/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A child rides a pony on a circul... [FREE SOLUTION] | 91Ó°ÊÓ

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A child rides a pony on a circular track whose radius is \(4.5 \mathrm{m}\). (a) Find the distance traveled and the displacement after the child has gone halfway around the track. (b) Does the distance traveled increase, decrease, or stay the same when the child completes one circuit of the track? Explain. (c) Does the displacement increase, decrease, or stay the same when the child completes one circuit of the track? Explain. (d) Find the distance and displacement after a complete circuit of the track.

Short Answer

Expert verified
(a) Distance: \(\frac{9\pi}{2}\, \text{m}\), Displacement: \(9\, \text{m}\). (b) Distance increases. (c) Displacement decreases. (d) Distance: \(9\pi\, \text{m}\), Displacement: \(0\, \text{m}\).

Step by step solution

01

Calculate Halfway Distance

The circumference of a circle is given by the formula \(C = 2\pi r\), where \(r\) is the radius. With \(r = 4.5\, \text{m}\), the circumference of the track is \(2\pi \times 4.5 = 9\pi\, \text{m}\). Halfway around the track is half the circumference, so the distance traveled is \(\frac{9\pi}{2}\, \text{m}\).
02

Calculate Halfway Displacement

For a circle, if you go halfway, your displacement is a straight line from start to opposite side. This line is a diameter of the circle. The diameter is \(2r = 9\, \text{m}\).
03

Analyze Full Circuit Distance

When the child completes a full circle, the distance traveled is the same as the circumference, as they return to the starting point. The distance traveled is \(9\pi\, \text{m}\).
04

Determining Change in Distance

After a complete circuit, the distance traveled increases from halfway (\(\frac{9\pi}{2}\, \text{m}\)) to full (\(9\pi\, \text{m}\)). So, the distance traveled increases.
05

Analyze Full Circuit Displacement

Completing a full circuit means returning to the starting point. The displacement is the straight-line distance from the starting point to itself, which is \(0 \, \text{m}\).
06

Determining Change in Displacement

After a full circle, returning to the starting point means the displacement stays \(0\, \text{m}\). Therefore, it decreases from the halfway displacement (\(9\, \text{m}\)) to \(0\, \text{m}\) after completing the circuit.
07

Summarize Full Circuit Findings

After a complete circuit, the distance traveled is \(9\pi\, \text{m}\) and the displacement is \(0\, \text{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance vs Displacement
Distance and displacement may sound similar but are very different in physics. Distance refers to how much ground an object has covered during its motion. It is a scalar quantity, meaning it only has magnitude and no direction.
In the context of our child riding a pony on a circular track, the distance traveled after going halfway around the circle is essentially half of the track's circumference.
Displacement, on the other hand, is a vector quantity. It considers both the magnitude and the direction of the straight line from the starting point to the endpoint of the motion.
When the child travels halfway around the track, the displacement is a straight line across the circle's diameter. But after a full circuit, the child returns to the starting point, making the displacement zero.
This is because the starting and ending points are the same, and no straight line can connect a point to itself.
Circumference Calculation
Each time we want to find how far around the circle the child has gone, we need to calculate the circumference. The circumference of a circle is derived from the formula: \[ C = 2\pi r \]where \(C\) is the circumference, and \(r\) is the radius of the circle.
For the track with a radius of \(4.5 \text{ m}\), substituting into the formula gives us:\[ C = 2 \times \pi \times 4.5 = 9\pi \text{ m} \].
This calculation is crucial because it helps in determining how much distance has been covered, especially when parts of the track are traversed, like halfway or full circuits.
Halfway around leads to half of the circumference, meaning the child travels:\[ \frac{9\pi}{2} \text{ m} \].
Understanding circumference aids in solving real-world problems that involve circular paths, as comprehending how much area is covered in terms of distance is key.
Radius and Diameter
Two essential components of a circle are the radius and diameter. The radius is the distance from the center of the circle to any point on it. It is a critical measurement because it helps in finding other circle parameters, like the circumference or diameter.
The diameter, meanwhile, is twice the radius, representing the longest distance across the circle through its center.
Mathematically, the diameter \(d\) is given by:\[ d = 2r \]For our exercise, with a radius of \(4.5 \text{ m}\), the diameter comes out to:\[ d = 2 \times 4.5 = 9 \text{ m} \].
When discussing motion around a circular path, like the pony's path, recognizing the diameter is handy in displacement calculation.
Remember, displacement halfway through the circle equals this diameter, reflecting the shortest straight-line path from one side directly across to the other.

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Most popular questions from this chapter

On your wedding day you leave for the church 30.0 minutes before the ceremony is to begin, which should be plenty of time since the church is only 10.0 miles away, On the way, how ever, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 15 minutes is only \(5.0 \mathrm{mi} / \mathrm{h}\). What average speed do you need for the rest of the trip to get you to the church on time?

A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of \(0.060 \mathrm{m} / \mathrm{s}\). After \(1.2 \mathrm{minutes}\) the finch tires of the tortoise"s slow pace, and takes flight in the same direction for another 1.2 minutes at \(12 \mathrm{m} / \mathrm{s}\). What was the average speed of the finch for this 2.4 -minute interval?

Jules Verne In his novel From the Earth to the Moon (1866). Jules Verne describes a spaceship that is blasted out of a cannon, called the Columbiad, with a speed of 12,000 yards/s. The Columliad is \(900 \mathrm{ft}\) long. but part of it is packed with powder, so the spaceship accelerates over a distance of only 700 ft. Fstimate the acceleration experienced by the occupants of the spaceship during launch. Give your answer in \(\mathrm{m} / \mathrm{s}^{2}\). (Verne realized that the "travelers would. ... encounter a violent recoil, " but he probably didn't know that people generally lose consciousness if they experience accelerations greater than about \(7 g \sim 70 \mathrm{m} / \mathrm{s}^{2}\) )

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A car is traveling due north at \(18.1 \mathrm{m} / \mathrm{s}\). Find the velocity of the car after \(7.50 \mathrm{s}\) if its acceleration is (a) \(1.30 \mathrm{m} / \mathrm{s}^{2}\) due north or \((\mathrm{b}) 1.15 \mathrm{m} / \mathrm{s}^{2}\) due south.

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