/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 In a grocery store, you push a 1... [FREE SOLUTION] | 91Ó°ÊÓ

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In a grocery store, you push a 12.3 -kg shopping cart with a force of \(10.1 \mathrm{N}\). If the cart starts at rest, how far does it move in \(2.50 \mathrm{s} ?\)

Short Answer

Expert verified
The shopping cart moves approximately 2.57 meters in 2.50 seconds.

Step by step solution

01

Calculate the Acceleration

To find the acceleration of the shopping cart, we use Newton's second law, which is given by the formula: \[ F = ma \]where \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration. Rearrange the formula to solve for acceleration \( a \) :\[ a = \frac{F}{m} \]Substitute \( F = 10.1 \text{ N} \) and \( m = 12.3 \text{ kg} \) into the equation:\[ a = \frac{10.1}{12.3} \approx 0.821 \text{ m/s}^2 \]
02

Determine Initial Velocity

Since the cart starts at rest, the initial velocity \( u \) of the cart is \( 0 \text{ m/s} \).
03

Use Kinematic Equation to Find Distance

To find the distance the cart travels in \( t = 2.50 \text{ s} \), use the kinematic equation:\[ s = ut + \frac{1}{2}at^2 \]where \( s \) is the distance, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time. Substitute the known values from the previous steps:\[ s = (0)(2.50) + \frac{1}{2}(0.821)(2.50)^2 \]\[ s = 0 + \frac{1}{2}(0.821)(6.25) \]\[ s = 0.4105 \times 6.25 \]\[ s = 2.566 \text{ meters} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Calculation
Acceleration is a key concept in physics that measures how quickly the velocity of an object changes over time. In the scenario given, Newton's Second Law provides us the starting point. The law states that the force on an object is equal to the mass of the object multiplied by its acceleration. This can be represented with the formula \( F = ma \). To calculate acceleration \( a \), you simply rearrange the formula to \( a = \frac{F}{m} \), where \( F \) is the force applied and \( m \) is the mass of the object.

Consider pushing a 12.3 kg shopping cart with a force of 10.1 N. Substituting the given values into the formula yields:
  • Acceleration \( a = \frac{10.1}{12.3} \approx 0.821 \text{ m/s}^2 \).
This means the cart's velocity increases at a rate of about 0.821 meters per second every second. Acceleration tells us not just the change, but the rate of that change as well.
Kinematic Equations
Kinematic equations help us describe the motion of objects without considering the forces that cause these motions. When you know an object's initial velocity, acceleration, and time period in motion, you can calculate various factors such as distance traveled. One helpful kinematic equation is:\[ s = ut + \frac{1}{2}at^2 \]where \( s \) is the distance, \( u \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.

In the given exercise, the shopping cart starts from rest, so the initial velocity \( u \) is 0. Plug in the acceleration we calculated earlier \( a \approx 0.821 \text{ m/s}^2 \) and the time \( t = 2.50 \text{ s} \):
  • \( s = 0 \times 2.50 + \frac{1}{2} \times 0.821 \times (2.50)^2 \)
  • \( s = 0 + \frac{1}{2} \times 0.821 \times 6.25 \)
  • \( s \approx 2.566 \text{ meters} \).
The cart moves approximately 2.566 meters in 2.50 seconds.
Force and Motion
Force and motion are intrinsically connected by Newton's laws of motion. Newton's Second Law explains how the forces acting on an object cause it to accelerate, impacting its motion. When you exert a force on an object, like pushing a shopping cart, you're affecting its speed and direction.

The formula \( F = ma \) highlights this direct connection between force and motion. The force you apply changes the velocity, demonstrating that motion requires a force to either change direction or speed. In the practical example at hand, the 10.1 N force applied on the 12.3 kg shopping cart is responsible for setting it into motion with a particular acceleration.

  • Without enough force, heavier objects resist motion due to their larger mass.
  • The direction of the motion depends on the direction of the applied force.
Understanding these principles helps you predict how objects will move in response to various forces encountered in everyday life.

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