/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 ?wo people start at the same pla... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

?wo people start at the same place and walk around a circular lake in opposite directions. One walks with an angular speed of \(1.7 \times 10^{-3}\) \(\mathrm{rad} / \mathrm{s},\) while the other has an angular speed of \(3.4 \times 10^{-3} \mathrm{rad} / \mathrm{s} .\) How long will it be before they meet?

Short Answer

Expert verified
They will meet after approximately 1232.53 seconds.

Step by step solution

01

Understand the problem

Two people start at the same point on a circular path and walk in opposite directions. We are given their angular speeds and need to determine the time it takes for them to meet.
02

Define key concepts

The key here is their relative angular speed. Since they walk in opposite directions, their relative angular speed is the sum of their angular speeds.
03

Calculate the relative angular speed

Calculate the relative angular speed as \[ \omega_{\text{relative}} = \omega_1 + \omega_2 = 1.7 \times 10^{-3} + 3.4 \times 10^{-3} = 5.1 \times 10^{-3} \, \text{rad/s}. \]
04

Determine the condition for meeting

They meet when the sum of the angles they have each covered equals the circumference of the circle, which in radians is effectively \(2\pi\) given one full loop around the circle.
05

Calculate time for meeting

Using the formula \( \Delta\theta = \omega_{\text{relative}} \cdot t \) and since they need one full cycle to meet, set \(\Delta\theta = 2\pi\) and solve for \(t\):\[ 2\pi = 5.1 \times 10^{-3} \cdot t \] \[ t = \frac{2\pi}{5.1 \times 10^{-3}}. \]
06

Compute the final answer

Calculate the time \( t \):\[ t = \frac{2\pi}{5.1 \times 10^{-3}} \approx 1232.53 \, \text{seconds}. \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Angular Speed
In the context of rotational motion, relative angular speed measures how quickly two objects move with respect to each other around a circular path. If two people walk in opposite directions along a circular lake, their relative angular speed is the sum of their individual angular speeds. This is because moving in opposite directions means their individual angular speeds effectively add up, increasing the rate at which they approach each other.

To find the relative angular speed, use the formula:
  • \[ \omega_{\text{relative}} = \omega_1 + \omega_2 \]
where \(\omega_1\) and \(\omega_2\) are the angular speeds of the two people. Understanding this concept allows us to predict when they will meet given their speed and direction.

In practical problems, calculating relative angular speed is often crucial, particularly for systems with multiple rotating parts or competitive circular races.
Circular Motion
Circular motion refers to the movement of an object along the circumference of a circle. It's a fundamental concept in physics describing how objects move in a circular path either at a constant speed or varying speeds.

Key characteristics of circular motion include:
  • An object traveling in a circular path of radius \( r \) is continuously changing direction.
  • The speed of the object can remain constant, but its velocity is always changing because its direction changes.
  • The motion is defined by its angular speed, which describes how fast an object is traversing the circle.
In our exercise, both individuals are involved in circular motion around the lake. Despite walking at different speeds, both follow the same circular path. Understanding circular motion is essential for solving problems involving objects that revolve or rotate around a fixed point.
Angular Displacement
Angular displacement refers to the change in an object's angular position as it moves along a circular path. It's typically measured in radians, providing a means of describing how far an object rotates around a circle from its starting orientation.

In simpler terms:
  • Angular displacement indicates the angle through which an object has rotated or moved.
  • For a full revolution, the angular displacement is \(2\pi\) radians.
  • It can be calculated using the formula: \( \Delta\theta = \omega \cdot t \), where \( \omega \) is the angular speed and \( t \) is the time.
In our scenario, both walkers will have an angular displacement that sums up to a full circle (or \(2\pi\) radians) when they meet again at the starting point. Thus, calculating when their combined angular displacements equal a full circle allows us to determine the time they will meet.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car is traveling with a speed of 20.0 \(\mathrm{m} / \mathrm{s}\) along a straight horizontal road. The wheels have a radius of \(0.300 \mathrm{m}\). If the car speeds up with a linear acceleration of \(1.50 \mathrm{m} / \mathrm{s}^{2}\) for \(8.00 \mathrm{s}\), find the angular displacement of each wheel during this period.

A motorcyclist is traveling along a road and accelerates for \(4.50 \mathrm{s}\) to pass another cyclist. The angular acceleration of each wheel is \(+6.70 \mathrm{rad} / \mathrm{s}^{2},\) and, just after passing, the angular velocity of each wheel is \(+74.5 \mathrm{rad} / \mathrm{s},\) where the plus signs indicate counterclockwise directions. What is the angular displacement of each wheel during this time?

An automobile tire has a radius of 0.330 m, and its center moves forward with a linear speed of \(v=15.0 \mathrm{m} / \mathrm{s} .\) (a) Determine the angular speed of the wheel. (b) Relative to the axle, what is the tangential speed of a point located \(0.175 \mathrm{m}\) from the axle?

In 9.5 s a fisherman winds \(2.6 \mathrm{m}\) of fishing line onto a reel whose radius is \(3.0 \mathrm{cm}\) (assumed to be constant as an approximation). The line is being reeled in at a constant speed. Determine the angular speed of the reel.

A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 5.00 rev/s while rotating through one-half of a revolution. How much time does this maneuver take?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.