/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 A car is traveling with a speed ... [FREE SOLUTION] | 91Ó°ÊÓ

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A car is traveling with a speed of 20.0 \(\mathrm{m} / \mathrm{s}\) along a straight horizontal road. The wheels have a radius of \(0.300 \mathrm{m}\). If the car speeds up with a linear acceleration of \(1.50 \mathrm{m} / \mathrm{s}^{2}\) for \(8.00 \mathrm{s}\), find the angular displacement of each wheel during this period.

Short Answer

Expert verified
The angular displacement of each wheel is approximately 693.33 radians.

Step by step solution

01

Calculate Final Linear Velocity

First, determine the car's final linear velocity after speeding up for 8 seconds. Use the equation for final velocity in linear motion: \[ v_f = v_i + a imes t \]where \( v_i = 20.0 \ \mathrm{m/s} \) is the initial velocity, \( a = 1.50 \ \mathrm{m/s^2} \) is the acceleration, and \( t = 8.00 \ \mathrm{s} \) is the time. Plug in the values: \[ v_f = 20.0 + 1.50 \times 8.00 = 32.0 \ \mathrm{m/s} \].
02

Calculate Average Linear Velocity

To find the angular displacement, first determine the average linear velocity of the car during acceleration. Use the formula:\[ v_{avg} = \frac{v_i + v_f}{2} \]Substitute the initial velocity \( v_i = 20.0 \ \mathrm{m/s} \) and final velocity \( v_f = 32.0 \ \mathrm{m/s} \):\[ v_{avg} = \frac{20.0 + 32.0}{2} = 26.0 \ \mathrm{m/s} \].
03

Calculate Linear Distance Traveled

Determine the distance traveled by the car using the average velocity:\[ d = v_{avg} \times t \]where \( v_{avg} = 26.0 \ \mathrm{m/s} \) and \( t = 8.00 \ \mathrm{s} \).Plug in the values:\[ d = 26.0 \times 8.00 = 208.0 \ \mathrm{m} \].
04

Find Angular Displacement

Convert the linear distance traveled into angular displacement. Use the relationship:\[ \theta = \frac{d}{r} \]where \( d = 208.0 \ \mathrm{m} \) is the linear distance and \( r = 0.300 \ \mathrm{m} \) is the radius of the wheels.Calculate the angular displacement:\[ \theta = \frac{208.0}{0.300} \approx 693.33 \ \mathrm{rad} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Velocity
Linear velocity is a fundamental concept in physics that describes the rate at which an object covers distance in a straight path. It is a vector quantity, meaning it has both magnitude and direction. In our problem involving a car speeding up, linear velocity plays a crucial role in understanding how quickly the car is moving at a given moment.

To calculate the final linear velocity after a period of acceleration, the formula used is:
  • \( v_f = v_i + a \times t \) - where \( v_f \) is the final velocity, \( v_i \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.
For instance, if a car starts traveling at \( 20.0 \ \mathrm{m/s} \) and accelerates at \( 1.50 \ \mathrm{m/s^2} \) for \( 8.0 \ \mathrm{s} \), its final velocity becomes \( 32.0 \ \mathrm{m/s} \). Understanding linear velocity helps us predict the car's motion and effectively transition to topics like angular displacement.
Linear Acceleration
Linear acceleration is another essential concept involving the rate of change of velocity for an object in linear motion. It indicates how quickly an object speeds up or slows down. Like velocity, acceleration is a vector quantity, meaning it comprises magnitude and direction.

In the scenario of the car speeding up, the given linear acceleration is \(1.50 \ \mathrm{m/s^2}\). This tells us that the car's speed is increasing at this rate each second during the 8-second interval.
  • Acceleration can be calculated if the final velocity and initial velocity are known, using the formula: \[ a = \frac{v_f - v_i}{t} \]
This formula solidifies our understanding of how acceleration affects velocity over time and is pivotal in advanced calculations relevant to angular motion and displacement. By mastering linear acceleration, you gain better insight into how rapidly an object's speed is adjusted in real-world scenarios.
Angular Motion
Angular motion concerns how an object rotates or revolves around a point or axis. It's particularly important when discussing objects like wheels or gears that experience rotational motion, as in our problem with the car's wheels.

