/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A spring is hanging down from th... [FREE SOLUTION] | 91Ó°ÊÓ

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A spring is hanging down from the ceiling, and an object of mass \(m\) is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time \(T\) required for one complete up-and-down oscillation is given by the equation \(T=2 \pi \sqrt{m / k},\) where \(k\) is known as the spring constant. What must be the dimension of \(k\) for this equation to be dimensionally correct?

Short Answer

Expert verified
The dimension of \( k \) is \([MT^{-2}]\).

Step by step solution

01

Identify Dimensions in the Equation

The given equation is \( T=2 \pi \sqrt{m / k} \). We need to ensure the dimensional consistency of this equation. Start by identifying the dimensions of each term. \( T \), the period of oscillation, has the dimension of time \([T]\). The mass \( m \) has the dimension \([M]\). \( \pi \) is a dimensionless constant.
02

Rearrange the Equation

Rearrange the equation to isolate the square root term: \( T = 2\pi \cdot \sqrt{m/k} \). This becomes \( \sqrt{m/k} = T / (2\pi) \). Express \( m/k \) in terms of dimensions: \([T]^2 = [M] / [k]\). Therefore, \( [k] = [M] / [T]^2 \).
03

Determine the Dimension of k

From \([k] = [M] / [T]^2\), we see that \( [k] \) must have the dimension \( [MT^{-2}] \) to maintain dimensional consistency. This indicates that the spring constant \( k \) has the same dimension as force divided by distance or stiffness in physics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oscillation Period
The oscillation period, often denoted by the symbol \( T \), is the time it takes for an object to complete one full cycle of motion. In the case of a mass-spring system, this means moving from one point, extending to a limit, compressing back, and returning to the starting point. The period is crucial because it gives insights into how fast or slow the oscillations occur.

For a simple mass-spring system, the oscillation period is defined by the formula:\[ T = 2 \pi \sqrt{\frac{m}{k}} \]where:
  • \( T \) is the period of oscillation.
  • \( m \) represents the mass attached to the spring.
  • \( k \) is the spring constant, a measure of the spring's stiffness.
This formula demonstrates that the period is independent of the amplitude of the oscillation, which is one of the remarkable properties of harmonic oscillators.
Dimensional Analysis
Dimensional analysis is a powerful method for checking the correctness of equations and understanding the relationships between different physical quantities. It involves using the basic dimensions of mass \([M]\), length \([L]\), and time \([T]\) to express other physical quantities.

In the given exercise, we ensure dimensional correctness in the oscillation period formula by breaking down the units involved:
  • \( T \), being a period, has the dimension \([T]\).
  • Mass \( m \) has the dimension \([M]\).
  • The spring constant \( k \) needs to have a dimension that balances the equation, \([k] = [M][T]^{-2}\).
This analysis confirms that the dimensions on both sides of the equation match, maintaining the fundamental laws of physics that apply to dimensional equations. Dimensional analysis helps to simplify and solve complex physical problems by reducing them to their core components.
Mass-Spring System
A mass-spring system is a classic example of a simple harmonic oscillator, which illustrates the fundamental principles of physics involving mass, spring constants, and oscillatory motion.

This system consists of a spring attached to a mass, either suspended vertically or attached horizontally. When displaced, the spring exerts a restoring force proportional to the displacement (according to Hooke's Law). The force that the spring exerts is opposite to the direction of displacement and, consequently, causes the mass to oscillate. The oscillatory motion continues at a period \( T \), which we've seen depends on the mass and spring constant by the equation \( T = 2 \pi \sqrt{m / k} \).

In practical terms, the mass-spring system is important in understanding various physical systems. It's seen in vehicle suspensions, measuring devices like scales, and even in some everyday objects. The simplicity of the system helps students and scientists alike to explore the deeper concepts of dynamics and harmonic motion.

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Most popular questions from this chapter

Two bicyclists, starting at the same place, are riding toward the same campground by two different routes. One cyclist rides \(1080 \mathrm{~m}\) due east and then turns due north and travels another \(1430 \mathrm{~m}\) before reaching the campground. The second cyclist starts out by heading due north for \(1950 \mathrm{~m}\) and then turns and heads directly toward the campground. (a) At the turning point, how far is the second cyclist from the campground? (b) What direction (measured relative to due east) must the second cyclist head during the last part of the trip?

To review the solution to a similar problem, consult Interactive Solution \(1.37\) at . The magnitude of the force vector \(\vec{F}\) is \(82.3\) newtons. The \(x\) component of this vector is directed along the \(+x\) axis and has a magnitude of \(74.6\) newtons. The \(y\) component points along the \(+y\) axis. (a) Find the direction of \(\overrightarrow{\mathbf{F}}\) relative to the \(+x\) axis. (b) Find the component of \(\overrightarrow{\mathbf{F}}\) along the \(+y\) axis.

The components of vector \(\overrightarrow{\mathbf{A}}\) are \(A_{x}\) and \(A_{v}\) (both positive), and the angle that it makes with respect to the positive \(x\) axis is \(\theta\). (a) Does increasing the component \(A_{x}\) (while holding \(A_{y}\) constant) increase or decrease the angle \(\theta\) ? (b) Does increasing the component \(A_{y}\) (while holding \(A_{x}\) constant) increase or decrease the angle \(\theta\) ? Account for your answers. The components of displacement vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}=12 \mathrm{~m}\) and \(A_{y}=12 \mathrm{~m}\). Find \(\theta\). (b) The components of displacement vector \(\overrightarrow{\mathrm{A}}\) are \(A_{x}=17 \mathrm{~m}\) and \(A_{y}=12 \mathrm{~m}\). Find \(\theta\). (c) The components of displacement vector \(\overrightarrow{\mathbf{A}}\) are \(A_{x}=12 \mathrm{~m}\) and \(A_{y}=17 \mathrm{~m}\). Find \(\theta\). Be sure that your answers are consistent with your answers to the Concept

A circus performer begins his act by walking out along a nearly horizontal high wire. He slips and falls to the safety net, \(25.0 \mathrm{ft}\) below. The magnitude of his displacement from the beginning of the walk to the net is \(26.7 \mathrm{ft}\). (a) How far out along the high wire did he walk? (b) Find the angle that his displacement vector makes below the horizontal.

Bicyclists in the Tour de France reach speeds of 34.0 miles per hour \((\mathrm{mi} / \mathrm{h})\) on flat sections of the road. What is this speed in (a) kilometers per hour \((\mathrm{km} / \mathrm{h})\) and \((\mathrm{b})\) meters per second \((\mathrm{m} / \mathrm{s}) ?\)

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