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You are pulling your little sister on her sled across an icy (frictionless) surtace. When you exert a constant horizontal force of \(120 \mathrm{N},\) the sled has an acceleration of \(2.5 \mathrm{m} / \mathrm{s}^{2} .\) If the sled has a mass of \(7.4 \mathrm{kg},\) what is the mass of your little sister?

Short Answer

Expert verified
The mass of your little sister is 40.6 kg.

Step by step solution

01

Understand the Problem

We are given that a constant horizontal force of 120 N is exerted to pull a sled across a frictionless surface, resulting in an acceleration of 2.5 m/s². The sled itself has a known mass of 7.4 kg. We need to find the mass of the little sister who is also on the sled.
02

Apply Newton's Second Law

According to Newton's Second Law, the total force acting on an object is equal to the mass of the object times its acceleration. The law can be represented as:\[ F = m \cdot a \]where:- \( F \) is the total force applied,- \( m \) is the total mass being accelerated, and- \( a \) is the acceleration.
03

Calculate the Total Mass

Rearranging the equation from Newton's Second Law, we can solve for the total mass:\[ m = \frac{F}{a} \]Plug in the given values:\[ m = \frac{120 \text{ N}}{2.5 \text{ m/s}^2} = 48 \text{ kg} \]This means the combined mass of the sled and sister is 48 kg.
04

Find the Mass of the Sister

To find the mass of the sister, subtract the mass of the sled from the total mass:\[ m_{sister} = 48 \text{ kg} - 7.4 \text{ kg} = 40.6 \text{ kg} \]Thus, the mass of your little sister is 40.6 kg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
When we talk about force and acceleration, it's essential to understand how closely linked they are through Newton's Second Law. In simple terms, this law states that an object will accelerate when a force is applied to it, and the extent of this acceleration is dependent on the object's mass.
A fact-filled way to remember this relationship is by using the equation: \[ F = m \cdot a \]where:
  • \( F \) is the force applied, measured in newtons (N),
  • \( m \) is the mass of the object, measured in kilograms (kg),
  • \( a \) is the acceleration, measured in meters per second squared (m/s²).
In practical terms, if you exert a greater force, the acceleration increases, provided the mass remains constant. This is why pulling a sled with a constant force, as in our problem, results in a steady acceleration. Understanding this relationship helps us determine how objects move, crucial when calculating either force, mass, or acceleration in physical problems.
Mass Calculation
Mass calculation becomes essential when you want to understand the total 'weight' or amount of matter an object or group of objects possess. In our exercise, to find the mass of the little sister, we must first calculate the total mass of the system (sled plus sister).
The formula derived from Newton’s Second Law allows us to find total mass using known values of force and acceleration: \[ m = \frac{F}{a} \]Substituting the given values yields:\[ m = \frac{120\, \text{N}}{2.5\, \text{m/s}^2} = 48\, \text{kg} \]This number, 48 kg, represents the combined mass of both the sled and your sister. To isolate the mass of your sister, we subtract the sled's mass:\[ m_{sister} = 48\, \text{kg} - 7.4\, \text{kg} = 40.6\, \text{kg} \]Thus, through basic algebra and physics, we discover the sister's mass, emphasizing how forces and motions interconnect with mass determination.
Frictionless Surface
A frictionless surface represents an idealized condition in physics where an object moves without any resistance caused by friction. Imagine a perfectly smooth icy surface where a sled slides effortlessly.
On such a surface, the only force needed is the one that changes the object's speed or direction. There is no energy lost to frictional forces, leading to:
  • Greater efficiency in motion – all applied force contributes to acceleration.
  • Simplification of calculations, as you don't need to account for frictional force.
  • Ideal conditions to vividly see principles of physics, such as Newton’s laws, in action without external interferences.
The notion of a frictionless surface is useful when we wish to simplify problems and better understand the core physics at play, as it allows us to isolate forces and accelerations without worrying about unwanted distractions. However, in real life, complete frictionless scenarios are rare, but in physics problems, they are a great tool for learning the basics.

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Most popular questions from this chapter

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\begin{aligned} &\text { "An object of mass } m=5.95 \mathrm{kg} \text { has an acceleration }\\\ &\overrightarrow{\mathrm{a}}=\left(1.17 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{x}}+\left(-0.664 \mathrm{m} / \mathrm{s}^{2}\right) \hat{\mathrm{y}} . \text { Three forces act on this }\\\ &\begin{array}{lllllll} \text { object: } \overline{\mathrm{F}}_{1}, & \overrightarrow{\mathrm{F}}_{2}, & \text { and } & \overrightarrow{\mathrm{F}}_{3} & \text { Given } & \text { that } & \overrightarrow{\mathrm{F}}_{1}=(3.22 \mathrm{N}) \hat{\mathrm{x}} & \text { and } \end{array}\\\ &\overrightarrow{\mathbf{F}}_{2}=(-1.55 \mathrm{N}) \hat{\mathrm{x}}+(2.05 \mathrm{N}) \hat{\mathrm{y}}, \text { find } \overrightarrow{\mathrm{F}}_{3} \end{aligned}

The combination of "crumple zones" and air bags/seatbelts might increase the distance over which a person stops in a collision to as great as \(1.00 \mathrm{m}\). What is the magnitude of the force exerted on a \(65.0-\mathrm{kg}\) driver who decelerates from \(18.0 \mathrm{m} / \mathrm{s}\) to \(0.00 \mathrm{m} / \mathrm{s}\) over a distance of \(1.00 \mathrm{m} ?\) \(\mathbf{A} .162 \mathrm{N}\) B. \(585 \mathrm{N}\) C. \(1.05 \times 10^{4} \mathrm{N}\) D. \(2.11 \times 10^{4} \mathrm{N}\)

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