Angular motion is represented using concepts like angular velocity, angular acceleration, and angular displacement. In our example, we are primarily interested in angular displacement, which tells us how much the wheel has rotated during the linear acceleration phase.
  • The relation between linear motion and angular motion is depicted by the radius of rotation: \(\theta = \frac{d}{r}\) - Where \(\theta\) is the angular displacement in radians, \(d\) is the linear distance traveled, and \(r\) is the radius of the wheel.
This interplay between linear and angular concepts allows us to understand complex mechanisms like those in vehicles, leading to a holistic comprehension of moving systems in physics.
Physics Problems
Physics problems like the one we explored with the car and its wheels are excellent learning tools for applying theoretical concepts to practical scenarios. These exercises enhance your understanding and allow you to see how abstract ideas function in real-life applications.

In tackling physics problems, remember:
  • Identify known values and what needs to be found.
  • Select appropriate equations and apply them systematically.
  • Perform unit checks to ensure consistency and accuracy.
By breaking down problems into manageable steps, you can solve them methodically and gain confidence in your physics skills. This approach ensures a more profound grasp of concepts like linear velocity, acceleration, and the integration they've shown with angular motion and displacement.

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Most popular questions from this chapter

A rider on a mountain bike is traveling to the left in the figure. Each wheel has an angular velocity of \(+21.7 \mathrm{rad} / \mathrm{s},\) where, as usual, the plus sign indicates that the wheel is rotating in the counterclockwise direction. (a) To pass another cyclist, the rider pumps harder, and the angular velocity of the wheels increases from \(+21.7 \mathrm{to}+28.5 \mathrm{rad} / \mathrm{s}\) in a time of \(3.50 \mathrm{s}\) (b) After passing the cyclist, the rider begins to coast, and the angular velocity of the wheels decreases from \(+28.5 \mathrm{to}+15.3 \mathrm{rad} / \mathrm{s}\) in a time of \(10.7 \mathrm{s}\) Concepts: (i) Is the angular acceleration positive or negative when the rider is passing the cyclist and the angular speed of the wheels is increasing? (ii) Is the angular acceleration positive or negative when the rider is coasting and the angular speed of the wheels is decreasing? Calculations: In both instances, (a) and (b), determine the magnitude and direction of the angular acceleration (assumed constant) of the wheels.

In a large centrifuge used for training pilots and astronauts, a small chamber is fixed at the end of a rigid arm that rotates in a horizontal circle. A trainee riding in the chamber of a centrifuge rotating with a constant angular speed of 2.5 rad/s experiences a centripetal acceleration of 3.2 times the acceleration due to gravity. In a second training exercise, the centrifuge speeds up from rest with a constant angular acceleration. When the centrifuge reaches an angular speed of \(2.5 \mathrm{rad} / \mathrm{s},\) the trainee experiences a total acceleration equal to 4.8 times the acceleration due to gravity. (a) How long is the arm of the centrifuge? (b) What is the angular acceleration of the centrifuge in the second training exercise?

A baseball pitcher throws a baseball horizontally at a linear speed of \(42.5 \mathrm{m} / \mathrm{s}\) (about \(95 \mathrm{mi} / \mathrm{h}\) ). Before being caught, the baseball travels a horizontal distance of \(16.5 \mathrm{m}\) and rotates through an angle of \(49.0 \mathrm{rad}\). The baseball has a radius of \(3.67 \mathrm{cm}\) and is rotating about an axis as it travels, much like the earth does. What is the tangential speed of a point on the "equator" of the baseball?

A string trimmer is a tool for cutting grass and weeds; it utilizes a length of nylon "string" that rotates about an axis perpendicular to one end of the string. The string rotates at an angular speed of 47 rev/s, and its tip has a tangential speed of \(54 \mathrm{m} / \mathrm{s}\). What is the length of the rotating string?

?wo people start at the same place and walk around a circular lake in opposite directions. One walks with an angular speed of \(1.7 \times 10^{-3}\) \(\mathrm{rad} / \mathrm{s},\) while the other has an angular speed of \(3.4 \times 10^{-3} \mathrm{rad} / \mathrm{s} .\) How long will it be before they meet?

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