It has both magnitude and direction. Unlike distance, which only considers the path traveled, displacement measures how far out of place an object is from its original position. In the physics of a falling object, displacement can often be visualized as the direct line (the hypotenuse in this case) between the starting point and the final position. For our performer, the net displacement is the straight path he travels from the wire to the net, effectively forming the hypotenuse of the imaginary right triangle. Understanding the concept of displacement helps in visualizing physical movements as vectors.
Angle Calculation
Finding angles in right triangles is often done using trigonometric ratios such as sine, cosine, and tangent. These functions relate the triangle's angles to its side lengths. In this context, the sine of an angle is calculated as the ratio of the opposite side to the hypotenuse: \[\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}\]Using this formula helps us determine the angle at which displacement occurs relative to a base, or horizontal, line. In the reported problem, we used the sine function to determine the angle of descent below the horizontal. Given the measured values, solving this involves finding the arcsine of the ratio, leading to an angle of approximately \(68.46^\circ\). This angle describes how steeply the performer fell relative to his initial path.

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Most popular questions from this chapter

Can the \(x\) or \(y\) component of a vector ever have a greater magnitude than the vector itself has? Give your reasoning. Problem A force vector has a magnitude of 575 newtons and points at an angle of \(36.0^{\circ}\) below the positive \(x\) axis. What are (a) the \(x\) scalar component and (b) the \(y\) scalar component of the vector? Verify that your answers are consistent with your answer to the Concept Question.

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