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An apple of mass \(m=0.22 \mathrm{kg}\) falls from a tree and hits the ground with a speed of \(v=14 \mathrm{m} / \mathrm{s}\). (a) What is the magnitude of the force of gravity, \(m g,\) acting on the apple? (b) What is the time, \(t,\) required for the apple to reach the ground? (c) Show that the force of gravity times the time, \(m g t,\) is equal to mo. (We shall investigate the significance of this result in Chapter \(9 .\) ) Be sure to show that the dimensions are in agreement as well as the numerical values.

Short Answer

Expert verified
(a) 2.16 N; (b) 1.43 s; (c) mg \cdot t \approx mo, dimensions match.

Step by step solution

01

Introduction to Problem

We are given an apple with mass \( m = 0.22 \ kg \) that hits the ground at \( v = 14 \ m/s \). We need to find the force of gravity, the time of fall, and verify that \( mg \times t = mo \). We will assume a gravitational acceleration \( g \) of \( 9.81 \ m/s^2 \).
02

Calculate Force of Gravity

The force of gravity acting on an object is given by the formula \( F = mg \). We substitute the known values into the formula:\[ F = 0.22 \ kg \times 9.81 \ m/s^2 = 2.16 \ N \].So, the magnitude of the force of gravity is \( 2.16 \ N \).
03

Calculate Time to Reach the Ground

To find the time \( t \) it takes for the apple to reach the ground, we can use the kinematic equation. Since we know the initial velocity \( u = 0 \) (it starts from rest), final velocity \( v = 14 \ m/s \), and acceleration \( a = g = 9.81 \ m/s^2 \), we use the equation \[ v = u + at \].Rearrange to solve for \( t \):\[ t = \frac{v - u}{a} = \frac{14 \ m/s}{9.81 \ m/s^2} \approx 1.43 \ s \].
04

Verify mg * t = mo and Dimensions

We need to verify that the product \( mgt = mo \) where \( o = \) final velocity \( v \). Using our previous results:\[ mgt = 0.22 \ kg \times 9.81 \ m/s^2 \times 1.43 \ s \approx 3.09 \ kg \cdot m/s \].Our final velocity \( v = 14 \ m/s \) gives us momentum \( mo = 0.22 \ kg \times 14 \ m/s = 3.08 \ kg \cdot m/s \), which is about equal to \( mgt \). Checking dimensions, \( [mg] = N = kg \cdot m/s^2 \) and \( [t] = s \), so \( [mgt] = kg \cdot m/s \) just as \( [mo] = kg \cdot m/s \), confirming dimensional consistency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Equations
Kinematic equations are essential tools in physics for describing the motion of objects. They relate the variables of motion, namely displacement, initial velocity, final velocity, acceleration, and time, without involving the forces that cause the motion. In our example, the kinematic equation used is:\[ v = u + at \]This equation states that the final velocity \( v \) of an object is equal to its initial velocity \( u \) plus the product of acceleration \( a \) and time \( t \). For the apple falling from the tree, we assumed it started from rest, so \( u = 0 \). The acceleration due to gravity is represented by \( g \), which is \( 9.81 m/s^2 \). Using this formula, students can solve for the time duration of the fall, helping them understand how different factors influence motion.
Key points to remember about kinematic equations:
  • They do not take into account the causes of motion (like forces).
  • Each variable must be understood in terms of its initial and final states.
  • You can rearrange them to find unknown quantities.
Thus, kinematic equations provide a mathematically simple yet powerful way to analyze uniform acceleration problems.
Momentum
Momentum is an important concept in physics, representing the quantity of motion an object possesses. The momentum of an object is the product of its mass and velocity, given by \( p = mv \). It is a vector quantity, meaning it has both a magnitude and a direction. In our exercise, we explored how the gravitational force acting over time results in the momentum of the apple when it hits the ground.
Recognizing \( mg \times t = mo \), where \( o \) is the velocity of the apple, reveals how the force applied over the time of the fall results in a specific momentum. This relationship becomes especially significant when considering the conservation of momentum in systems where forces act over time.
Some important aspects of momentum include:
  • Momentum is conserved in isolated systems.
  • It provides insight into how forces impact motion over time.
  • It is closely linked with the concept of force and impulse.
Understanding momentum helps explain how objects move after collisions or in various force-related scenarios.
Dimensional Analysis
Dimensional analysis is a powerful tool in physics that allows us to check the consistency of physical equations. It involves analyzing the units or dimensions of the various quantities in an equation to ensure they make sense together. In the given exercise, dimensional analysis confirms the equivalence between \( mg \times t \) and \( mo \).
To break it down:
  • The force of gravity \( mg \) has the dimension \( [N] = [kg \cdot m/s^2] \).
  • Time \( t \) is measured in seconds \( [s] \).
  • Therefore, \( [mg \times t] = [kg \cdot m/s] \), matching the dimension of momentum \( [mo] = [kg \cdot m/s] \).
This agreement provides confidence in the correctness of our calculations and equations. Dimensional analysis is a quick way to verify formulas and understand the relationships between the physical quantities at play. While it may not offer precise numerical solutions, it serves as a useful check to prevent mistakes in physics problems and ensures comprehensive understanding of units across any equation.

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