/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Bicyclists in the Tour de France... [FREE SOLUTION] | 91Ó°ÊÓ

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Bicyclists in the Tour de France reach speeds of 34.0 miles per hour \((\mathrm{mi} / \mathrm{h})\) on flat sections of the road. What is this speed in (a) kilometers per hour \((\mathrm{km} / \mathrm{h})\) and \((\mathrm{b})\) meters per second \((\mathrm{m} / \mathrm{s}) ?\)

Short Answer

Expert verified
The speed is 54.7 km/h and 15.2 m/s.

Step by step solution

01

Convert miles per hour to kilometers per hour

To convert miles per hour to kilometers per hour, we use the conversion factor that 1 mile equals 1.60934 kilometers. Therefore, the speed of 34.0 miles per hour is converted as follows:\[34.0 \text{ mi/h} \times 1.60934 \frac{\text{km}}{\text{mi}} = 54.71756 \text{ km/h}\]
02

Round kilometers per hour to a reasonable precision

Round the calculated speed in kilometers per hour to a reasonable number of significant figures, considering the precision of the given data. Here, the initial data is given to 3 significant figures, so:\[54.71756 \text{ km/h} \approx 54.7 \text{ km/h}\]
03

Convert kilometers per hour to meters per second

Now we convert the speed from kilometers per hour to meters per second. We know that 1 kilometer is 1000 meters and 1 hour is 3600 seconds. Thus, the conversion is as follows:\[54.7 \text{ km/h} \times \frac{1000 \text{ m}}{1 \text{ km}} \times \frac{1 \text{ h}}{3600 \text{ s}} = 15.1944 \text{ m/s}\]
04

Round meters per second to a reasonable precision

Round the speed in meters per second to match the precision of the given data, which is 3 significant figures:\[15.1944 \text{ m/s} \approx 15.2 \text{ m/s}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kilometers per Hour
Kilometers per hour (km/h) is a unit used to measure speed, popular in many countries around the world. This unit tells us how many kilometers an object or person travels in one hour. It's essential for understanding speed in contexts such as road traffic regulations, where speed limits are often expressed in km/h. When converting miles per hour (mi/h) to kilometers per hour, a crucial conversion factor comes into play. Since 1 mile is equal to 1.60934 kilometers, you multiply the speed in miles per hour by 1.60934 to convert it into kilometers per hour. For instance, if a bicyclist moves at 34.0 mi/h, the speed in km/h would be:
  • 34.0 mi/h × 1.60934 km/mi = 54.71756 km/h
It's insightful to consider that various countries use different units for speed. In the United States, miles per hour is more common, while many other countries use kilometers per hour. Understanding these conversions helps you make sense of international speed data.
Moreover, when performing such conversions, it's useful to adjust the final figure to the appropriate number of significant figures, reflecting the precision with which you initially measured the speed.
Meters per Second
Meters per second (m/s) is another unit for measuring speed, commonly used in scientific contexts. It provides a direct measure of how many meters an object travels in one second, offering a more precise view of speed in shorter timeframes compared to kilometers per hour. To convert a speed given in km/h to m/s, you need to understand two basic equivalencies:
  • 1 kilometer is 1000 meters
  • 1 hour is 3600 seconds
Next, you perform the conversion by dividing the kilometers per hour by 3.6, since:
  • 54.7 km/h × (1000 m/km) × (1 h/3600 s) = 54.7 km/h ÷ 3.6 = 15.1944 m/s
Like with km/h, it's important to express m/s to the appropriate number of significant figures, especially when dealing with scientific data or when reporting precise speed values. Rounding to three significant figures provides consistency, given the precision of the initial input. For example, a calculated speed of 15.1944 m/s would be rounded to 15.2 m/s when reported.
Significant Figures
Significant figures are a way of expressing the precision of a number. They indicate which digits in a number are meaningful in the context of measurement accuracy. This concept is crucial in calculations and scientific reporting, as it helps determine how precisely figures should be reported. When rounding to significant figures, start from the first non-zero digit and continue counting until you reach the desired number of figures. It is important to remember:
  • The starting speed in the problem was 34.0 mi/h, which has three significant figures.
  • Thus, the converted speeds should be rounded to three significant figures, maintaining consistent precision.
For instance, after converting to km/h, an unrounded speed of 54.71756 km/h becomes 54.7 km/h. Similarly, for speeds in m/s, a detailed value of 15.1944 m/s is modified to 15.2 m/s, ensuring that these figures reflect the initial measurement's precision. Using significant figures properly maintains the integrity of data across calculations, ensuring that no false precision is implicated. Whether converting units or performing complex computations, sticking to the correct number of significant figures is crucial for accurate and reliable results.

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Most popular questions from this chapter

Vector \(\overrightarrow{\mathrm{A}}\) points due west, while vector \(\overrightarrow{\mathbf{B}}\) points due south. (a) Does the direction \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) point north or south of due west? (b) Does the direction of \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\) point north or south of due west? Give your reasoning in each case. Vector \(\overrightarrow{\mathbf{A}}\) has a magnitude of 63 units and points due west, while vector \(\overrightarrow{\mathbf{B}}\) has the same magnitude and points due south. Find the magnitude and direction of (a) \(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}\) and (b) \(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}\). Specify the directions relative to due west. Verify that your answers agree with your answers to the Concept Questions.

To review the solution to a similar problem, consult Interactive Solution \(1.37\) at . The magnitude of the force vector \(\vec{F}\) is \(82.3\) newtons. The \(x\) component of this vector is directed along the \(+x\) axis and has a magnitude of \(74.6\) newtons. The \(y\) component points along the \(+y\) axis. (a) Find the direction of \(\overrightarrow{\mathbf{F}}\) relative to the \(+x\) axis. (b) Find the component of \(\overrightarrow{\mathbf{F}}\) along the \(+y\) axis.

As preparation for this problem, consult Concept Simulation 1.1 at \(.\) On a safari, a team of naturalists sets out toward a research station located \(4.8 \mathrm{~km}\) away in a direction \(42^{\circ}\) north of east. After traveling in a straight line for \(2.4 \mathrm{~km}\), they stop and discover that they have been traveling \(22^{\circ}\) north of east, because their guide misread his compass. What are (a) the magnitude and (b) the direction (relative to due east) of the displacement vector now required to bring the team to the research station?

Can the \(x\) or \(y\) component of a vector ever have a greater magnitude than the vector itself has? Give your reasoning. Problem A force vector has a magnitude of 575 newtons and points at an angle of \(36.0^{\circ}\) below the positive \(x\) axis. What are (a) the \(x\) scalar component and (b) the \(y\) scalar component of the vector? Verify that your answers are consistent with your answer to the Concept Question.

Three deer, \(A, B,\) and \(C,\) are grazing in a field. Deer \(B\) is located \(62 \mathrm{~m}\) from deer \(A\) at an angle of \(51^{\circ}\) north of west. Deer \(\mathrm{C}\) is located \(77^{\circ}\) north of east relative to deer \(\mathrm{A}\). The distance between deer \(\mathrm{B}\) and \(\mathrm{C}\) is \(95 \mathrm{~m}\). What is the distance between deer \(\mathrm{A}\) and \(\mathrm{C} ?\)

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