/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A 92 -kg water skier floating in... [FREE SOLUTION] | 91Ó°ÊÓ

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A 92 -kg water skier floating in a lake is pulled from rest to a speed of \(12 \mathrm{m} / \mathrm{s}\) in a distance of \(25 \mathrm{m}\). What is the net force exerted on the skier, assuming his acceleration is constant?

Short Answer

Expert verified
The net force exerted on the skier is approximately 265 N.

Step by step solution

01

Identify Known Values

Let's identify and list the given values from the problem. The mass of the skier is \( m = 92 \text{ kg} \). The final speed is \( v_f = 12 \text{ m/s} \). The distance covered is \( s = 25 \text{ m} \). The initial speed \( v_i = 0 \text{ m/s} \) since the skier starts from rest.
02

Write the Equation for Acceleration

We need to find the acceleration using the kinematic equation. The equation relating the final velocity, initial velocity, acceleration, and distance is:\[v_f^2 = v_i^2 + 2a s\]We will use this equation to solve for \( a \).
03

Substitute Values to Find Acceleration

Substitute the known values into the equation and solve for acceleration \( a \):\[12^2 = 0 + 2a \times 25\]Solving this gives:\[144 = 50a \quad \Rightarrow \quad a = \frac{144}{50} = 2.88 \text{ m/s}^2\]
04

Use Newton's Second Law to Find Net Force

Newton's Second Law states that \( F = ma \), where \( F \) is the net force, \( m \) is the mass, and \( a \) is the acceleration. Substitute the values for mass and acceleration:\[F = 92 \times 2.88 = 264.96 \text{ N}\]
05

Final Answer

The net force exerted on the skier is approximately \( 265 \text{ N} \) when rounded to three significant figures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is an essential principle in physics that helps us to understand how forces affect motion. It states: \( F = ma \), where:
  • \( F \) is the net force applied to an object.
  • \( m \) is the mass of the object.
  • \( a \) is the acceleration caused by this force.
This law implies that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. If you apply more force, the object accelerates more. If the object is heavier, it takes more force to achieve the same acceleration.
In the context of the water skier problem, we used Newton's Second Law to find the net force needed to accelerate the skier from rest to a certain speed over a given distance. By determining the acceleration using kinematic equations and knowing the mass, we could then calculate the required net force.
Kinematics
Kinematics is the branch of physics that studies the motion of objects without considering the forces causing the motion. It focuses on understanding and predicting the trajectory of objects merely by using initial conditions and time.
  • Key equations relate displacement, velocity, acceleration, and time.
  • Kinematic equations help in solving motion problems when forces are not involved directly.

In our exercise, we used a kinematic equation to find the acceleration. The equation \( v_f^2 = v_i^2 + 2as \) allowed us to relate the final velocity, initial velocity, acceleration, and displacement. By inserting the known values, we isolated the acceleration which was integral to solving the next steps of the problem.
Constant Acceleration
The assumption of constant acceleration simplifies problems significantly. Constant acceleration means that an object's speed changes at a uniform rate over time.
  • This assumption allows us to use simple kinematic equations.
  • Real-world scenarios often approximate constant acceleration over short periods.

For the water skier, assuming constant acceleration enabled us to use the kinematic equation effectively. We calculated acceleration consistently throughout the skier's motion, from a starting velocity of 0 to the final speed of \(12\, \text{m/s}\). The assumption held because no significant changes in force or resistance were indicated during the skier's speed-up.
Physics Problem Solving
Physics problem solving involves understanding the problem, identifying known and unknown variables, and applying the right physical principles and formulas.
  • Break down problems into smaller steps: Identify what you know and what you need to find.
  • Choose appropriate equations based on the given information.
  • Substitute known values and solve systematically.

In the original exercise, the problem-solving process involved several key steps. By breaking it down, we identified the known variables, used a kinematic equation to find acceleration, and applied Newton's Second Law for the net force. This methodical approach simplifies complex problems into actionable tasks, guiding us towards the solution efficiently.

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Most popular questions from this chapter

When two people push in the same direction on an object of mass \(m\) they cause an acceleration of magnitude \(a_{1}\). When the same people push in opposite directions, the acceleration of the object has a magnitude \(a_{2}\). Determine the magnitude of the force exerted by each of the two people in terms of \(m, a_{1},\) and \(a_{2}\)

\- CE An object of mass \(m\) is initially at rest. After a force of magnitude \(F\) acts on it for a time \(T,\) the object has a speed \(v\). Suppose the mass of the object is doubled, and the magnitude of the force acting on it is quadrupled. In terms of \(T\), how long does it take for the object to accelerate from rest to a speed \(v\) now?

In a grocery store, you push a 12.3 -kg shopping cart with a force of \(10.1 \mathrm{N}\). If the cart starts at rest, how far does it move in \(2.50 \mathrm{s} ?\)

Suppose the initial speed of the driver is doubled to \(36.0 \mathrm{m} / \mathrm{s}\). If the driver still has a mass of \(65.0 \mathrm{kg}\), and comes to rest in \(1.00 \mathrm{m},\) what is the magnitude of the force exerted on the driver during this collision? A. \(648 \mathrm{N}\) B. \(1170 \mathrm{N}\) C. \(2.11 \times 10^{4} \mathrm{N}\) D. \(4.21 \times 10^{4} \mathrm{N}\)

\begin{aligned} &\text { "An object of mass } m=5.95 \mathrm{kg} \text { has an acceleration }\\\ &\overrightarrow{\mathrm{a}}=\left(1.17 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{x}}+\left(-0.664 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{y}} . \text { Three forces act on this }\\\ &\begin{array}{lllllll} \text { object: } \overline{\mathrm{F}}_{1}, & \overrightarrow{\mathrm{F}}_{2}, & \text { and } & \overrightarrow{\mathrm{F}}_{3} & \text { Given } & \text { that } & \overrightarrow{\mathrm{F}}_{1}=(3.22 \mathrm{N}) \hat{\mathrm{x}} & \text { and } \end{array}\\\ &\overrightarrow{\mathbf{F}}_{2}=(-1.55 \mathrm{N}) \hat{\mathrm{x}}+(2.05 \mathrm{N}) \hat{\mathrm{y}}, \text { find } \overrightarrow{\mathrm{F}}_{3} \end{aligned}

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