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Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at \(9.1 \mathrm{rad} / \mathrm{s}\). The wheel has a radius of \(0.45 \mathrm{m} .\) If you ride the bike for \(35 \mathrm{min},\) how far would you have gone if the bike could move?

Short Answer

Expert verified
You would have travelled 8600 meters.

Step by step solution

01

Find the Total Time in Seconds

First, convert the total time spent riding from minutes to seconds. Since there are 60 seconds in a minute, multiply the number of minutes by 60: \[ 35 \, \text{minutes} \times 60 = 2100 \, \text{seconds} \] So, you ride the bike for 2100 seconds.
02

Calculate the Total Angle Rotated

The electronic meter indicates the wheel rotates at \(9.1 \, \text{rad/s}\). To find the total angle in radians that the wheel rotates during the whole time, multiply the angular velocity by the total time:\[ \text{Total angle} = 9.1 \, \text{rad/s} \times 2100 \, \text{s} = 19110 \, \text{rad} \]
03

Determine the Linear Distance Traversed

Use the formula for the length of the arc (distance travelled) for a circle: \( s = r \theta \), where \( r \) is the radius and \( \theta \) is the total angle in radians. Hence:\[ s = 0.45 \, \text{m} \times 19110 \, \text{rad} = 8600 \, \text{m} \] The wheel would have travelled 8600 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radians
When exploring angular motion, radians are a fundamental unit of measure. A radian is an angle measurement based on the radius of a circle. Think of a radian as the angle created when you wrap the radius of a circle along its circumference. Therefore, one complete circle is equivalent to approximately 6.2832 radians (commonly known as \(2\pi\)).
Understanding radians is crucial for calculating rotational movements. Since they are based on the radius, they naturally relate the circle's geometry. Here are some key points about radians:
  • A complete revolution around a circle equals \(2\pi\) radians.
  • Half the circle is \(\pi\) radians.
  • A quarter of the circle, often associated with 90 degrees, is \(\frac{\pi}{2}\) radians.
Using radians, you can easily calculate angular distances like those needed for measuring rotation in circular objects, such as bicycle wheels.
Angular Velocity
Angular velocity helps us understand how quickly something spins around a point. It's expressed in radians per second (\( \text{rad/s} \)).
Imagine how fast the wheel of the exercise bicycle spins. That speed is its angular velocity. In the given exercise, the bicycle wheel has an angular velocity of \(9.1 \text{ rad/s}\). This means every second, the wheel rotates through \(9.1\) radians.
Generally, with angular velocity:
  • Higher angular velocities indicate faster rotations.
  • Low angular velocities are associated with slower spinning objects.
  • Angular velocity connects the speed of the rotation with the radius of the rotating object.
This concept is crucial for solving problems related to rotational speed and understanding how quickly parts of a circle or a wheel are moving along the circular path.
Linear Distance
Linear distance in circular motion refers to the actual path traversed over time. It's different from angular distance, as it measures the straight-line distance a point would cover if it moved linearly. For instance, on the exercise bike, the linear distance covered by the outer edge of the wheel as it rotates depends on both the wheel's angular velocity and its radius.
The linear distance (\(s\)) is given by the formula \(s = r \theta\). Here, \(r\) is the radius, and \(\theta\) is the total angle rotated in radians.
In solving for the linear distance traveled by the bicycle in the exercise:
  • First, you determine the total angle rotated using angular velocity and time.
  • Multiply this angle by the wheel's radius.
  • This product gives the linear distance.
This demonstration highlights linear distances and provides insight into how circles relate angular concepts to real-world travel measurements, enhancing understanding of circular motion principles.

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Most popular questions from this chapter

A baseball pitcher throws a baseball horizontally at a linear speed of \(42.5 \mathrm{m} / \mathrm{s}\) (about \(95 \mathrm{mi} / \mathrm{h}\) ). Before being caught, the baseball travels a horizontal distance of \(16.5 \mathrm{m}\) and rotates through an angle of \(49.0 \mathrm{rad}\). The baseball has a radius of \(3.67 \mathrm{cm}\) and is rotating about an axis as it travels, much like the earth does. What is the tangential speed of a point on the "equator" of the baseball?

A flywheel has a constant angular deceleration of \(2.0 \mathrm{rad} / \mathrm{s}^{2}\). (a) Find the angle through which the flywheel turns as it comes to rest from an angular speed of \(220 \mathrm{rad} / \mathrm{s}\) (b) Find the time for the flywheel to come to rest.

A top is a toy that is made to spin on its pointed end by pulling on a string wrapped around the body of the top. The string has a length of \(64 \mathrm{cm}\) and is wound around the top at a spot where its radius is \(2.0 \mathrm{cm} .\) The thickness of the string is negligible. The top is initially at rest. Someone pulls the free end of the string, thereby unwinding it and giving the top an angular acceleration of \(+12 \mathrm{rad} / \mathrm{s}^{2} .\) What is the final angular velocity of the top when the string is completely unwound?

The wheels of a bicycle have an angular velocity of \(+20.0 \mathrm{rad} / \mathrm{s}\). Then, the brakes are applied. In coming to rest, each wheel makes an angular displacement of +15.92 revolutions. (a) How much time does it take for the bike to come to rest? (b) What is the angular acceleration (in \(\mathrm{rad} / \mathrm{s}^{2}\) ) of each wheel?

The initial angular velocity and the angular acceleration of four rotating objects at the same instant in time are listed in the table that follows. For each of the objects (a), (b), (c), and (d), determine the fi nal angular speed after an elapsed time of 2.0 s. $$ \begin{array}{lcc} & \begin{array}{c} \text { Initial angular } \\ \text { velocity } \omega_{0} \end{array} & \begin{array}{c} \text { Angular } \\ \text { acceleration } \alpha \end{array} \\ \text { (a) } & +12 \mathrm{rad} / \mathrm{s} & +3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \hline \text { (b) } & +12 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \hline \text { (c) } & -12 \mathrm{rad} / \mathrm{s} & +3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \hline \text { (d) } & -12 \mathrm{rad} / \mathrm{s} & -3.0 \mathrm{rad} / \mathrm{s}^{2} \\ \hline \end{array} $$

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